Chapter 17, Problem 17.38P

Interpretation Introduction

Interpretation:

The graph between peak current and voltage for the given reaction has to be sketched.

Concept introduction:

In a reversible reaction, the peak current of first cycle is relative to strength of analyte and square root of sweep rate

$\begin{array}{l}{\text{I}}_{\text{pc}}\text{=}\text{(2}\text{.69}\text{×}{\text{10}}^{\text{8}}{\text{)n}}^{\frac{\text{3}}{\text{2}}}{\text{ACD}}^{\text{0}\text{.5}}{\text{υ}}^{\text{0}\text{.5}}\\ \\ \text{n}\text{is}\text{number}\text{of}\text{electrons}\\ \\ \text{A}\text{is}\text{area}\text{of}{\text{electrode(m}}^{\text{2}}\text{)}\\ \\ \text{C}\text{is}\text{concentration(mol/L)}\\ \\ \text{D}\text{is}\text{diffusion}\text{coefficient}\text{of}\text{electroactive}{\text{species(m}}^{\text{2}}\text{/s)}\\ \\ \text{υ}\text{is}\text{sweep}\text{rate}\text{(V/s)}\end{array}$