Chapter 15, Problem 7STP

To determine

To Choose: The correct option.

Answer to Problem 7STP

Option B

Explanation of Solution

Introduction:

The frequency at which the instrument’s natural frequency matches is called resonant frequency.

For a clamped string, resonance frequencies occur at: $f_n=n{f}_1\left(n=1,2,3,\mathrm{4...}\right)$

For a closed pipe, resonance frequencies occur at: $f_n=n{f}_1\left(n=1,3,5,\mathrm{7...}\right)$

For an open pipe, resonance frequencies occur at: $f_n=n{f}_1\left(n=1,2,3,\mathrm{4...}\right)$

For reed instruments, resonance frequencies occur at: $f_n=n{f}_1\left(n=1,3,5,\mathrm{7...}\right)$

Here, $f_1$ represents the lowest frequency and n is a positive integer.

Conclusion:

Thus, clamped string and open pipe have resonant frequencies at each whole number multiple of lowest frequency. The correct option is B.