Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Question
Chapter 16, Problem 16.16P
To determine
Find the gross allowable load that the footing could carry using the effective area concept.
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Students have asked these similar questions
A rectangular footing is constructed on saturated sand. This footing is placed under 1000 KN
column load and 500 KN.m moment as shown in the image. Find the eccentricity in both
directions and calculate the equivalent footing size.
3.0
M=500 KN.m
0.50
2.5
P1=1000 KN
0.50
A square footing is shown
on the right. The footing is
subjected to an eccentric
load. For the following
cases, determine the gross
allowable load that the
Qult
Unit weight of
soil = y
(or density = F
footing could carry. Use
Meyerhof's procedure and
Fs = 4.
Given:
p = 1950 kg/m³ ; c' = 0
$ = 40°
D,= 1.4 m
; В 3 3 m
;x = 0.5
%3D
y = 0
b) As shown in the figure below, a rectangular footing (B x L = 2m x 2.2m) is subjected
to a vertical load (400 kN) and moment (100 kN-m). The eccentricity is in the direction
of L. Determine the effective width B'
=
9max =
, and
400 kN
2.2 m
Rock
1
the effective length L'
100 kN-m
Chapter 16 Solutions
Principles of Geotechnical Engineering (MindTap Course List)
Ch. 16 - A continuous footing is shown in Figure 16.17....Ch. 16 - Refer to Problem 16.1. If a square footing with...Ch. 16 - Redo Problem 16.1 with the following: = 115...Ch. 16 - Redo Problem 16.1 with the following: = 16.5...Ch. 16 - Redo Problem 16.1 using the modified general...Ch. 16 - Redo Problem 16.2 using the modified general...Ch. 16 - Redo Problem 16.3 using the modified general...Ch. 16 - Redo Problem 16.4 using the modified general...Ch. 16 - Prob. 16.9PCh. 16 - If the water table in Problem 16.9 drops down to...
Ch. 16 - Prob. 16.11PCh. 16 - A square footing is subjected to an inclined load...Ch. 16 - A square footing (B B) must carry a gross...Ch. 16 - Redo Problem 16.13 with the following data: gross...Ch. 16 - Refer to Problem 16.13. Design the size of the...Ch. 16 - Prob. 16.16PCh. 16 - Prob. 16.17PCh. 16 - Refer to the footing in Problem 16.16. Determine...Ch. 16 - Figure 16.21 shows a continuous foundation with a...Ch. 16 - The following table shows the boring log at a site...
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- b) As shown in the figure below, a rectangular footing (B x L = 2m x 2.2m) is subjected to a vertical load (400 kN) and moment (100 kN-m). The eccentricity is in the direction , the effective length L =___, and of L. Determine the effective width B' = = 9max = - 400 kN 100 kN-m 2.2 m Rockarrow_forwardThe ultimate bearing capacity of a strip footing is 1500 mm wide and 120 cm deep for a frictional cohesive soil, Use Terzaghi's formula at general failure condition. Take Nc= 57.80, Nq= 41.4, Nϒ= 42.4, ϒ = 18kN/m3, c= 15kN/m3arrow_forwardA square footing is shown on the right. The footing is subjected to an eccentric load. For the following cases, determine the gross Qult Unit weight of soil = y (or density = f allowable load that the footing could carry. Use Meyerhof's procedure and Fs = 4. Given: y = 120 lb/ft3 ; c' = 400 lb/ft? $ = 25° %D %3D ; B = 6 ft %3D D, = 4.5 ft ; x = 0 В y = 0,5 ftarrow_forward
- A strip footing is to carry a load of 750kN/m at a depth of 1.6m in acohesive soil having unit weight of 18kN/ m3 & C=20kN/ m2and angle of internal friction is 25 degree. Determine the width of footing, using F.O.S as 3. Use Terzhagi’s equations. Nc = 25.1, Nq = 12.7 and Nγ = 9.7arrow_forwardb) As shown in the figure below, a rectangular footing (B x L = 2m x 2.2m) is subjected to a vertical load (400 kN) and moment (100 kN-m). The eccentricity is in the direction of L. Determine the effective width B': , and = 9max = — 400 KN t 2.2 m Y 100 kN-m Rock the effective length =arrow_forward1. A circular footing 3 m in diameter is shown below. [Soil Bearing Capacity] ( Assume the general shear failure and use a factor of safety 2.8. Determine the follow N. = 25.13 , N, = 12.72, N, = 8. 34 a. The gross allowable bearing capacity. b. Net Allowable bearing capacity c. The safe load that the footing can carry. Ground surface Y = 18.5 kN/m³ C = 80 kPa + = 25° 1.1 m D: = 1.8 m Water table Tse = 19.2 kN/m? Diameter = 3 marrow_forward
- FDE 007: A square footing 2m x 2m is located at a depth of 1.2m below the ground surface. The soil properties are cohesion c' = 10 kPa, angle of internal friction = 15 degrees, unit weight of soil = 16.7 kN/m³ and saturated unit weight of soil = 20kN/m³. Use Terzhagi's bearing capacity equation: q=1.3cNc + (gamma)D+Na+ 0.4(B)(gamma)(Ngamma) Bearing capacity factors, Nc = 12.9, Nq = 4.4, Ngamma = 2.5. Find qu under the following conditions: Refer to FDE 007. When the water table is at the ground surface. Select the correct response: 94.563 kPa 277.75 kPa 126.58 kPa 328.67 kPaarrow_forwardQ: A rigid shallow footing has the dimension of 1m x 1m, shown in the following figure. The depth of footing, mechanical properties of supporting soil and the load transmitted through the footing are shown in the figure. Determine shape factor (Is) and depth factor (I). 500 mm E,= 6500 kN/m² H₂=0.3 E, - 5000 kN/m² 1₂ = 0.3 E, 10000 kN/m = H₂ = 0.3 Ao = 200 kN/m² 0.0 m 3.0 m 5.0 m 8.0 marrow_forwardEx1: A footing is uniformly loaded with q = 100 kN/m² as shown in the figure. Compute the vertical stress increments under Points A, B, and C at z = 10 m. By 13.5 Footing 12m Use Vertical stress Increment under corner of rectangular footing 7 (Plane view) 6arrow_forward
- A square footing (1.5 m × 1.5 m) is located at a depth of 1.0 m. The footing is subjected to an eccentric load of 450 kN, with an eccentricity of 0.2 m along one of the symmetrical axes. Determine the factor of safety against bearing failure. U se Vesic's equation. Take y= 21 kN/m³, c = 100 kN/m², p= 0; N = 5.14; s = 1.14; s = 1; d. 1.27 ; d = 1; i = ig = 1. = q qarrow_forwardA rectangular footing 2 m x 3 m carries a column load of 600 kN a at depth of 1 m. The footing rests on a c-O soil strata 6 m thick, having Poisson's ratio of 0.25 and Young's modulus of elasticity as 20000 kN/m2. The immediate elastic settlement of the footing occurs as soon as the load is applied. The depth of the footing after immediate settlement from original ground level will be. (Take I, = 1.06) mm.arrow_forward. A square footing is shown is the following figure. Assume the induced stress, Ao,, due to load from foundation is linearly distributed along the depth, as shown in the figure. Ignore the deformation of hard rock. Using the classical method, compute its settlement. S, = 140kPa C/(1+e) 0.12 C, / (1+e) = 0.02 2m Aơ, = 150kPa O'= 200kPa y = 18kN/m Silty clay Ao, = 70kPa Hard rock 1.0m 1.5marrow_forward
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