Algebra and Trigonometry: Structure and Method, Book 2

2000th Edition

ISBN: 9780395977255

Author: MCDOUGAL LITTEL

Publisher: McDougal Littell

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Question

Chapter 1.2, Problem 49WE

To determine

To explain:

The grouping symbols to be inserted in given expression to make it a true equation.

Expert Solution & Answer

Answer to Problem 49WE

The true statement after grouping is: [(32−2)2−4⋅(3+3)]=25 .

Explanation of Solution

Given information:

32−22−4⋅3+3=25

For grouping the given expression, use the following calculation to make it true equation:

32−22−4⋅3+3=25

After grouping,

[(32−2)2−4⋅(3+3)]=25[(9−2)2−4⋅(6)]=25[(7)2−4⋅(6)]=25[49−24]=2525=25

From the above calculation, L.H.S=R.H.S .

Therefore, the true statement after grouping is as below:

[(32−2)2−4⋅(3+3)]=25

Chapter 1.2, Problem 48WE

Chapter 1.2, Problem 50WE

Chapter 1 Solutions

Algebra and Trigonometry: Structure and Method, Book 2

Ch. 1.1 - Prob. 1OE Ch. 1.1 - Prob. 2OE Ch. 1.1 - Prob. 3OE Ch. 1.1 - Prob. 4OE Ch. 1.1 - Prob. 5OE Ch. 1.1 - Prob. 6OE Ch. 1.1 - Prob. 7OE Ch. 1.1 - Prob. 8OE Ch. 1.1 - Prob. 9OE Ch. 1.1 - Prob. 10OE

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The grouping symbols to be inserted in given expression to make it a true equation.

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To explain: The grouping symbols to be inserted in given expression to make it a true equation.

Answer to Problem 49WE

Explanation of Solution

Chapter 1 Solutions

Additional Math Textbook Solutions

To explain:

The grouping symbols to be inserted in given expression to make it a true equation.