(a)
Interpretation:
The overall balanced equation by adding half reactions for the given reaction has to be stated.
Concept Introduction:
(a)
Answer to Problem 15QRT
The overall equation is as follows.
Explanation of Solution
The given reaction is shown below.
The oxidation number of any element in its native form is zero. So, the oxidation number of
In almost all compounds oxidation number of bromine is
Apply charge balance formula in
Therefore, the oxidation number of iron in
In the given reaction, the oxidation number of
The oxidation number of
The half reaction that represents oxidation is as follows.
The half reaction that represents reduction is as follows.
Multiply equation (2) and add to equation (1) as shown below.
The overall equation obtained is as follows.
(b)
Interpretation:
The overall balanced equation by adding half reactions for the given reaction has to be stated.
Concept Introduction:
Refer to part (a).
(b)
Answer to Problem 15QRT
The overall reaction is shown below.
Explanation of Solution
The given reaction is shown below.
The oxidation number of any element in its native form is zero. So, the oxidation number of
In almost all compounds oxidation number of chlorine is
Apply charge balance formula in
Therefore, the oxidation number of aluminium in
In the given reaction, the oxidation number of
The oxidation number of
The half reaction that represents oxidation is as follows.
The half reaction that represents reduction is as follows.
Multiply equation (4) with three and add to equation (3) as shown below.
Multiply the above equation to get final reaction as follows.
Therefore, the overall reaction is shown below.
(c)
Interpretation:
The overall balanced equation by adding half reactions for the given reaction has to be stated.
Concept Introduction:
Refer to part (a).
(c)
Answer to Problem 15QRT
The overall reaction is shown below.
Explanation of Solution
The given reaction is shown below.
The oxidation number of any element in its native form is zero. So, the oxidation number of
In almost all compounds oxidation number of iodine is
Apply charge balance formula in
Therefore, the oxidation number of sulfur in
Apply charge balance formula in
Therefore, the oxidation number of sulfur in
In the given reaction, the oxidation number of sulfur changes from
The oxidation number of
The half reaction that represents oxidation is as follows.
The half reaction that represents reduction is as follows.
The number of oxygen atoms is balanced by adding four molecules of water on product side as shown below.
In acidic medium, the number of hydrogen atoms is balanced by adding
The charge on reactant side is
The balanced half cell reaction represents reduction is shown below.
Multiply equation (5) with eight and add to equation (6) as shown below.
Therefore, the overall reaction is shown below.
(d)
Interpretation:
The overall balanced equation by adding half reactions for the given reaction has to be stated.
Concept Introduction:
Refer to part (a).
(d)
Answer to Problem 15QRT
The overall reaction is as follows.
Explanation of Solution
The given reaction is shown below.
The oxidation number of any element carrying charge is equal to that charge. So, the oxidation number of
In almost all compounds oxidation number of hydrogen is
Apply charge balance formula in
Therefore, the oxidation number of oxygen in
Apply charge balance formula in
Therefore, the oxidation number of oxygen in
In the given reaction, the oxidation number of
The oxidation number of
The half reaction that represents oxidation is as follows.
The reaction for the conversion of
The number of oxygen atoms is balanced by adding one molecule of water on product side as shown below.
In acidic medium, the number of hydrogen atoms is balanced by adding
The charge on reactant side is
The balanced half cell reaction represents reduction is shown below.
Multiply equation (7) with two and add to equation (8) as shown below.
Therefore, the overall reaction is as follows.
(e)
Interpretation:
The overall balanced equation by adding half reactions for the given reaction has to be stated.
Concept Introduction:
Refer to part (a).
(e)
Answer to Problem 15QRT
The, the overall reaction is as follows.
Explanation of Solution
The given reaction is shown below.
The oxidation number of any element carrying charge is equal to that charge. So, the oxidation number of
In almost all compounds oxidation number of hydrogen is
Apply charge balance formula in
Therefore, the oxidation number of nitrogen in
Apply charge balance formula in
Therefore, the oxidation number of nitrogen in
Apply charge balance formula in
Therefore, the oxidation number of nitrogen in
Apply charge balance formula in
Therefore, the oxidation number of iron in
In the given reaction, the oxidation number of
In the given reaction, the oxidation number of
The oxidation number of
The reaction for the oxidation of
The number of oxygen atoms is balanced by adding four molecules of water on reactant side as shown below.
In acidic medium, the number of hydrogen atoms is balanced by adding
The charge on reactant side is zero and the charge on product side is
The half cell reaction for oxidation of
The reaction for the reduction of
The number of oxygen atoms is balanced by adding two molecules of water on product side as shown below.
In acidic medium, the number of hydrogen atoms is balanced by adding
The charge on reactant side is
The half cell reaction for reduction of
Multiply equation (10) with three and add to equation (10) as shown below.
Therefore, the overall reaction is as follows.
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Chapter 17 Solutions
Chemistry: The Molecular Science
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- . In which direction do electrons flow in a galvanic cell, from anode to cathode or vice versa?arrow_forwardGive the notation for a voltaic cell whose overall cell reaction is Mg(s)+2Ag+(aq)Mg2+(aq)+2Ag(s) What are the half-cell reactions? Label them as anode or cathode reactions. What is the standard cell potential of this cell?arrow_forwardHalf-cells were made from a nickel rod dipping in a nickel sulfate solution and a silver rod dipping in a silver nitrate solution. The half-reactions in a voltaic cell using these half-cells were Ag+(aq)+eAg(s)Ni(s)Ni2+(aq)+2e Sketch the cell and label the anode and cathode, showing the corresponding electrode reactions. Give the direction of electron flow and the movement of cations.arrow_forward
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