Chapter 16, Problem 16.126SP

Interpretation Introduction

Interpretation:

Whether $$

${\text{Fe}}^{\text{2+}}$ can be separated from ${\text{Sn}}^{\text{2+}}$ by bubbling ${\text{H}}_{\text{2}}\text{S}$ in presence of $\text{0}\text{.3 M HCl}$ must be determined.

Concept introduction:

• Common ion effect is the phenomena in which the solubility of a species is decreased in presence of any common ion.
• Passing ${\text{H}}_{\text{2}}\text{S}$ in presence of $\text{HCl}$is an application of common ion effect.
• Solubility of ${\text{S}}^{\text{2-}}$ decreases due to presence of $\text{HCl}$ which give ${\text{H}}^{\text{+}}$ as the common ion with ${\text{H}}_{\text{2}}\text{S}$.

Given:

Concentrations of $\left[{\text{Fe}}^{\text{2+}}\right]$ is $\text{0}\text{.01 M}$ and $\left[{\text{Sn}}^{\text{2+}}\right]\text{=0}\text{.01 M}$

${\text{K}}_{\text{sp}}$ of $\text{FeS=6}\times {\text{10}}^{\text{2}}$ and ${\text{K}}_{\text{sp}}$ of $\text{SnS=1}\times {\text{10}}^{\text{-5}}$

$\left[\text{HCl}\right]\text{=0}\text{.3 M}$ and $\left[{\text{H}}_{\text{2}}\text{S}\right]\text{=0}\text{.1 M}$