The mechanism for the formation of β − lactose from α − galactose and β − D − glucose in dilute HCl has to be drawn. Concept Introduction: The general steps followed by the acid catalyzed reaction are as follows: First step is the protonation of alcohol group placed at first position of β − D − glucose . The second step is the removal of OH 2 group by the attack of lone pair of oxygen of alcohol group placed at fourth position of α − galactose . The third step is the deprotonation.

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Answer 1

Question

Chapter 16, Problem 36P

Interpretation Introduction

Interpretation:

The mechanism for the formation of β−lactose from α−galactose and β−D−glucose in dilute HCl has to be drawn.

Concept Introduction:

The general steps followed by the acid catalyzed reaction are as follows:

First step is the protonation of alcohol group placed at first position of β−D−glucose.

The second step is the removal of OH2 group by the attack of lone pair of oxygen of alcohol group placed at fourth position of α−galactose.

The third step is the deprotonation.

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Answer 2

Question

Chapter 16, Problem 36P

Interpretation Introduction

Interpretation:

The mechanism for the formation of β−lactose from α−galactose and β−D−glucose in dilute HCl has to be drawn.

Concept Introduction:

The general steps followed by the acid catalyzed reaction are as follows:

First step is the protonation of alcohol group placed at first position of β−D−glucose.

The second step is the removal of OH2 group by the attack of lone pair of oxygen of alcohol group placed at fourth position of α−galactose.

The third step is the deprotonation.

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Answer 3

Question

Chapter 16, Problem 36P

Interpretation Introduction

Interpretation:

The mechanism for the formation of β−lactose from α−galactose and β−D−glucose in dilute HCl has to be drawn.

Concept Introduction:

The general steps followed by the acid catalyzed reaction are as follows:

First step is the protonation of alcohol group placed at first position of β−D−glucose.

The second step is the removal of OH2 group by the attack of lone pair of oxygen of alcohol group placed at fourth position of α−galactose.

The third step is the deprotonation.

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Answer 4

Question

Chapter 16, Problem 36P

Interpretation Introduction

Interpretation:

The mechanism for the formation of β−lactose from α−galactose and β−D−glucose in dilute HCl has to be drawn.

Concept Introduction:

The general steps followed by the acid catalyzed reaction are as follows:

First step is the protonation of alcohol group placed at first position of β−D−glucose.

The second step is the removal of OH2 group by the attack of lone pair of oxygen of alcohol group placed at fourth position of α−galactose.

The third step is the deprotonation.

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Answer 5

Chapter 16, Problem 36P

Interpretation Introduction

Interpretation:

The mechanism for the formation of β−lactose from α−galactose and β−D−glucose in dilute HCl has to be drawn.

Concept Introduction:

The general steps followed by the acid catalyzed reaction are as follows:

First step is the protonation of alcohol group placed at first position of β−D−glucose.

The second step is the removal of OH2 group by the attack of lone pair of oxygen of alcohol group placed at fourth position of α−galactose.

The third step is the deprotonation.

Answer 6

Chapter 16, Problem 36P

Interpretation Introduction

Interpretation:

The mechanism for the formation of β−lactose from α−galactose and β−D−glucose in dilute HCl has to be drawn.

Concept Introduction:

The general steps followed by the acid catalyzed reaction are as follows:

First step is the protonation of alcohol group placed at first position of β−D−glucose.

The second step is the removal of OH2 group by the attack of lone pair of oxygen of alcohol group placed at fourth position of α−galactose.

The third step is the deprotonation.

Answer 7

Chapter 16, Problem 36P

Interpretation Introduction

Interpretation:

The mechanism for the formation of β−lactose from α−galactose and β−D−glucose in dilute HCl has to be drawn.

Concept Introduction:

The general steps followed by the acid catalyzed reaction are as follows:

First step is the protonation of alcohol group placed at first position of β−D−glucose.

The second step is the removal of OH2 group by the attack of lone pair of oxygen of alcohol group placed at fourth position of α−galactose.

The third step is the deprotonation.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 16.1 - Prob. 1P Ch. 16.2 - Prob. 2P Ch. 16.3 - Prob. 3P Ch. 16.3 - Prob. 4P Ch. 16.4 - Prob. 5P Ch. 16.4 - Prob. 6P Ch. 16.5 - Prob. 7P Ch. 16.5 - Prob. 8P Ch. 16.6 - Prob. 10P Ch. 16.8 - Prob. 12P

Solution Summary: The author explains the steps followed by the acid catalyzed reaction: protonation, removal, and deprotonation.

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Chapter 16 Solutions