Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN: 9780547587776

Author: HOLT MCDOUGAL

Publisher: HOLT MCDOUGAL

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Question

Chapter 1.6, Problem 50E

To determine

To evaluate : The expression 3−(−x)+8−10 for the given value of x=18

Expert Solution & Answer

Answer to Problem 50E

The evaluated value is 19

Explanation of Solution

Calculation:

the expression is evaluated as,

3−(−x)+8−10

Substitute the value of x,

3−(−x)+8−10=3−(−18)+8−10 [ one elementary bracket operation]

=3+18+8−10 [bracket removed and negative signs multiplied]

=29−10

Subtract the 10 from 29

That is,

=19

Therefore, the answer is 19

Chapter 1.6, Problem 49E

Chapter 1.6, Problem 51E

Chapter 1 Solutions

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Ch. 1.1 - Prob. 1C Ch. 1.1 - Prob. 2C Ch. 1.1 - Prob. 3C Ch. 1.1 - Prob. 4C Ch. 1.1 - Prob. 1E Ch. 1.1 - Prob. 2E Ch. 1.1 - Prob. 3E Ch. 1.1 - Prob. 4E Ch. 1.1 - Prob. 5E Ch. 1.1 - Prob. 6E

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The expression 3 − ( − x ) + 8 − 10 for the given value of x = 18

Concept explainers

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To evaluate : The expression 3−(−x)+8−10 for the given value of x=18

Answer to Problem 50E

Explanation of Solution

Chapter 1 Solutions

Additional Math Textbook Solutions