(a)
Interpretation: From the given concentration of
Concept Introduction:
Autoionization of water is the reaction in which the water undergoes ionization to give a proton and a hydroxide ion. Water is a very weak electrolyte and hence it does not completely dissociate into the ions. The ionization happens to a very less extent only. The ionization of water is an equilibrium reaction and hence this has equilibrium rate constant.
To calculate the concentration of
(a)
Answer to Problem 16.21QP
Answer
The concentration of
Explanation of Solution
Given
Concentration of
Formula
Where,
Substitute the given concentration of
Thus the concentration of
(b)
Interpretation: From the given concentration of
Concept Introduction:
Autoionization of water is the reaction in which the water undergoes ionization to give a proton and a hydroxide ion. Water is a very weak electrolyte and hence it does not completely dissociate into the ions. The ionization happens to a very less extent only. The ionization of water is an equilibrium reaction and hence this has equilibrium rate constant.
To calculate the concentration of
(b)
Answer to Problem 16.21QP
Answer
The concentration of
Explanation of Solution
Given
Concentration of
Formula
Where,
Substitute the given concentration of
Thus the concentration of
c)
Interpretation: From the given concentration of
Concept Introduction:
Autoionization of water is the reaction in which the water undergoes ionization to give a proton and a hydroxide ion. Water is a very weak electrolyte and hence it does not completely dissociate into the ions. The ionization happens to a very less extent only. The ionization of water is an equilibrium reaction and hence this has equilibrium rate constant.
To calculate the concentration of
c)
Answer to Problem 16.21QP
Answer
The concentration of
Explanation of Solution
Given
Concentration of
Formula
Where,
Substitute the given concentration of
Thus the concentration of
(d)
Interpretation: From the given concentration of
Concept Introduction:
Autoionization of water is the reaction in which the water undergoes ionization to give a proton and a hydroxide ion. Water is a very weak electrolyte and hence it does not completely dissociate into the ions. The ionization happens to a very less extent only. The ionization of water is an equilibrium reaction and hence this has equilibrium rate constant.
To calculate the concentration of
(d)
Answer to Problem 16.21QP
Answer
The concentration of
Explanation of Solution
Given
Concentration of
Formula
Where,
Substitute the given concentration of
Thus the concentration of
Want to see more full solutions like this?
Chapter 16 Solutions
Chemistry: Atoms First
- A solution contains 0.350 grams of malonic acid, H2C3H2O4 in 500.0ml.(malonic acid a diprotic acid). What is the molarity of the solution? What is the normality of the solution? What is the % (W/V) of the solution?arrow_forwardIf the hydrogen ion concentration of a 0.100 M HC3H5O3 solution is 0.0038 M, what is the ionization constant for lactic acid?arrow_forwardWhich beaker correctly depicts the best representation of AgCl in a beaker of water?arrow_forward
- Complete and balance the following neutralization reactions. HNO3(aq)+Ca(OH)2(aq)→HNO3(aq)+Ca(OH)2(aq)→ Express your answer as a chemical equation. Identify all of the phases in your answer.arrow_forwardGiven the values on the image find the Molarity of NaOH and the % (w/v) of acetic acid.arrow_forwardUse the mean value of 540 for Keq to calculate the SCN− concentration in a solution whose initial Fe3+ concentration was 4.10×10−02 M and initial SCN− concentration was 1.50×10−03 M . Fe3++SCN−⇌FeNCS2+arrow_forward
- How many grams of ammonium chloride,NH4Cl , are required to make a 3.05 %(w/v) aqueous solution in a 250. mL volumetric flask? garrow_forwardComplete and balance each of the following equations for acid-base reactions. H2SO4(aq)+Ca(OH)2(aq)→H2SO4(aq)+Ca(OH)2(aq)→ Express your answer as a chemical equation. Identify all of the phases in your answer.arrow_forwardA student prepared two solutions: 1 @ (water + cabbage extract) and 1 @ (buffet + cabbage extract). The student adjusted the solutions to pH = 7 but forgot to label each of them so both were indistinguishable. The student decided to test one of the two solutions and split the solution into two beakers: Sol1 and Sol2. The student was really struggling that day and forgot to label the HCL and the NaOH solutions. Continuing with the experiment, the student added SolA into Sol1 and the color turned light red. What is the identity of SolA? What will the color of Sol2 be after SolB is added? What must the initial solution contain?arrow_forward
- Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningPrinciples of Modern ChemistryChemistryISBN:9781305079113Author:David W. Oxtoby, H. Pat Gillis, Laurie J. ButlerPublisher:Cengage Learning
- Chemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning