Chapter 16, Problem 16.31P

Interpretation Introduction

Interpretation:

The boiling point of a $2.00m$ aqueous solution of $Sc{\left(Cl{O}_4\right)}_3$ has to be calculated.

Concept Introduction:

Boiling point elevation:

The boiling point of a solution is higher than the boiling point of the pure solvent.  The amount by which the boiling point of solution exceeds the boiling point of the pure liquid that is called the boiling point elevation.  The mathematical relationship is given below.

  $\Delta T_b=T_b-T_b{}^{\circ }=K_b{m}_c$

Where, $\Delta T_b$ is boiling point elevation, $T_b$ is the boiling point of solution, $T_b{}^{\circ }$ is the boiling point of pure solvent, $K_b$ is the boiling point elevation constant and $m_c$ is the colligative molality.