Fundamentals of Physics Extended
10th Edition
ISBN: 9781118230725
Author: David Halliday, Robert Resnick, Jearl Walker
Publisher: Wiley, John & Sons, Incorporated
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Chapter 15, Problem 75P
A 4.00 kg block is suspended from a spring with k = 500 N/m. A 50.0 g bullet is fired into the block from directly below with a speed of 150 m/s and becomes embedded in the block. (a) Find the amplitude of the resulting
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Chapter 15 Solutions
Fundamentals of Physics Extended
Ch. 15 - Which of the following describe for the SHM of...Ch. 15 - The velocity vt of a particle undergoing SHM is...Ch. 15 - The acceleration at of a particle undergoing SHM...Ch. 15 - Which of the following relationships between the...Ch. 15 - You are to complete Fig. 15-22a so that it is a...Ch. 15 - You are to complete Fig. 15-23a so that it is a...Ch. 15 - Figure 15-24 shows the xt curves for three...Ch. 15 - Figure 15-25 shows plots of the kinetic energy K...Ch. 15 - Figure 15-26 shows three physical pendulums...Ch. 15 - You are to build the oscillation transfer device...
Ch. 15 - In Fig. 15-28, a springblock system is put into...Ch. 15 - Figure 15-29 gives, for three situations, the...Ch. 15 - An object undergoing simple harmonic motion takes...Ch. 15 - A 0.12 kg body undergoes simple harmonic motion of...Ch. 15 - What is the maximum acceleration of a platform...Ch. 15 - An automobile can be considered to be mounted on...Ch. 15 - SSM In an electric shaver, the blade moves back...Ch. 15 - A particle with a mass of 1.00 1020 kg is...Ch. 15 - SSM A loudspeaker produces a musical sound by...Ch. 15 - What is the phase constant for the harmonic...Ch. 15 - The position function x = 6.0 m cos3 rad/st /3...Ch. 15 - An oscillating blockspring system takes 0.75 s to...Ch. 15 - In Fig. 15-31, two identical springs of spring...Ch. 15 - What is the phase constant for the harmonic...Ch. 15 - SSM An oscillator consists of a block of mass...Ch. 15 - A simple harmonic oscillator consists of a block...Ch. 15 - SSM Two particles oscillate in simple harmonic...Ch. 15 - Two particles execute simple harmonic motion of...Ch. 15 - ILW An oscillator consists of a block attached to...Ch. 15 - GO At a certain harbor, the tides cause the ocean...Ch. 15 - A block rides on a piston a squat cylindrical...Ch. 15 - GO Figure 15-33a is a partial graph of the...Ch. 15 - ILW In Fig. 15-31, two springs are attached to a...Ch. 15 - GO Figure 15-34 shows block 1 of mass 0.200 kg...Ch. 15 - SSM WWW A block is on a horizontal surface a shake...Ch. 15 - In Fig. 15-35, two springs are joined and...Ch. 15 - GO In Fig. 15-36, a block weighing 14.0 N, which...Ch. 15 - GO In Fig. 15-37, two blocks m = 1.8 kg and M = 10...Ch. 15 - SSM When the displacement in SHM is one-half the...Ch. 15 - Figure 15-38 gives the one-dimensional potential...Ch. 15 - SSM Find the mechanical energy of a blockspring...Ch. 15 - An oscillating blockspring system has a mechanical...Ch. 15 - ILW A 5.00 kg object on a horizontal frictionless...Ch. 15 - Figure 15-39 shows the kinetic energy K of a...Ch. 15 - GO A block of mass M = 5.4 kg, at rest on a...Ch. 15 - GO In Fig. 15-41, block 2 of mass 2.0 kg...Ch. 15 - A 10 g particle undergoes SHM with an amplitude of...Ch. 15 - If the phase angle for a blockspring system in SHM...Ch. 15 - GO A massless spring hangs from the ceiling with a...Ch. 15 - A 95 kg solid sphere with a 15 cm radius is...Ch. 15 - SSM WWW The balance wheel of an old-fashioned...Ch. 15 - ILW A physical pendulum consists of a meter stick...Ch. 15 - SSM In Fig. 15-42, the pendulum consists of a...Ch. 15 - Suppose that a simple pendulum consists of a small...Ch. 15 - a If the physical pendulum of Fig. 15-13 and the...Ch. 15 - A physical pendulum consists of two meter-long...Ch. 15 - A performer seated on a trapeze is swinging back...Ch. 15 - A physical pendulum has a center of oscillation at...Ch. 15 - In Fig. 15-44, a physical pendulum consists of a...Ch. 15 - GO A rectangular block, with face lengths a = 35...Ch. 15 - GO The angle of the pendulum of Fig. 15-11b is...Ch. 15 - Prob. 50PCh. 15 - GO In Fig. 15-46, a stick of length L = 1.85 m...Ch. 15 - GO The 3.00 kg cube in Fig. 15-47 has edge lengths...Ch. 15 - SSM ILW In the overhead view of Fig. 15-48, a long...Ch. 15 - Prob. 54PCh. 15 - GO A pendulum is formed by pivoting a long thin...Ch. 15 - In Fig. 15-50: a 2.50 kg disk of diameter D = 42.0...Ch. 15 - The amplitude of a lightly damped oscillator...Ch. 15 - For the damped oscillator system shown in Fig....Ch. 15 - SSM WWW For the damped oscillator system shown in...Ch. 15 - The suspension system of a 2000 kg automobile sags...Ch. 15 - For Eq. 15-45, suppose the amplitude xm is given...Ch. 15 - Hanging from a horizontal beam are nine simple...Ch. 15 - A. 1000 kg car carrying four 82 kg people travels...Ch. 15 - Although California is known for earthquakes, is...Ch. 15 - A loudspeaker diaphragm is oscillating in simple...Ch. 15 - A uniform spring with k = 8600 N/m is cut into...Ch. 15 - GO In Fig. 15-51, three 10, 000 kg ore cars are...Ch. 15 - A 2.00 kg block hangs from a spring. A 300 g body...Ch. 15 - SSM In the engine of a locomotive, a cylindrical...Ch. 15 - GO A wheel is free to rotate about its fixed axle....Ch. 15 - A 50.0 g stone is attached to the bottom of a...Ch. 15 - A uniform circular disk: whose radius R is 12.6 cm...Ch. 15 - SSM A vertical spring stretches 9.6 cm when a 1.3...Ch. 15 - A massless spring with spring constant 19 N/m...Ch. 15 - A 4.00 kg block is suspended from a spring with k...Ch. 15 - A 55.0 g block oscillates in SHM on the end of a...Ch. 15 - Figure 15-53 gives the position of a 20 g block...Ch. 15 - Figure 15-53 gives the position xt of a block...Ch. 15 - Figure 15-54 shows the kinetic energy K of a...Ch. 15 - A block is in SHM on the end of a spring, with...Ch. 15 - A simple harmonic oscillator consists of a 0.50 kg...Ch. 15 - A simple pendulum of length 20 cm and mass 5.0 g...Ch. 15 - The scale of a spring balance that reads from 0 to...Ch. 15 - A 0.10 kg block oscillates back and forth along a...Ch. 15 - The end point of a spring oscillates with a period...Ch. 15 - The tip of one prong of a tuning fork undergoes...Ch. 15 - Prob. 87PCh. 15 - A block weighing 20 N oscillates at one end of a...Ch. 15 - A 3.0 kg particle is in simple harmonic motion in...Ch. 15 - A particle executes linear SHM with frequency 0.25...Ch. 15 - SSM What is the frequency of a simple pendulum 2.0...Ch. 15 - A grandfather clock has a pendulum that consists...Ch. 15 - A 4.00 kg block hangs from a spring, extending it...Ch. 15 - What is the phase constant for SMH with at given...Ch. 15 - An engineer has an odd-shaped 10 kg object and...Ch. 15 - A spider can tell when its web has captured, say,...Ch. 15 - A torsion pendulum consists of a metal disk with a...Ch. 15 - When a 20 N can is hung from the bottom of a...Ch. 15 - For a simple pendulum, find the angular amplitude...Ch. 15 - In Fig. 15-59, a solid cylinder attached to a...Ch. 15 - SSM A 1.2 kg block sliding on a horizontal...Ch. 15 - A simple harmonic oscillator consists of an 0.80...Ch. 15 - A block sliding on a horizontal frictionless...Ch. 15 - A damped harmonic oscillator consists of a block m...Ch. 15 - A block weighing 10.0 N is attached to the lower...Ch. 15 - A simple harmonic oscillator consists of a block...Ch. 15 - The vibration frequencies of atoms in solids at...Ch. 15 - Figure 15-61 shows that if we hang a block on the...Ch. 15 - The physical pendulum in Fig. 15-62 has two...Ch. 15 - A common device for entertaining a toddler is a...Ch. 15 - A 2.0 kg block executes SHM while attached to a...Ch. 15 - In Fig. 15-64, a 2500 kg demolition ball swings...Ch. 15 - The center of oscillation of a physical pendulum...Ch. 15 - A hypothetical large slingshot is stretched 2.30 m...Ch. 15 - What is the length of a simple pendulum whose full...Ch. 15 - A 2.0 kg block is attached to the end of a spring...
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- A grandfather clock has a pendulum length of 0.7 m and mass bob of 0.4 kg. A mass of 2 kg falls 0.8 m in seven days to keep the amplitude (from equilibrium) of the pendulum oscillation steady at 0.03 rad. What is the Q of the system?arrow_forwardThe amplitude of a lightly damped oscillator decreases by 3.0% during each cycle. What percentage of the mechanical energy of the oscillator is lost in each cycle?arrow_forwardWhich of the following statements is not true regarding a massspring system that moves with simple harmonic motion in the absence of friction? (a) The total energy of the system remains constant. (b) The energy of the system is continually transformed between kinetic and potential energy. (c) The total energy of the system is proportional to the square of the amplitude. (d) The potential energy stored in the system is greatest when the mass passes through the equilibrium position. (e) The velocity of the oscillating mass has its maximum value when the mass passes through the equilibrium position.arrow_forward
- A 50.0-g object connected to a spring with a force constant of 35.0 N/m oscillates with an amplitude of 4.00 cm on a frictionless, horizontal surface. Find (a) the total energy of the system and (b) the speed of the object when its position is 1.00 cm. Find (c) the kinetic energy and (d) the potential energy when its position is 3.00 cm.arrow_forwardA block of unknown mass is attached to a spring with a spring constant of 6.50 N/m and undergoes simple harmonic motion with an amplitude of 10.0 cm. When the block is halfway between its equilibrium position and the end point, its speed is measured to be 30.0 cm/s. Calculate (a) the mass of the block, (b) the period of the motion, and (c) the maximum acceleration of the block.arrow_forwardIn an engine, a piston oscillates with simple harmonic motion so that its position varies according to the expression x=5.00cos(2t+6) where x is in centimeters and t is in seconds. At t = 0, find (a) the position of the piston, (b) its velocity, and (c) its acceleration. Find (d) the period and (e) the amplitude of the motion.arrow_forward
- Consider the damped oscillator illustrated in Figure 12.16a. The mass of the object is 375 g, the spring constant is 100 N/m, and b = 0.100 N s/m. (a) Over what time interval does the amplitude drop to half its initial value? (b) What If? Over what time interval does the mechanical energy drop to half its initial value? (c) Show that, in general, the fractional rate at which the amplitude decreases in a damped harmonic oscillator is one-half the fractional rate at which the mechanical energy decreases.arrow_forwardDetermine the angular frequency of oscillation of a thin, uniform, vertical rod of mass m and length L pivoted at the point O and connected to two springs (Fig. P16.78). The combined spring constant of the springs is k(k = k1 + k2), and the masses of the springs are negligible. Use the small-angle approximation (sin ). FIGURE P16.78arrow_forwardThe total energy of a simple harmonic oscillator with amplitude 3.00 cm is 0.500 J. a. What is the kinetic energy of the system when the position of the oscillator is 0.750 cm? b. What is the potential energy of the system at this position? c. What is the position for which the potential energy of the system is equal to its kinetic energy? d. For a simple harmonic oscillator, what, if any, are the positions for which the kinetic energy of the system exceeds the maximum potential energy of the system? Explain your answer. FIGURE P16.73arrow_forward
- Show that angular frequency of a physical pendulum phy=mgrCM/I (Eq. 16.33) equals the angular frequency of a simple pendulum smp=g/, (Eq. 16.29) in the case of a particle at the end of a string of length .arrow_forwardThe mechanical energy of an undamped block-spring system is constant as kinetic energy transforms to elastic potential energy and vice versa. For comparison, explain what happens to the energy of a damped oscillator in terms of the mechanical, potential, and kinetic energies.arrow_forwardA lightweight spring with spring constant k = 225 N/m is attached to a block of mass m1 = 4.50 kg on a frictionless, horizontal table. The blockspring system is initially in the equilibrium configuration. A second block of mass m2 = 3.00 kg is then pushed against the first block, compressing the spring by x = 15.0 cm as in Figure P16.77A. When the force on the second block is removed, the spring pushes both blocks to the right. The block m2 loses contact with the springblock 1 system when the blocks reach the equilibrium configuration of the spring (Fig. P16.77B). a. What is the subsequent speed of block 2? b. Compare the speed of block 1 when it again passes through the equilibrium position with the speed of block 2 found in part (a). 77. (a) The energy of the system initially is entirely potential energy. E0=U0=12kymax2=12(225N/m)(0.150m)2=2.53J At the equilibrium position, the total energy is the total kinetic energy of both blocks: 12(m1+m2)v2=12(4.50kg+3.00kg)v2=(3.75kg)v2=2.53J Therefore, the speed of each block is v=2.53J3.75kg=0.822m/s (b) Once the second block loses contact, the first block is moving at the speed found in part (a) at the equilibrium position. The energy 01 this spring-block 1 system is conserved, so when it returns to the equilibrium position, it will be traveling at the same speed in the opposite direction, or v=0.822m/s. FIGURE P16.77arrow_forward
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