BIOLOGY
12th Edition
ISBN: 9781260169614
Author: Raven
Publisher: RENT MCG
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Textbook Question
Chapter 15, Problem 2U
What is the central dogma of molecular biology?
a. DNA is the genetic material.
b. Information passes from DNA directly to protein.
c. Information passes from DNA to RNA to protein.
d. One gene encodes only one polypeptide.
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Which of the following statements about genes is incorrect?
Select one:
O a. During fertilization, both the sperm and the ovum contribute genes to the resulting fertilized egg.
b. Genetic differences can result from changes in the DNA called mutations.
O c. Genes correspond to segments of DNA.
d. Under normal circumstances, each chromosome contains precisely one gene.
e. Many genes contain the information needed for cells to synthesize enzymes and other proteins.
The Human Genome Project was created in 1990 as an international effort began to analyze the human DNA sequence. What was the purpose of this global
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A. to develop a vaccine for diabetes
O B. for scientists to be able to eventually clone humans
C. for scientists to be able to determine which genes code for specific proteins
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a. Which gene is mutated in individuals with sickle-cell anemia?
b. What are the major symptoms of this disorder?
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d. Describe two other features of this disorder that you learned from the OMIM database and state where in the database you found this information
Chapter 15 Solutions
BIOLOGY
Ch. 15.1 - Prob. 1LOCh. 15.1 - Prob. 2LOCh. 15.1 - List the roles played by RNA in gene expression.Ch. 15.2 - Prob. 1LOCh. 15.2 - Describe the characteristics of the genetic code.Ch. 15.2 - Prob. 3LOCh. 15.3 - Prob. 1LOCh. 15.3 - Differentiate among initiation, elongation, and...Ch. 15.3 - Prob. 3LOCh. 15.4 - Prob. 1LO
Ch. 15.4 - Prob. 2LOCh. 15.4 - Explain the differences between bacterial and...Ch. 15.5 - Prob. 1LOCh. 15.5 - Prob. 2LOCh. 15.5 - Prob. 3LOCh. 15.6 - Explain why the tRNA charging reaction is critical...Ch. 15.6 - Prob. 2LOCh. 15.7 - Prob. 1LOCh. 15.7 - Prob. 2LOCh. 15.7 - Compare translation on the RER and in the...Ch. 15.9 - Prob. 1LOCh. 15.9 - Explain the nature of triplet repeat expansion.Ch. 15.9 - Prob. 3LOCh. 15 - Prob. 1DACh. 15 - Prob. 2DACh. 15 - Prob. 1IQCh. 15 - Prob. 2IQCh. 15 - Prob. 3IQCh. 15 - The experiments with nutritional mutants in...Ch. 15 - What is the central dogma of molecular biology? a....Ch. 15 - In the genetic code, one codon a. consists of...Ch. 15 - Eukaryotic transcription differs from prokaryotic...Ch. 15 - An anticodon would be found on which of the...Ch. 15 - RNA polymerase binds to a ________ to initiate...Ch. 15 - During translation, the codon in mRNA is actually...Ch. 15 - You have mutants that all affect the same...Ch. 15 - The splicing process a. occurs in prokaryotes. b....Ch. 15 - The enzyme that forms peptide bonds is called...Ch. 15 - In comparing gene expression in prokaryotes and...Ch. 15 - The codon CCA could be mutated to produce a. a...Ch. 15 - An inversion will a. necessarily cause a mutant...Ch. 15 - What is the relationship between mutations and...Ch. 15 - Prob. 1SCh. 15 - Frameshift mutations often result in truncated...Ch. 15 - Describe how each of the following mutations will...Ch. 15 - There are a number of features that are unique 10...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Even when a gene is available and its sequence of nucleotides is known, chemical studies of the protein are still required to determine: a. molecular weight of the unmodified protein. b. the amino-terminal amino acid. c. the location of disulfide bonds. d. the number of amino acids in the protein. e. whether the protein has the amino acid methionine in its sequence.arrow_forward1. State the central dogma of molecular biology. 2. What are Chargaff's rules? 3. Identify the structure of the DNA molecule. 4. Describe transcription. 5. How may mRNA be modified before it leaves the nucleus? 6. What is the genetic code? What are codons? 7. Outline the steps of translation. 8. Define mutation and mutagen. 9. List three examples of mutagens. 10. Identify three types of chromosomal alterations.arrow_forwardWhat are the most highly-conserved regions of human DNA (when compared to similar DNA sequences in closely-related animals)? A. transposons B. non-transcribed spacers C. introns D. pseudogenes E. exonsarrow_forward
- Which of the following is true about the three major classes of RNAs in the cell: mRNAs, tRNAs, and rRNAs? A. mRNAs encode polypeptide chains. B. tRNAs are structural components of the ribosome. C. rRNAs are adapter molecules that translate the information on an mRNA into a polypeptide sequence. D. mRNAs can also encode tRNAs and rRNAs.arrow_forwardWhich of the following does not conform about Genetic Engineering? * a. used recombinant DNA (rDNA) technology b. direct manipulation of only one gene c. requires complex machinery and innovative minds d. process of manually transferring genetic informationarrow_forwardWhy can the transcriptome not be used to predict the proteome with complete accuracy? a. It cannot be sequenced like the genome can be. b. The transcriptome is too dynamic to be used to make predictions. c. Not all genes are transcribed. d. Many transcripts are alternatively spliced to produce different proteins.arrow_forward
- You are working in the lab and have measured the size of mRNA that has been transcribed from a particular gene in your cell population. The length of the gene in the cells you are working, measured from the start to the stop sequence is 9000 nucleotides. When you measure the RNA, however, the size is only 3000 nucleotides. What do you think happened? O a. Three DNA base pairs code for one RNA nucleotide. b. mRNA does not contain exons. c. There must have been a deletion mutation in the DNA in these cells. Od. The poly-A tail is present in the DNA but not on the mRNA. Oe. RNA splicing occurred, so introns are removed in the mRNA.arrow_forwardThe original DNA base sequence is 5’-AGCGTTACCGT-3’; a mutation in the DNA strand results in the base sequence 5’-AGGCGTTACCGT-3’. What can you conclude about the mutation? A. It is a frameshift mutation. B. It is a silent mutation. C. It is a deleterious mutation. D. It may result in a single amino acid change in the protein being coded for by this base sequence.arrow_forwardWhen using gene therapy to treat an hereditary disease, the idea is to: A. Introduce the correct gene into the patient's DNA B. Inject the patient with a specific protein to cure the disease. C. Blood transfusions from healthy individuals. D. ntroduce mRNA molecules with the correct genetic information to the patient. E. Introduce a virus to the patient that will specifically destroy mutated cells.arrow_forward
- What did the Hershey / Chase experiments (above) demonstrate about the molecules responsible for genetic inheritance patterns in the T2 bacteriophage? A. the genetic material consists of carbohydrates, not RNA B. the genetic material consists of protein, not lipids C. the genetic material consists of DNA, not polypeptides D. the genetic material consists of protein, not DNA E. the genetic material consists of lipids, not polypeptidesarrow_forwardMost scientists consider the Human Genome Project (HGP) to be the most significant scientific project of the 21st century. Choose the statements that describe the key findings of the Human Genome Project. A. There are 23 pairs of chromosomes that make up the human genome. B. DNA exists in a double helical form. C. There are approximately three billion base pairs in the human genome. D. The human genome contains approximately 25000 genes. E. The genetic information of a cell is stored in the form of DNA.arrow_forwardWhat is the difference between orthologs and paralogs? a. Orthologs are homologous sequences; paralogs are analogous sequences. b. Orthologs are more similar than paralogs. c. Orthologs are in the same species; paralogs are in different species. d. Orthologs are in different species; paralogs are in the same species.arrow_forward
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