Find the equation of the regression line.

Question

Want to see more full solutions like this?

Answer 1

Question

Chapter 16, Problem 19CAP

(a)

To determine

Find the equation of the regression line.

(a)

Expert Solution

Answer to Problem 19CAP

The equation of the regression line is, $Y^=0.36X+13.17$ .

Explanation of Solution

Calculation:

The information given that is the case files to record the age of five criminals and the age of the victim in those cases with the factors age of a criminal (X) predicts the age of the victim (Y) for nonviolent crimes.

The procedure of straight line by using the method of least square is shown below:

Compute preliminary calculations.
Calculate the slope $(b)$ .
Calculate the y-intercept $(a)$ .

The formula for slope is,

$slope(b)=SSXYSSX$

Where,

$SSXY=∑(X−MX)(Y−MY)$

$SSX=∑(X−MX)2$

In the formulas, $MX$ denotes the mean of factor X, $MY$ denotes the mean of factor Y.

The formula for y-intercept is,

$a=MY−bMX$

The regression equation is, $Y^=bX+a$ .

The value of $SSX$ :

The value of mean for X is,

$MX=32+24+28+17+125=1135=22.6$

X	Y	$(X−MX)$	$(X−MX)2$
32	24	$(32−22.6)=9.4$	88.36
24	20	$(24−22.6)=1.4$	1.96
28	25	$(28−22.6)=5.4$	29.16
17	22	$(17−22.6)=−5.6$	31.36
12	16	$(12−22.6)=−10.6$	112.36
			$∑(X−MX)2=263.2$

Table 1

The value of $SSX$ is 263.2.

The value of $SSXY$ :

The value of mean for Y is,

$MY=24+20+25+22+165=1075=21.4$

X	Y	$(X−MX)$	$(X−MY)$	$(X−MX)(X−MY)$
32	24	$(32−22.6)=9.4$	$(24−21.4)=2.6$	24.44
24	20	$(24−22.6)=1.4$	$(20−21.4)=−1.4$	–1.96
28	25	$(28−22.6)=5.4$	$(25−21.4)=3.6$	19.44
17	22	$(17−22.6)=−5.6$	$(22−21.4)=0.6$	–3.36
12	16	$(12−22.6)=−10.6$	$(16−21.4)=−5.4$	57.24
				$∑(X−MX)(X−MY)=95.8$

Table 2

The value of $SSXY$ is 95.8.

Slope:

Substitute, $SSX=263.2$ and $SSXY=95.8$ in slope formula

$slope(b)=95.8263.2=0.364$

Hence, the value of slope is 0.364.

Substitute, $MY=21.4, MX=22.6, b=0.364$ in y-intercept formula.

$a=MY−bMX=21.4−(0.364)22.6=21.4−8.2264=13.174$

Hence, the value of y-intercept is 13.174.

Substitute, $a=13.174, b=0.364$ in regression equation formula.

$Y^=(0.364)X+13.174=0.36X+13.17$

The equation of the regression line is, $Y^=0.36X+13.17$ .

(b)

To determine

Find the predicted age of a victim of a nonviolent crime when the criminal is 20 years old.

(b)

Expert Solution

Answer to Problem 19CAP

The predicted age of a victim of a nonviolent crime when the criminal is 20 years old is 20.37 years old.

Explanation of Solution

Calculation:

The given information is that the criminal is 20 years old.

The equation of the regression line is $Y^=0.36X+13.17$ .

Substitute, $X=20$ in regression line.

$Y^=0.36(20)+13.174=7.2+13.17=20.37$

Hence, the predicted age of a victim of a nonviolent crime when the criminal is 20 years old is 20.37 years old.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

Please solve 6.31 by using the method of sections im stuck and need explanation

a) When two variables are correlated, can the researcher be sure that one variable causes the other? If YES , why? If NO , why? b) What is meant by the statement that two variables are related? Discuss.

SCIE 211 Lab 3: Graphing and DataWorksheetPre-lab Questions:1. When should you use each of the following types of graphs? Fill answers in the table below.Type of Graph Used to showLine graphScatter plotBar graphHistogramPie Chart2. Several ways in which we can be fooled or misled by a graph were identified in the Lab 3Introduction. Find two examples of misleading graphs on the Internet and paste them below. Besure to identify why each graph is misleading. Data Charts:Circumference vs. Diameter for circular objectsDiameter Can 1 (cm) Can 2 (cm) Can 3 (cm)Trial 1Trial 2Trial 3MeanCircumference Can 1 (cm) Can 2 (cm) Can 3 (cm)Trial 1Trial 2Trial 3MeanScatter Plot Graph – Circumference Vs. DiameterIdentify 2 points of the Trendline.Y1 = ________ Y2 = _________X1 = ________ X2 = _________Calculate the Slope of the Trendline = Post-lab Questions:1. Answer the questions below. You will need to use the following equation to answer…

Answer 2

Question

Chapter 16, Problem 19CAP

(a)

To determine

Find the equation of the regression line.

(a)

Expert Solution

Answer to Problem 19CAP

The equation of the regression line is, $Y^=0.36X+13.17$ .

Explanation of Solution

Calculation:

The information given that is the case files to record the age of five criminals and the age of the victim in those cases with the factors age of a criminal (X) predicts the age of the victim (Y) for nonviolent crimes.

The procedure of straight line by using the method of least square is shown below:

Compute preliminary calculations.
Calculate the slope $(b)$ .
Calculate the y-intercept $(a)$ .

The formula for slope is,

$slope(b)=SSXYSSX$

Where,

$SSXY=∑(X−MX)(Y−MY)$

$SSX=∑(X−MX)2$

In the formulas, $MX$ denotes the mean of factor X, $MY$ denotes the mean of factor Y.

The formula for y-intercept is,

$a=MY−bMX$

The regression equation is, $Y^=bX+a$ .

The value of $SSX$ :

The value of mean for X is,

$MX=32+24+28+17+125=1135=22.6$

X	Y	$(X−MX)$	$(X−MX)2$
32	24	$(32−22.6)=9.4$	88.36
24	20	$(24−22.6)=1.4$	1.96
28	25	$(28−22.6)=5.4$	29.16
17	22	$(17−22.6)=−5.6$	31.36
12	16	$(12−22.6)=−10.6$	112.36
			$∑(X−MX)2=263.2$

Table 1

The value of $SSX$ is 263.2.

The value of $SSXY$ :

The value of mean for Y is,

$MY=24+20+25+22+165=1075=21.4$

X	Y	$(X−MX)$	$(X−MY)$	$(X−MX)(X−MY)$
32	24	$(32−22.6)=9.4$	$(24−21.4)=2.6$	24.44
24	20	$(24−22.6)=1.4$	$(20−21.4)=−1.4$	–1.96
28	25	$(28−22.6)=5.4$	$(25−21.4)=3.6$	19.44
17	22	$(17−22.6)=−5.6$	$(22−21.4)=0.6$	–3.36
12	16	$(12−22.6)=−10.6$	$(16−21.4)=−5.4$	57.24
				$∑(X−MX)(X−MY)=95.8$

Table 2

The value of $SSXY$ is 95.8.

Slope:

Substitute, $SSX=263.2$ and $SSXY=95.8$ in slope formula

$slope(b)=95.8263.2=0.364$

Hence, the value of slope is 0.364.

Substitute, $MY=21.4, MX=22.6, b=0.364$ in y-intercept formula.

$a=MY−bMX=21.4−(0.364)22.6=21.4−8.2264=13.174$

Hence, the value of y-intercept is 13.174.

Substitute, $a=13.174, b=0.364$ in regression equation formula.

$Y^=(0.364)X+13.174=0.36X+13.17$

The equation of the regression line is, $Y^=0.36X+13.17$ .

(b)

To determine

Find the predicted age of a victim of a nonviolent crime when the criminal is 20 years old.

(b)

Expert Solution

Answer to Problem 19CAP

The predicted age of a victim of a nonviolent crime when the criminal is 20 years old is 20.37 years old.

Explanation of Solution

Calculation:

The given information is that the criminal is 20 years old.

The equation of the regression line is $Y^=0.36X+13.17$ .

Substitute, $X=20$ in regression line.

$Y^=0.36(20)+13.174=7.2+13.17=20.37$

Hence, the predicted age of a victim of a nonviolent crime when the criminal is 20 years old is 20.37 years old.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 16, Problem 19CAP

(a)

To determine

Find the equation of the regression line.

(a)

Expert Solution

Answer to Problem 19CAP

The equation of the regression line is, $Y^=0.36X+13.17$ .

Explanation of Solution

Calculation:

The information given that is the case files to record the age of five criminals and the age of the victim in those cases with the factors age of a criminal (X) predicts the age of the victim (Y) for nonviolent crimes.

The procedure of straight line by using the method of least square is shown below:

Compute preliminary calculations.
Calculate the slope $(b)$ .
Calculate the y-intercept $(a)$ .

The formula for slope is,

$slope(b)=SSXYSSX$

Where,

$SSXY=∑(X−MX)(Y−MY)$

$SSX=∑(X−MX)2$

In the formulas, $MX$ denotes the mean of factor X, $MY$ denotes the mean of factor Y.

The formula for y-intercept is,

$a=MY−bMX$

The regression equation is, $Y^=bX+a$ .

The value of $SSX$ :

The value of mean for X is,

$MX=32+24+28+17+125=1135=22.6$

X	Y	$(X−MX)$	$(X−MX)2$
32	24	$(32−22.6)=9.4$	88.36
24	20	$(24−22.6)=1.4$	1.96
28	25	$(28−22.6)=5.4$	29.16
17	22	$(17−22.6)=−5.6$	31.36
12	16	$(12−22.6)=−10.6$	112.36
			$∑(X−MX)2=263.2$

Table 1

The value of $SSX$ is 263.2.

The value of $SSXY$ :

The value of mean for Y is,

$MY=24+20+25+22+165=1075=21.4$

X	Y	$(X−MX)$	$(X−MY)$	$(X−MX)(X−MY)$
32	24	$(32−22.6)=9.4$	$(24−21.4)=2.6$	24.44
24	20	$(24−22.6)=1.4$	$(20−21.4)=−1.4$	–1.96
28	25	$(28−22.6)=5.4$	$(25−21.4)=3.6$	19.44
17	22	$(17−22.6)=−5.6$	$(22−21.4)=0.6$	–3.36
12	16	$(12−22.6)=−10.6$	$(16−21.4)=−5.4$	57.24
				$∑(X−MX)(X−MY)=95.8$

Table 2

The value of $SSXY$ is 95.8.

Slope:

Substitute, $SSX=263.2$ and $SSXY=95.8$ in slope formula

$slope(b)=95.8263.2=0.364$

Hence, the value of slope is 0.364.

Substitute, $MY=21.4, MX=22.6, b=0.364$ in y-intercept formula.

$a=MY−bMX=21.4−(0.364)22.6=21.4−8.2264=13.174$

Hence, the value of y-intercept is 13.174.

Substitute, $a=13.174, b=0.364$ in regression equation formula.

$Y^=(0.364)X+13.174=0.36X+13.17$

The equation of the regression line is, $Y^=0.36X+13.17$ .

(b)

To determine

Find the predicted age of a victim of a nonviolent crime when the criminal is 20 years old.

(b)

Expert Solution

Answer to Problem 19CAP

The predicted age of a victim of a nonviolent crime when the criminal is 20 years old is 20.37 years old.

Explanation of Solution

Calculation:

The given information is that the criminal is 20 years old.

The equation of the regression line is $Y^=0.36X+13.17$ .

Substitute, $X=20$ in regression line.

$Y^=0.36(20)+13.174=7.2+13.17=20.37$

Hence, the predicted age of a victim of a nonviolent crime when the criminal is 20 years old is 20.37 years old.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 16, Problem 19CAP

(a)

To determine

Find the equation of the regression line.

(a)

Expert Solution

Answer to Problem 19CAP

The equation of the regression line is, $Y^=0.36X+13.17$ .

Explanation of Solution

Calculation:

The information given that is the case files to record the age of five criminals and the age of the victim in those cases with the factors age of a criminal (X) predicts the age of the victim (Y) for nonviolent crimes.

The procedure of straight line by using the method of least square is shown below:

Compute preliminary calculations.
Calculate the slope $(b)$ .
Calculate the y-intercept $(a)$ .

The formula for slope is,

$slope(b)=SSXYSSX$

Where,

$SSXY=∑(X−MX)(Y−MY)$

$SSX=∑(X−MX)2$

In the formulas, $MX$ denotes the mean of factor X, $MY$ denotes the mean of factor Y.

The formula for y-intercept is,

$a=MY−bMX$

The regression equation is, $Y^=bX+a$ .

The value of $SSX$ :

The value of mean for X is,

$MX=32+24+28+17+125=1135=22.6$

X	Y	$(X−MX)$	$(X−MX)2$
32	24	$(32−22.6)=9.4$	88.36
24	20	$(24−22.6)=1.4$	1.96
28	25	$(28−22.6)=5.4$	29.16
17	22	$(17−22.6)=−5.6$	31.36
12	16	$(12−22.6)=−10.6$	112.36
			$∑(X−MX)2=263.2$

Table 1

The value of $SSX$ is 263.2.

The value of $SSXY$ :

The value of mean for Y is,

$MY=24+20+25+22+165=1075=21.4$

X	Y	$(X−MX)$	$(X−MY)$	$(X−MX)(X−MY)$
32	24	$(32−22.6)=9.4$	$(24−21.4)=2.6$	24.44
24	20	$(24−22.6)=1.4$	$(20−21.4)=−1.4$	–1.96
28	25	$(28−22.6)=5.4$	$(25−21.4)=3.6$	19.44
17	22	$(17−22.6)=−5.6$	$(22−21.4)=0.6$	–3.36
12	16	$(12−22.6)=−10.6$	$(16−21.4)=−5.4$	57.24
				$∑(X−MX)(X−MY)=95.8$

Table 2

The value of $SSXY$ is 95.8.

Slope:

Substitute, $SSX=263.2$ and $SSXY=95.8$ in slope formula

$slope(b)=95.8263.2=0.364$

Hence, the value of slope is 0.364.

Substitute, $MY=21.4, MX=22.6, b=0.364$ in y-intercept formula.

$a=MY−bMX=21.4−(0.364)22.6=21.4−8.2264=13.174$

Hence, the value of y-intercept is 13.174.

Substitute, $a=13.174, b=0.364$ in regression equation formula.

$Y^=(0.364)X+13.174=0.36X+13.17$

The equation of the regression line is, $Y^=0.36X+13.17$ .

(b)

To determine

Find the predicted age of a victim of a nonviolent crime when the criminal is 20 years old.

(b)

Expert Solution

Answer to Problem 19CAP

The predicted age of a victim of a nonviolent crime when the criminal is 20 years old is 20.37 years old.

Explanation of Solution

Calculation:

The given information is that the criminal is 20 years old.

The equation of the regression line is $Y^=0.36X+13.17$ .

Substitute, $X=20$ in regression line.

$Y^=0.36(20)+13.174=7.2+13.17=20.37$

Hence, the predicted age of a victim of a nonviolent crime when the criminal is 20 years old is 20.37 years old.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 16, Problem 19CAP

(a)

To determine

Find the equation of the regression line.

(a)

Expert Solution

Answer to Problem 19CAP

The equation of the regression line is, $Y^=0.36X+13.17$ .

Explanation of Solution

Calculation:

The information given that is the case files to record the age of five criminals and the age of the victim in those cases with the factors age of a criminal (X) predicts the age of the victim (Y) for nonviolent crimes.

The procedure of straight line by using the method of least square is shown below:

Compute preliminary calculations.
Calculate the slope $(b)$ .
Calculate the y-intercept $(a)$ .

The formula for slope is,

$slope(b)=SSXYSSX$

Where,

$SSXY=∑(X−MX)(Y−MY)$

$SSX=∑(X−MX)2$

In the formulas, $MX$ denotes the mean of factor X, $MY$ denotes the mean of factor Y.

The formula for y-intercept is,

$a=MY−bMX$

The regression equation is, $Y^=bX+a$ .

The value of $SSX$ :

The value of mean for X is,

$MX=32+24+28+17+125=1135=22.6$

X	Y	$(X−MX)$	$(X−MX)2$
32	24	$(32−22.6)=9.4$	88.36
24	20	$(24−22.6)=1.4$	1.96
28	25	$(28−22.6)=5.4$	29.16
17	22	$(17−22.6)=−5.6$	31.36
12	16	$(12−22.6)=−10.6$	112.36
			$∑(X−MX)2=263.2$

Table 1

The value of $SSX$ is 263.2.

The value of $SSXY$ :

The value of mean for Y is,

$MY=24+20+25+22+165=1075=21.4$

X	Y	$(X−MX)$	$(X−MY)$	$(X−MX)(X−MY)$
32	24	$(32−22.6)=9.4$	$(24−21.4)=2.6$	24.44
24	20	$(24−22.6)=1.4$	$(20−21.4)=−1.4$	–1.96
28	25	$(28−22.6)=5.4$	$(25−21.4)=3.6$	19.44
17	22	$(17−22.6)=−5.6$	$(22−21.4)=0.6$	–3.36
12	16	$(12−22.6)=−10.6$	$(16−21.4)=−5.4$	57.24
				$∑(X−MX)(X−MY)=95.8$

Table 2

The value of $SSXY$ is 95.8.

Slope:

Substitute, $SSX=263.2$ and $SSXY=95.8$ in slope formula

$slope(b)=95.8263.2=0.364$

Hence, the value of slope is 0.364.

Substitute, $MY=21.4, MX=22.6, b=0.364$ in y-intercept formula.

$a=MY−bMX=21.4−(0.364)22.6=21.4−8.2264=13.174$

Hence, the value of y-intercept is 13.174.

Substitute, $a=13.174, b=0.364$ in regression equation formula.

$Y^=(0.364)X+13.174=0.36X+13.17$

The equation of the regression line is, $Y^=0.36X+13.17$ .

(b)

To determine

Find the predicted age of a victim of a nonviolent crime when the criminal is 20 years old.

(b)

Expert Solution

Answer to Problem 19CAP

The predicted age of a victim of a nonviolent crime when the criminal is 20 years old is 20.37 years old.

Explanation of Solution

Calculation:

The given information is that the criminal is 20 years old.

The equation of the regression line is $Y^=0.36X+13.17$ .

Substitute, $X=20$ in regression line.

$Y^=0.36(20)+13.174=7.2+13.17=20.37$

Hence, the predicted age of a victim of a nonviolent crime when the criminal is 20 years old is 20.37 years old.

Answer 6

Chapter 16, Problem 19CAP

(a)

To determine

Find the equation of the regression line.

(a)

Expert Solution

Answer to Problem 19CAP

The equation of the regression line is, $Y^=0.36X+13.17$ .

Explanation of Solution

Calculation:

The information given that is the case files to record the age of five criminals and the age of the victim in those cases with the factors age of a criminal (X) predicts the age of the victim (Y) for nonviolent crimes.

The procedure of straight line by using the method of least square is shown below:

Compute preliminary calculations.
Calculate the slope $(b)$ .
Calculate the y-intercept $(a)$ .

The formula for slope is,

$slope(b)=SSXYSSX$

Where,

$SSXY=∑(X−MX)(Y−MY)$

$SSX=∑(X−MX)2$

In the formulas, $MX$ denotes the mean of factor X, $MY$ denotes the mean of factor Y.

The formula for y-intercept is,

$a=MY−bMX$

The regression equation is, $Y^=bX+a$ .

The value of $SSX$ :

The value of mean for X is,

$MX=32+24+28+17+125=1135=22.6$

X	Y	$(X−MX)$	$(X−MX)2$
32	24	$(32−22.6)=9.4$	88.36
24	20	$(24−22.6)=1.4$	1.96
28	25	$(28−22.6)=5.4$	29.16
17	22	$(17−22.6)=−5.6$	31.36
12	16	$(12−22.6)=−10.6$	112.36
			$∑(X−MX)2=263.2$

Table 1

The value of $SSX$ is 263.2.

The value of $SSXY$ :

The value of mean for Y is,

$MY=24+20+25+22+165=1075=21.4$

X	Y	$(X−MX)$	$(X−MY)$	$(X−MX)(X−MY)$
32	24	$(32−22.6)=9.4$	$(24−21.4)=2.6$	24.44
24	20	$(24−22.6)=1.4$	$(20−21.4)=−1.4$	–1.96
28	25	$(28−22.6)=5.4$	$(25−21.4)=3.6$	19.44
17	22	$(17−22.6)=−5.6$	$(22−21.4)=0.6$	–3.36
12	16	$(12−22.6)=−10.6$	$(16−21.4)=−5.4$	57.24
				$∑(X−MX)(X−MY)=95.8$

Table 2

The value of $SSXY$ is 95.8.

Slope:

Substitute, $SSX=263.2$ and $SSXY=95.8$ in slope formula

$slope(b)=95.8263.2=0.364$

Hence, the value of slope is 0.364.

Substitute, $MY=21.4, MX=22.6, b=0.364$ in y-intercept formula.

$a=MY−bMX=21.4−(0.364)22.6=21.4−8.2264=13.174$

Hence, the value of y-intercept is 13.174.

Substitute, $a=13.174, b=0.364$ in regression equation formula.

$Y^=(0.364)X+13.174=0.36X+13.17$

The equation of the regression line is, $Y^=0.36X+13.17$ .

Answer 7

Chapter 16, Problem 19CAP

(a)

To determine

Find the equation of the regression line.

Answer 8

(a)

Expert Solution

Answer to Problem 19CAP

The equation of the regression line is, $Y^=0.36X+13.17$ .

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Calculation:

The information given that is the case files to record the age of five criminals and the age of the victim in those cases with the factors age of a criminal (X) predicts the age of the victim (Y) for nonviolent crimes.

The procedure of straight line by using the method of least square is shown below:

Compute preliminary calculations.
Calculate the slope $(b)$ .
Calculate the y-intercept $(a)$ .

The formula for slope is,

$slope(b)=SSXYSSX$

Where,

$SSXY=∑(X−MX)(Y−MY)$

$SSX=∑(X−MX)2$

In the formulas, $MX$ denotes the mean of factor X, $MY$ denotes the mean of factor Y.

The formula for y-intercept is,

$a=MY−bMX$

The regression equation is, $Y^=bX+a$ .

The value of $SSX$ :

The value of mean for X is,

$MX=32+24+28+17+125=1135=22.6$

X	Y	$(X−MX)$	$(X−MX)2$
32	24	$(32−22.6)=9.4$	88.36
24	20	$(24−22.6)=1.4$	1.96
28	25	$(28−22.6)=5.4$	29.16
17	22	$(17−22.6)=−5.6$	31.36
12	16	$(12−22.6)=−10.6$	112.36
			$∑(X−MX)2=263.2$

Table 1

The value of $SSX$ is 263.2.

The value of $SSXY$ :

The value of mean for Y is,

$MY=24+20+25+22+165=1075=21.4$

X	Y	$(X−MX)$	$(X−MY)$	$(X−MX)(X−MY)$
32	24	$(32−22.6)=9.4$	$(24−21.4)=2.6$	24.44
24	20	$(24−22.6)=1.4$	$(20−21.4)=−1.4$	–1.96
28	25	$(28−22.6)=5.4$	$(25−21.4)=3.6$	19.44
17	22	$(17−22.6)=−5.6$	$(22−21.4)=0.6$	–3.36
12	16	$(12−22.6)=−10.6$	$(16−21.4)=−5.4$	57.24
				$∑(X−MX)(X−MY)=95.8$

Table 2

The value of $SSXY$ is 95.8.

Slope:

Substitute, $SSX=263.2$ and $SSXY=95.8$ in slope formula

$slope(b)=95.8263.2=0.364$

Hence, the value of slope is 0.364.

Substitute, $MY=21.4, MX=22.6, b=0.364$ in y-intercept formula.

$a=MY−bMX=21.4−(0.364)22.6=21.4−8.2264=13.174$

Hence, the value of y-intercept is 13.174.

Substitute, $a=13.174, b=0.364$ in regression equation formula.

$Y^=(0.364)X+13.174=0.36X+13.17$

The equation of the regression line is, $Y^=0.36X+13.17$ .

Answer 13

(b)

To determine

Find the predicted age of a victim of a nonviolent crime when the criminal is 20 years old.

(b)

Expert Solution

Answer to Problem 19CAP

The predicted age of a victim of a nonviolent crime when the criminal is 20 years old is 20.37 years old.

Explanation of Solution

Calculation:

The given information is that the criminal is 20 years old.

The equation of the regression line is $Y^=0.36X+13.17$ .

Substitute, $X=20$ in regression line.

$Y^=0.36(20)+13.174=7.2+13.17=20.37$

Hence, the predicted age of a victim of a nonviolent crime when the criminal is 20 years old is 20.37 years old.

Answer 14

(b)

To determine

Find the predicted age of a victim of a nonviolent crime when the criminal is 20 years old.

Answer 15

(b)

Expert Solution

Answer to Problem 19CAP

The predicted age of a victim of a nonviolent crime when the criminal is 20 years old is 20.37 years old.

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Calculation:

The given information is that the criminal is 20 years old.

The equation of the regression line is $Y^=0.36X+13.17$ .

Substitute, $X=20$ in regression line.

$Y^=0.36(20)+13.174=7.2+13.17=20.37$

Hence, the predicted age of a victim of a nonviolent crime when the criminal is 20 years old is 20.37 years old.

Answer 20

Ch. 16.2 - Prob. 1.1LC Ch. 16.2 - Prob. 1.2LC Ch. 16.2 - Prob. 1.3LC Ch. 16.4 - Prob. 2.1LC Ch. 16.4 - Prob. 2.2LC Ch. 16.4 - Prob. 2.3LC Ch. 16.5 - Prob. 3.1LC Ch. 16.5 - Prob. 3.2LC Ch. 16.6 - Prob. 4.1LC Ch. 16.6 - Prob. 4.2LC

Find the equation of the regression line.

Concept explainers

Videos

Find the equation of the regression line.

Answer to Problem 19CAP

Explanation of Solution

Find the predicted age of a victim of a nonviolent crime when the criminal is 20 years old.

Answer to Problem 19CAP

Explanation of Solution

Want to see more full solutions like this?

Chapter 16 Solutions