Organic Chemistry
Organic Chemistry
9th Edition
ISBN: 9781305080485
Author: John E. McMurry
Publisher: Cengage Learning
bartleby

Concept explainers

bartleby

Videos

Textbook Question
Book Icon
Chapter 15.SE, Problem 13VC

Give IUPAC names for the following substances (red = O, blue = N):

Chapter 15.SE, Problem 13VC, Give IUPAC names for the following substances (red = O, blue = N):

Expert Solution
Check Mark
Interpretation Introduction

a)

Organic Chemistry, Chapter 15.SE, Problem 13VC , additional homework tip  1

Interpretation:

The IUPAC name of the compound shown is to be given.

Concept introduction:

Compounds with a hydroxyl group attached to the benzene ring are named as derivatives of phenol. Substituted phenols are named using the prefixes ortho (o), meta (m) and para (p). An ortho-substituted phenol has an another substituent in a 1,2-relationship on the ring. A meta-disubstituted phenol has an another substituent in a 1,3-relationship on the ring. A para-disubstituted phenol has another substituent in a 1,4-relationship on the ring.

To give:

The IUPAC name of the compound shown.

Answer to Problem 13VC

The IUPAC name of the compound is m-isopropylphenol.

Explanation of Solution

The compound shown is

Organic Chemistry, Chapter 15.SE, Problem 13VC , additional homework tip  2

It has a hydroxyl and an isopropyl groups in the benzene ring in 1,3-relationship. Therefore its IUPAC name is m-isopropylphenol.

Conclusion

The IUPAC name of the compound is m-isopropylphenol.

Expert Solution
Check Mark
Interpretation Introduction

b)

Organic Chemistry, Chapter 15.SE, Problem 13VC , additional homework tip  3

Interpretation:

The IUPAC name of the compound shown is to be given.

Concept introduction:

Compounds with a carboxyl group attached to the benzene ring are named as derivatives of benzoic acid. Substituted benzoic acids are named using the prefixes ortho (o), meta (m) and para (p). An ortho-substituted benzoic acid has an another substituent in a 1,2-relationship on the ring. A meta-disubstituted benzoic acid has an another substituent in a 1,3-relationship on the ring. A para-disubstituted benzoic acid has another substituent in a 1,4-relationship on the ring.

To give:

The IUPAC name of the compound shown.

Answer to Problem 13VC

The IUPAC name of the compound is o-nitrobenzoic acid.

Explanation of Solution

The compound shown is

Organic Chemistry, Chapter 15.SE, Problem 13VC , additional homework tip  4

It has a carboxyl group and a nitro group in the benzene ring in 1,2-relationship. Therefore its IUPAC name is o-nitrobenzoic acid.

Conclusion

The IUPAC name of the compound is o-nitrobenzoic acid.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Give the IUPAC name for each compound (except A)
8
Give the IUPAC name of the following compounds:

Chapter 15 Solutions

Organic Chemistry

Ch. 15.6 - Prob. 11PCh. 15.6 - How many electrons does each of the four nitrogen...Ch. 15.SE - Give IUPAC names for the following substances (red...Ch. 15.SE - All-cis cyclodecapentaene is a stable molecule...Ch. 15.SE - 1, 6-Methanonaphthalene has an interesting 1H NMR...Ch. 15.SE - Prob. 16VCCh. 15.SE - Azulene, an isomer of naphthalene, has a...Ch. 15.SE - Give IUPAC names for the following compounds:Ch. 15.SE - Draw structures corresponding to the following...Ch. 15.SE - Prob. 20APCh. 15.SE - Prob. 21APCh. 15.SE - Draw and name all possible aromatic compounds with...Ch. 15.SE - Propose structures for aromatic hydrocarbons that...Ch. 15.SE - Look at the three resonance structures of...Ch. 15.SE - Prob. 25APCh. 15.SE - Prob. 26APCh. 15.SE - Look at the five resonance structures for...Ch. 15.SE - Prob. 28APCh. 15.SE - 3-Chlorocyclopropene, on treatment with AgBF4,...Ch. 15.SE - Prob. 30APCh. 15.SE - Prob. 31APCh. 15.SE - Prob. 32APCh. 15.SE - Which would you expect to be most stable,...Ch. 15.SE - How might you convert 1, 3, 5, 7-cyclononatetraene...Ch. 15.SE - Calicene, like azulene (Problem 15-17), has an...Ch. 15.SE - Pentalene is a most elusive molecule that has been...Ch. 15.SE - Prob. 37APCh. 15.SE - Prob. 38APCh. 15.SE - Compound A, C8H10, yields three substitution...Ch. 15.SE - Prob. 40APCh. 15.SE - Propose structures for compounds that fit the...Ch. 15.SE - Prob. 42APCh. 15.SE - Prob. 43APCh. 15.SE - N-Phenylsydnone, so-named because it was first...Ch. 15.SE - Prob. 45APCh. 15.SE - Prob. 46APCh. 15.SE - Prob. 47APCh. 15.SE - Propose a structure for a molecule C14H12 that has...Ch. 15.SE - The proton NMR spectrum for a compound with...Ch. 15.SE - The proton NMR spectrum of a compound with formula...Ch. 15.SE - Aromatic substitution reactions occur by addition...Ch. 15.SE - Prob. 52APCh. 15.SE - Consider the aromatic anions below and their...Ch. 15.SE - After the reaction below, the chemical shift of Ha...Ch. 15.SE - Prob. 55APCh. 15.SE - Azo dyes are the major source of artificial color...
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Organic Chemistry
Chemistry
ISBN:9781305080485
Author:John E. McMurry
Publisher:Cengage Learning
Text book image
Chemistry for Today: General, Organic, and Bioche...
Chemistry
ISBN:9781305960060
Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher:Cengage Learning
Text book image
Introduction to General, Organic and Biochemistry
Chemistry
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning
Nomenclature: Crash Course Chemistry #44; Author: CrashCourse;https://www.youtube.com/watch?v=U7wavimfNFE;License: Standard YouTube License, CC-BY