Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN: 9781337553292
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 15.2, Problem 15.3QQ
shows two curves representing particles undergoing
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Two blocks, with masses M1 = 2.10 kg and M2 = 9.20 kg, and a spring with spring constant k = 463 N/m are arranged on a horizontal, frictionless surface as shown in the Figure. The coefficient of static friction between the two blocks is 0.540. What is the maximum possible amplitude of the simple harmonic motion if no slippage is to occur between the blocks?
Problem 1:
A particle undergoes simple harmonic motion with a frequency of f, = 10 Hz. At t = 0 ; the
position of the particle is x(0) = 0.25 m, and the velocity of the particle is v(0) = 0.1 m/s
a- Calculate the angular frequency of the oscillation (wo = ??)
b- Find the amplitude of the oscillation (A = ??)
c- Determine the phase f from the initial conditions (f=??)
d- Find the displacement x at any time t. (x(t) = ??)
In the figure, a physical pendulum consists of a uniform solid disk (of radius R = 44.6 cm) supported in a vertical plane by a pivot located
a distance d = 30.4 cm from the center of the disk. The disk is displaced by a small angle and released. What is the period of the
resulting simple harmonic motion?
A disk with radius R supported in a vertical plane by a pivot that is located a distance of d from the center of the disk.
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Chapter 15 Solutions
Physics for Scientists and Engineers with Modern Physics
Ch. 15.1 - A block on the end of a spring is pulled to...Ch. 15.2 - Consider a graphical representation (Fig. 15.3) of...Ch. 15.2 - shows two curves representing particles undergoing...Ch. 15.2 - An object of mass m is hung from a spring and set...Ch. 15.4 - The ball in Figure 15.13 moves in a circle of...Ch. 15.5 - The grandfather clock in the opening storyline...Ch. 15 - A 0.60-kg block attached to a spring with force...Ch. 15 - A piston in a gasoline engine is in simple...Ch. 15 - The position of a particle is given by the...Ch. 15 - Prob. 4P
Ch. 15 - Review. A particle moves along the x axis. It is...Ch. 15 - Prob. 6PCh. 15 - A particle moving along the x axis in simple...Ch. 15 - The initial position, velocity, and acceleration...Ch. 15 - You attach an object to the bottom end of a...Ch. 15 - Prob. 10PCh. 15 - Prob. 11PCh. 15 - Prob. 12PCh. 15 - A simple harmonic oscillator of amplitude A has a...Ch. 15 - Review. A 65.0-kg bungee jumper steps off a bridge...Ch. 15 - Review. A 0.250-kg block resting on a...Ch. 15 - While driving behind a car traveling at 3.00 m/s,...Ch. 15 - A simple pendulum makes 120 complete oscillations...Ch. 15 - A particle of mass m slides without friction...Ch. 15 - A physical pendulum in the form of a planar object...Ch. 15 - Prob. 20PCh. 15 - Prob. 21PCh. 15 - Consider the physical pendulum of Figure 15.16....Ch. 15 - A watch balance wheel (Fig. P15.25) has a period...Ch. 15 - Show that the time rate of change of mechanical...Ch. 15 - Show that Equation 15.32 is a solution of Equation...Ch. 15 - Prob. 26PCh. 15 - Prob. 27PCh. 15 - Considering an undamped, forced oscillator (b =...Ch. 15 - Prob. 29PCh. 15 - Prob. 30PCh. 15 - An object of mass m moves in simple harmonic...Ch. 15 - Prob. 32APCh. 15 - An object attached to a spring vibrates with...Ch. 15 - Prob. 34APCh. 15 - A pendulum of length L and mass M has a spring of...Ch. 15 - Prob. 36APCh. 15 - Review. A particle of mass 4.00 kg is attached to...Ch. 15 - Prob. 38APCh. 15 - Prob. 39APCh. 15 - Prob. 40APCh. 15 - Review. A lobstermans buoy is a solid wooden...Ch. 15 - Prob. 42APCh. 15 - Prob. 43APCh. 15 - Prob. 44APCh. 15 - A block of mass m is connected to two springs of...Ch. 15 - Review. A light balloon filled with helium of...Ch. 15 - A particle with a mass of 0.500 kg is attached to...Ch. 15 - A smaller disk of radius r and mass m is attached...Ch. 15 - Prob. 49CPCh. 15 - Prob. 50CPCh. 15 - A light, cubical container of volume a3 is...
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- A simple harmonic oscillator has amplitude A and period T. Find the minimum time required for its position to change from x = A to x = A/2 in terms of the period T.arrow_forwardThe total energy of a simple harmonic oscillator with amplitude 3.00 cm is 0.500 J. a. What is the kinetic energy of the system when the position of the oscillator is 0.750 cm? b. What is the potential energy of the system at this position? c. What is the position for which the potential energy of the system is equal to its kinetic energy? d. For a simple harmonic oscillator, what, if any, are the positions for which the kinetic energy of the system exceeds the maximum potential energy of the system? Explain your answer. FIGURE P16.73arrow_forwardC, N A uniform plank of length L and mass M is balanced on a fixed, semicircular bowl of radius R (Fig. P16.19). If the plank is tilted slightly from its equilibrium position and released, will it execute simple harmonic motion? If so, obtain the period of its oscillation.arrow_forward
- Figure 12.4 shows two curves representing particles undergoing simple harmonic motion. The correct description of these two motions is that the simple harmonic motion of particle B is (a) of larger angular frequency and larger amplitude than that of particle A, (b) of larger angular frequency and smaller amplitude than that of particle A, (c) of smaller angular frequency and larger amplitude than that of particle A, or (d) of smaller angular frequency and smaller amplitude than that of particle A. Figure 12.4 (Quick Quiz 12.3) Two xt graphs for particles undergoing simple harmonic motion. The amplitudes and frequencies are different for the two particles.arrow_forwardReproduce Figures 3-10b and c for the same values given in Example 3.2, but instead let = 0.1 s1 and = rad. How many times does the system cross the x = 0 line before the amplitude finally falls below 102 of its maximum value? Which plot, b or c, is more useful for determining this number? Explain.arrow_forwardConsider the simplified single-piston engine in Figure CQ12.13. Assuming the wheel rotates with constant angular speed, explain why the piston rod oscillates in simple harmonic motion. Figure CQ12.13arrow_forward
- The equations listed in Table 2.2 give position as a function of time, velocity as a function of time, and velocity as a function of position for an object moving in a straight line with constant acceleration. The quantity vxi appears in every equation. (a) Do any of these equations apply to an object moving in a straight line with simple harmonic motion? (b) Using a similar format, make a table of equations describing simple harmonic motion. Include equations giving acceleration as a function of time and acceleration as a function of position. State the equations in such a form that they apply equally to a blockspring system, to a pendulum, and to other vibrating systems. (c) What quantity appears in every equation?arrow_forwardThe expression x = 8.50 cos (2.40 t + /2) describes the position of an object as a function of time, with x in centimeters and t in seconds. What are the a. frequency, b. period, c. amplitude, and d. initial phase of the objects motion? e. What is the position of the particle at t = 1.45 s?arrow_forwardA particle undergoes a simple harmonic motion with an amplitude A and a total energy E. When the displacement is one-fourth the amplitude (x A/4), the ratio of the kinetic energy, K. to the total energy, E, is: O K/E = 15/16 O K/E= 3/4 O K/E = 1/4 O KE= 8/9 K/E 1/16 KE=1/9arrow_forward
- You have made a physical pendulum by swinging a rod of mass M = 1.08 kg and length L = 1.45 meters around its end. The mass of the rod is distributed uniformly along its length. We will assume that the amplitude of the swing is max = 19.34 degrees. Solid Rod Swings in Simple Harmonic Motion ^ 0=-0, max 0=+0₁ max Determine all the following: The FORMULA for the moment of inertia of your rod, I = The distance from the pivot point to the Center-Of-Mass, d = The angular frequency of the pendulum, w = The amplitude of the motion in radians, max = radians The angular velocity when 0 = 64% of full swing, w(0 = 0.64 0max): NOTE: The first question requires a FORMULA, not a value. rad/sec = meters rad/secarrow_forwardA body performs simple harmonic motion in a straight line. Its velocity is 12 m/s when the displacement is 50 mm, and 3 m/s when the displacement is 100 mm, the displacement being measured from the mid - position. Calculate the frequency and amplitude of the motion. What is the acceleration when the displacement is 75 mm?arrow_forward
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