Chapter 1.3, Problem 27E

To determine

To calculate : the value of the expression,

$y+{\left(z-1\right)}^2$ when $y=4and\text{ z}=5$

Answer to Problem 27E

The value of the expression,

$y+{\left(z-1\right)}^2=20$ when $y=4and\text{ z}=5$

Explanation of Solution

Given information :

Consider, the expression,

$y+{\left(z-1\right)}^2$ when $y=4and\text{ z}=5$

  $$

Calculation :

To evaluate the value of the expression, substitute, $y=4and\text{ z}=5$

Therefore,

The value of the expression is obtained as:

  $\begin{array}{l}y+{\left(z-1\right)}^2=4+{\left(5-1\right)}^2\\ y+{\left(z-1\right)}^2=4+{\left(4\right)}^2\left[\text{subtract within parentheses}\right]\\ y+{\left(z-1\right)}^2=4+16\left[\text{evaluate power}\right]\\ y+{\left(z-1\right)}^2=20\left[\text{add}\right]\end{array}$

Hence,

The value of the expression $y+{\left(z-1\right)}^2=20$ when $y=4and\text{ z}=5$