Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 17, Problem 17.10P
To determine
Find the settlement of the foundation.
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A circular footing with a 1.5 m diameter is to be
constructed 1.22 m
below the ground surface. The subsoil consists of
a uniform deposit
of dense soil having the following strength
parameters:
Angle of Friction = 250 Nc = 24.1 Nq = 13.1 Ny = 9.1
Cohesion = 48 kN/m2
Unit weight of soil = 20.12 kN/m2
The groundwater table is at a great depth and its
effect can be
ignored.
Determine the following:
a) Ultimate bearing Capacity of the soil
2. A 2m X 2m footing carrying 1400KN load is constructed in
a site with 2.5m thick clay layer under a 2.5m thick sand
layer. If the footing and the ground water table are located
at 1.5m below the surface, calculate the consolidation
settlement of the footing. You may assume the following
soil properties: for sand sat
15.7kN/m°, and for clay eo= 0.65, Cc = 0.25, Cs = 0.06,
O'p = 200kN/m² and sat =19.25KN/m³.
19.25kN/m and t =
%3D
A 1.8 m square, 2 m deep footing supports a service load of 570 kN. It is supported on a clayeysand. A dilatometer test run at the site has returned the following modulus profile.Depth (m) 2 3 4 5 6 7 8 9 10 11 12M (MPa) 7.7 8.8 10.2 14.8 15.4 10.8 11.6 11.6 13.1 13.8 13.4Compute the footing settlement.
Chapter 17 Solutions
Fundamentals of Geotechnical Engineering (MindTap Course List)
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- 3. A 1882KN load is carried by a 2.6m x 2.6m square footing at a depth of 1.4m in a 30 m deep sand layer. Given the following soil properties for soil calculate the total settlement of the footing after 10 years. Where soil properties are: 0 MN/m². (Use Schmertman's method) 15.9 kN/m³, Is=0.5 and Es= 30.0arrow_forwardThe 2.5 m x 3.5m rectangular spread footing placed at a depth of 1.5 m supports a vertical load of 4000 kN and a moment of 400 KN-m, as shown in Figure 2. Determine the factor of safety, against bearing capacity failure, using Meyerhof's effective area method. 4000 kN Clayey Sand y = 17.5 kN/m² c'= 7 kN/m³ $' = 30° 2.5 m 400 kN-m Figure 2 1.5 marrow_forwardFoundation Engineering Homework: The allowable settlement for a continuous footing shown in the figure below is 45 mm. Using the classical method (Terzaghi method), compute its settlement and determine if it satisfies design criterion. Assume the soil beneath the continuous footing is fully saturated. Use the simplified method to compute induced stresses at mid-point of each soil layer. PD=40 kN/m PL=25 kN/m 1.2 m Silty Clay 1: (1.0 m) C/(1+e) = 0.13. C,/(1+ e) = 0.04 á, = 300 kPa Y= 18 kN/m 2: (1.0 m) 3: (1.5 m) Silty Clay C/(1+e) = 0.13, C./(1+e) = 0.04 á =10 kPa Y= 178 kN/m 4: (2.0 m) Clay C/(1+e) = 0.15, C,/(1+ e) 0.05 , = 400 kPa y= 19 kN/m 5: (3.0 m) 3.5 m 2.5 m 0.5 marrow_forward
- Q2. a) A 2 mx 2 m square footing is subjected to an axial load of 600 kN and a bending moment of 180 kNm as appears in Figure 2. The footing is located at 1.2 m deep in a cohesionless soil that has a friction angle of 35° and a saturated unit weight of 18.4 kN/m³. The water table is 2.7 m below the soil surface. Calculate the following, (i) Calculate the eccentricity of the load, (ii) Calculate and draw the soil contact pressure beneath the footing, (iii) Determine the factor of safety of the footing against the bearing capacity (use the general Meyerhof, bearing capacity equation). Assume the soil above water table is saturated. -600 KN /sat = 18.4 kN/m³ 1.2 m c'= 0 kPa, o'= 35° 1.5 m DI. 2 m M = 180 kNm Figure 2arrow_forward3500 kN 3 m x 3 m 0.6 m Ya = 17.5 kN/m³ Sand 0.6 m GWT Sand Ysat = 18.3 kN/m3 1.2 m Y sat = 17.1 kN/m³ C, = 0.06 Clay 1.2 m e, = 1.4 Cc = 0.38 %3Darrow_forwardQuiz-2: For the strip footing shown. Calculate the reduction percentage in the bearing capacity of the soil profile when the groundwater rises to the footing base level. Use Meyerhof's equation P = 723 kN/m 0.5 m Yt = 17.0 kN/m3 B = 3.0 m Pure Sand Ywet 18.0 kN/m3 5.9 m Ø = 36.0° W.T. Ysat = 18.0 kN/m3arrow_forward
- 1. A 3m x 3m square footing is constructed at a depth of 2m in a 26m deep clay layer with following soil properties: ] =16.5kN/m³, Normally Consolidated Clay, e̟= 0.65, Cc = 0.25,s=0.5 and Es= 6.0 MN/m2. If there is a 1000kN structural load on the footing, calculate the consolidation settlement of the footing.arrow_forwardExample: 1 • A square footing 2.5m x 2.5m is shown in the figure below. Determine the magnitude of the safe gross load (using MEYERHOF'S method and factor of safety of 3) that the footing can carry. 1m Bearing Capacity 1m y = 15kN/m³ c=0 = 35⁰ Yat=19kN/m²arrow_forwardExample 24.31. Determine the ultimate net bearing capacity of the circular footing shown in Fig. 24.33. Also, compute the change in ultimate net bearing capacity, if the entire region is flooded, due to which the ground water level reaches ground level. 1.5 m -2 m Clay Cu = 48 kPa $ = 0° y = 1.8 g/cc No = 5.7 3.5 m %3D W.T.arrow_forward
- Check the adequacy of the (3*8.5*1) m footing to resist the applied loads. Use Vesic's equation and FSBearing= 3. 2.25 m Тon V 80 1 m - Y = 14.5 kN/m $ =25°arrow_forwardChapter 5: Settlement of Buildings EXE-3) Determine the total immediate settlement of the rectangular footing shown in figure below after 2 months. 1200 kN G.S. 1.0m 3m x 4m 8000.kN/m², ..Y = 20.kN/m 0.5B =1.5m 0.6 2.0m Clay 0.533 Iz(avg.) Sand 3.0m E = 20000.kN/m? 4.5m 0.133 Rock 2B = 6m 2B – 0.6 Iz redo problem (5.3) but with sand instead of clay as shown in the figure below (Ans:Si(total)=5.75mmarrow_forwardA 2.0 m x 2.0 m square pad footing will be placed in a normally consolidated clay soil to carry acolumn load Q. The depth of the footing is 1.0 m. The soil parameters are: c’= 0, ϕ’= 26º, γ =19kN/m3, and cu = 60 kN/m2. Determine the maximum possible value for Q, considering short-termand long-term stability of the footingarrow_forward
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