(a) Answer The value of x is 3. Explanation Given information : 2 x = 6 Calculation: Divide both sides of the given equation 2 x = 6 by 2 . 2 x 2 = 6 3 ∴ x = 3 (b) To determine To find: The solution of the equation. Answer The solution of the equation is infinite. Explanation Given information : 0 × 2 x = 0 × 6 Calculation: Since 0 × 2 x = 0 × 6 any number plugged in for x will give the same value zero Therefore, the solution of the equation is ∞ . (c) To determine To find: Whether you get an equivalent equation if an equation multiplies by zero. Answer Yes, it gives an equivalent equation. Explanation Given information : An equation is multiply by zero. Calculation: If we multiply zero on both sides of the equation, it give zero every time. Therefore, the result will be the same for an equation. This means it will be equivalent equation. (d) To determine To explain: The reason why each side of an equation is not possible to divide by zero. Answer Yes, it gives an equivalent equation. Explanation Given information : Each side of an equation is divided by zero. The zero in the dominator gives the undefined result. Therefore, it is not possible to divide an equation by zero.

Algebra and Trigonometry: Structure and Method, Book 2

2000th Edition

ISBN: 9780395977255

Author: MCDOUGAL LITTEL

Publisher: McDougal Littell

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Equations and Inequations

Equations and inequalities describe the relationship between two mathematical expressions.

Linear Functions

A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.

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Question

Chapter 1.7, Problem 12OE

(a)

To determine

To find: The value of x .

(a)

Expert Solution

Answer to Problem 12OE

The value of x is 3.

Explanation of Solution

Given information: 2x=6

Calculation:

Divide both sides of the given equation 2x=6 by 2 .

2x2=63∴x=3

(b)

To determine

To find: The solution of the equation.

(b)

Expert Solution

Answer to Problem 12OE

The solution of the equation is infinite.

Explanation of Solution

Given information: 0×2x=0×6

Calculation:

Since 0×2x=0×6 any number plugged in for x will give the same value zero

Therefore, the solution of the equation is ∞ .

(c)

To determine

To find: Whether you get an equivalent equation if an equation multiplies by zero.

(c)

Expert Solution

Answer to Problem 12OE

Yes, it gives an equivalent equation.

Explanation of Solution

Given information: An equation is multiply by zero.

Calculation: If we multiply zero on both sides of the equation, it give zero every time. Therefore, the result will be the same for an equation. This means it will be equivalent equation.

(d)

To determine

To explain: The reason why each side of an equation is not possible to divide by zero.

(d)

Expert Solution

Answer to Problem 12OE

Yes, it gives an equivalent equation.

Explanation of Solution

Given information: Each side of an equation is divided by zero.

The zero in the dominator gives the undefined result. Therefore, it is not possible to divide an equation by zero.

Chapter 1.7, Problem 11OE

Chapter 1.7, Problem 1WE

Chapter 1 Solutions

Algebra and Trigonometry: Structure and Method, Book 2

Ch. 1.1 - Prob. 1OE Ch. 1.1 - Prob. 2OE Ch. 1.1 - Prob. 3OE Ch. 1.1 - Prob. 4OE Ch. 1.1 - Prob. 5OE Ch. 1.1 - Prob. 6OE Ch. 1.1 - Prob. 7OE Ch. 1.1 - Prob. 8OE Ch. 1.1 - Prob. 9OE Ch. 1.1 - Prob. 10OE

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Prob. 36WE Ch. 1.4 - Prob. 37WE Ch. 1.4 - Prob. 38WE Ch. 1.4 - Prob. 39WE Ch. 1.4 - Prob. 40WE Ch. 1.4 - Prob. 41WE Ch. 1.4 - Prob. 42WE Ch. 1.4 - Prob. 43WE Ch. 1.4 - Prob. 44WE Ch. 1.4 - Prob. 45WE Ch. 1.4 - Prob. 46WE Ch. 1.4 - Prob. 47WE Ch. 1.4 - Prob. 48WE Ch. 1.4 - Prob. 49WE Ch. 1.4 - Prob. 50WE Ch. 1.4 - Prob. 51WE Ch. 1.4 - Prob. 52WE Ch. 1.4 - Prob. 53WE Ch. 1.4 - Prob. 54WE Ch. 1.4 - Prob. 55WE Ch. 1.4 - Prob. 56WE Ch. 1.4 - Prob. 1E Ch. 1.4 - Prob. 2E Ch. 1.4 - Prob. 3E Ch. 1.4 - Prob. 4E Ch. 1.4 - Prob. 5E Ch. 1.4 - Prob. 6E Ch. 1.4 - Prob. 7E Ch. 1.5 - Prob. 1OE Ch. 1.5 - Prob. 2OE Ch. 1.5 - Prob. 3OE Ch. 1.5 - Prob. 4OE Ch. 1.5 - Prob. 5OE Ch. 1.5 - Prob. 6OE Ch. 1.5 - Prob. 7OE Ch. 1.5 - Prob. 8OE Ch. 1.5 - Prob. 9OE Ch. 1.5 - Prob. 10OE Ch. 1.5 - Prob. 11OE Ch. 1.5 - Prob. 12OE Ch. 1.5 - Prob. 13OE Ch. 1.5 - Prob. 14OE Ch. 1.5 - Prob. 15OE Ch. 1.5 - Prob. 16OE Ch. 1.5 - Prob. 17OE Ch. 1.5 - Prob. 18OE Ch. 1.5 - Prob. 19OE Ch. 1.5 - Prob. 20OE Ch. 1.5 - Prob. 1WE Ch. 1.5 - 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Prob. 2CE Ch. 1.5 - Prob. 3CE Ch. 1.5 - Prob. 4CE Ch. 1.6 - Prob. 1OE Ch. 1.6 - Prob. 2OE Ch. 1.6 - Prob. 3OE Ch. 1.6 - Prob. 4OE Ch. 1.6 - Prob. 5OE Ch. 1.6 - Prob. 6OE Ch. 1.6 - Prob. 7OE Ch. 1.6 - Prob. 8OE Ch. 1.6 - Prob. 9OE Ch. 1.6 - Prob. 10OE Ch. 1.6 - Prob. 11OE Ch. 1.6 - Prob. 12OE Ch. 1.6 - Prob. 13OE Ch. 1.6 - Prob. 14OE Ch. 1.6 - Prob. 15OE Ch. 1.6 - Prob. 16OE Ch. 1.6 - Prob. 17OE Ch. 1.6 - Prob. 18OE Ch. 1.6 - Prob. 19OE Ch. 1.6 - Prob. 1WE Ch. 1.6 - Prob. 2WE Ch. 1.6 - Prob. 3WE Ch. 1.6 - Prob. 4WE Ch. 1.6 - Prob. 5WE Ch. 1.6 - Prob. 6WE Ch. 1.6 - Prob. 7WE Ch. 1.6 - Prob. 8WE Ch. 1.6 - Prob. 9WE Ch. 1.6 - Prob. 10WE Ch. 1.6 - Prob. 11WE Ch. 1.6 - Prob. 12WE Ch. 1.6 - Prob. 13WE Ch. 1.6 - Prob. 14WE Ch. 1.6 - Prob. 15WE Ch. 1.6 - Prob. 16WE Ch. 1.6 - Prob. 17WE Ch. 1.6 - Prob. 18WE Ch. 1.6 - Prob. 19WE Ch. 1.6 - Prob. 20WE Ch. 1.6 - Prob. 21WE Ch. 1.6 - Prob. 22WE Ch. 1.6 - Prob. 23WE Ch. 1.6 - Prob. 24WE Ch. 1.6 - Prob. 25WE Ch. 1.6 - Prob. 26WE Ch. 1.6 - Prob. 27WE Ch. 1.6 - 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