To identify the number of proton signals the structure exhibits in the 1 H NMR spectrum. Concept Introduction : 1 H NMR : A technique gives information to predict the Carbon and Hydrogen connectivity in the organic compounds. Enantiotopic protons: If subjected protons in the molecule can be interchanged through rotational or reflection symmetry known as Enantiotopic protons and the protons are chemically equivalent. Replacement test: In the molecule replacing each one of the subjected protons with deuterium gives the two compounds are same; then the protons are chemically equivalent. To Identify: The number of proton signals the structure would exhibits.

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Answer 1

Question

Chapter 15.4, Problem 2LTS

Interpretation Introduction

Interpretation: To identify the number of proton signals the structure exhibits in the 1H NMR spectrum.

Concept Introduction:

1H NMR : A technique gives information to predict the Carbon and Hydrogen connectivity in the organic compounds.

Enantiotopic protons: If subjected protons in the molecule can be interchanged through rotational or reflection symmetry known as Enantiotopic protons and the protons are chemically equivalent.

Replacement test: In the molecule replacing each one of the subjected protons with deuterium gives the two compounds are same; then the protons are chemically equivalent.

To Identify: The number of proton signals the structure would exhibits.

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Answer 2

Question

Chapter 15.4, Problem 2LTS

Interpretation Introduction

Interpretation: To identify the number of proton signals the structure exhibits in the 1H NMR spectrum.

Concept Introduction:

1H NMR : A technique gives information to predict the Carbon and Hydrogen connectivity in the organic compounds.

Enantiotopic protons: If subjected protons in the molecule can be interchanged through rotational or reflection symmetry known as Enantiotopic protons and the protons are chemically equivalent.

Replacement test: In the molecule replacing each one of the subjected protons with deuterium gives the two compounds are same; then the protons are chemically equivalent.

To Identify: The number of proton signals the structure would exhibits.

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Answer 3

Question

Chapter 15.4, Problem 2LTS

Interpretation Introduction

Interpretation: To identify the number of proton signals the structure exhibits in the 1H NMR spectrum.

Concept Introduction:

1H NMR : A technique gives information to predict the Carbon and Hydrogen connectivity in the organic compounds.

Enantiotopic protons: If subjected protons in the molecule can be interchanged through rotational or reflection symmetry known as Enantiotopic protons and the protons are chemically equivalent.

Replacement test: In the molecule replacing each one of the subjected protons with deuterium gives the two compounds are same; then the protons are chemically equivalent.

To Identify: The number of proton signals the structure would exhibits.

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Answer 4

Question

Chapter 15.4, Problem 2LTS

Interpretation Introduction

Interpretation: To identify the number of proton signals the structure exhibits in the 1H NMR spectrum.

Concept Introduction:

1H NMR : A technique gives information to predict the Carbon and Hydrogen connectivity in the organic compounds.

Enantiotopic protons: If subjected protons in the molecule can be interchanged through rotational or reflection symmetry known as Enantiotopic protons and the protons are chemically equivalent.

Replacement test: In the molecule replacing each one of the subjected protons with deuterium gives the two compounds are same; then the protons are chemically equivalent.

To Identify: The number of proton signals the structure would exhibits.

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Answer 5

Chapter 15.4, Problem 2LTS

Interpretation Introduction

Interpretation: To identify the number of proton signals the structure exhibits in the 1H NMR spectrum.

Concept Introduction:

1H NMR : A technique gives information to predict the Carbon and Hydrogen connectivity in the organic compounds.

Enantiotopic protons: If subjected protons in the molecule can be interchanged through rotational or reflection symmetry known as Enantiotopic protons and the protons are chemically equivalent.

Replacement test: In the molecule replacing each one of the subjected protons with deuterium gives the two compounds are same; then the protons are chemically equivalent.

To Identify: The number of proton signals the structure would exhibits.

Answer 6

Chapter 15.4, Problem 2LTS

Interpretation Introduction

Interpretation: To identify the number of proton signals the structure exhibits in the 1H NMR spectrum.

Concept Introduction:

1H NMR : A technique gives information to predict the Carbon and Hydrogen connectivity in the organic compounds.

Enantiotopic protons: If subjected protons in the molecule can be interchanged through rotational or reflection symmetry known as Enantiotopic protons and the protons are chemically equivalent.

Replacement test: In the molecule replacing each one of the subjected protons with deuterium gives the two compounds are same; then the protons are chemically equivalent.

To Identify: The number of proton signals the structure would exhibits.

Answer 7

Chapter 15.4, Problem 2LTS

Interpretation Introduction

Interpretation: To identify the number of proton signals the structure exhibits in the 1H NMR spectrum.

Concept Introduction:

1H NMR : A technique gives information to predict the Carbon and Hydrogen connectivity in the organic compounds.

Enantiotopic protons: If subjected protons in the molecule can be interchanged through rotational or reflection symmetry known as Enantiotopic protons and the protons are chemically equivalent.

Replacement test: In the molecule replacing each one of the subjected protons with deuterium gives the two compounds are same; then the protons are chemically equivalent.

To Identify: The number of proton signals the structure would exhibits.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 15.4 - Prob. 1LTS Ch. 15.4 - Prob. 1PTS Ch. 15.4 - Prob. 2PTS Ch. 15.4 - Prob. 3PTS Ch. 15.4 - Prob. 4ATS Ch. 15.4 - Prob. 2LTS Ch. 15.5 - Prob. 3LTS Ch. 15.6 - Prob. 4LTS Ch. 15.6 - Prob. 11PTS Ch. 15.6 - Prob. 12PTS

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