FUNDAMENTALS OF PHYSICS - EXTENDED
12th Edition
ISBN: 9781119773511
Author: Halliday
Publisher: WILEY
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Textbook Question
Chapter 15, Problem 29P
SSM Find the mechanical energy of a block–spring system with a spring constant of 1.3 N/cm and an amplitude of 2.4 cm.
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FUNDAMENTALS OF PHYSICS - EXTENDED
Ch. 15 - Which of the following relationships between the...Ch. 15 - An object undergoing simple harmonic motion takes...Ch. 15 - A 0.12 kg body undergoes simple harmonic motion of...Ch. 15 - What is the maximum acceleration of a platform...Ch. 15 - An automobile can be considered to be mounted on...Ch. 15 - SSM In an electric shaver, the blade moves back...Ch. 15 - A particle with a mass of 1.00 1020 kg is...Ch. 15 - SSM A loudspeaker produces a musical sound by...Ch. 15 - The position function x = 6.0 m cos3 rad/st /3...Ch. 15 - An oscillating blockspring system takes 0.75 s to...
Ch. 15 - SSM An oscillator consists of a block of mass...Ch. 15 - A simple harmonic oscillator consists of a block...Ch. 15 - SSM Two particles oscillate in simple harmonic...Ch. 15 - Two particles execute simple harmonic motion of...Ch. 15 - ILW An oscillator consists of a block attached to...Ch. 15 - GO At a certain harbor, the tides cause the ocean...Ch. 15 - A block rides on a piston a squat cylindrical...Ch. 15 - SSM WWW A block is on a horizontal surface a shake...Ch. 15 - SSM When the displacement in SHM is one-half the...Ch. 15 - SSM Find the mechanical energy of a blockspring...Ch. 15 - An oscillating blockspring system has a mechanical...Ch. 15 - ILW A 5.00 kg object on a horizontal frictionless...Ch. 15 - A 10 g particle undergoes SHM with an amplitude of...Ch. 15 - If the phase angle for a blockspring system in SHM...Ch. 15 - GO A massless spring hangs from the ceiling with a...Ch. 15 - A 95 kg solid sphere with a 15 cm radius is...Ch. 15 - SSM WWW The balance wheel of an old-fashioned...Ch. 15 - ILW A physical pendulum consists of a meter stick...Ch. 15 - Suppose that a simple pendulum consists of a small...Ch. 15 - A performer seated on a trapeze is swinging back...Ch. 15 - Prob. 50PCh. 15 - GO A pendulum is formed by pivoting a long thin...Ch. 15 - The amplitude of a lightly damped oscillator...Ch. 15 - The suspension system of a 2000 kg automobile sags...Ch. 15 - Hanging from a horizontal beam are nine simple...Ch. 15 - A. 1000 kg car carrying four 82 kg people travels...Ch. 15 - Although California is known for earthquakes, is...Ch. 15 - A loudspeaker diaphragm is oscillating in simple...Ch. 15 - A 2.00 kg block hangs from a spring. A 300 g body...Ch. 15 - SSM In the engine of a locomotive, a cylindrical...Ch. 15 - A 50.0 g stone is attached to the bottom of a...Ch. 15 - A uniform circular disk: whose radius R is 12.6 cm...Ch. 15 - SSM A vertical spring stretches 9.6 cm when a 1.3...Ch. 15 - A massless spring with spring constant 19 N/m...Ch. 15 - A 4.00 kg block is suspended from a spring with k...Ch. 15 - A 55.0 g block oscillates in SHM on the end of a...Ch. 15 - A block is in SHM on the end of a spring, with...Ch. 15 - A simple pendulum of length 20 cm and mass 5.0 g...Ch. 15 - The scale of a spring balance that reads from 0 to...Ch. 15 - A 0.10 kg block oscillates back and forth along a...Ch. 15 - The end point of a spring oscillates with a period...Ch. 15 - The tip of one prong of a tuning fork undergoes...Ch. 15 - Prob. 87PCh. 15 - A block weighing 20 N oscillates at one end of a...Ch. 15 - A 3.0 kg particle is in simple harmonic motion in...Ch. 15 - A particle executes linear SHM with frequency 0.25...Ch. 15 - SSM What is the frequency of a simple pendulum 2.0...Ch. 15 - A 4.00 kg block hangs from a spring, extending it...Ch. 15 - An engineer has an odd-shaped 10 kg object and...Ch. 15 - A spider can tell when its web has captured, say,...Ch. 15 - When a 20 N can is hung from the bottom of a...Ch. 15 - For a simple pendulum, find the angular amplitude...Ch. 15 - SSM A 1.2 kg block sliding on a horizontal...Ch. 15 - A simple harmonic oscillator consists of an 0.80...Ch. 15 - A block sliding on a horizontal frictionless...Ch. 15 - A damped harmonic oscillator consists of a block m...Ch. 15 - Prob. 105PCh. 15 - Prob. 106PCh. 15 - Prob. 107PCh. 15 - Prob. 108PCh. 15 - Prob. 109PCh. 15 - Prob. 110PCh. 15 - Prob. 111P
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- Use the data in Table P16.59 for a block of mass m = 0.250 kg and assume friction is negligible. a. Write an expression for the force FH exerted by the spring on the block. b. Sketch FH versus t.arrow_forwardA 50.0-g object connected to a spring with a force constant of 35.0 N/m oscillates with an amplitude of 4.00 cm on a frictionless, horizontal surface. Find (a) the total energy of the system and (b) the speed of the object when its position is 1.00 cm. Find (c) the kinetic energy and (d) the potential energy when its position is 3.00 cm.arrow_forwardThe amplitude of a lightly damped oscillator decreases by 3.0% during each cycle. What percentage of the mechanical energy of the oscillator is lost in each cycle?arrow_forward
- If a car has a suspension system with a force constant of 5.00104 N/m , how much energy must the car’s shocks remove to dampen an oscillation starting with a maximum displacement of 0.0750 m?arrow_forwardA grandfather clock has a pendulum length of 0.7 m and mass bob of 0.4 kg. A mass of 2 kg falls 0.8 m in seven days to keep the amplitude (from equilibrium) of the pendulum oscillation steady at 0.03 rad. What is the Q of the system?arrow_forwardConsider the data for a block of mass m = 0.250 kg given in Table P16.59. Friction is negligible. a. What is the mechanical energy of the blockspring system? b. Write expressions for the kinetic and potential energies as functions of time. c. Plot the kinetic energy, potential energy, and mechanical energy as functions of time on the same set of axes. Problems 5965 are grouped. 59. G Table P16.59 gives the position of a block connected to a horizontal spring at several times. Sketch a motion diagram for the block. Table P16.59arrow_forward
- Refer to the problem of the two coupled oscillators discussed in Section 12.2. Show that the total energy of the system is constant. (Calculate the kinetic energy of each of the particles and the potential energy stored in each of the three springs, and sum the results.) Notice that the kinetic and potential energy terms that have 12 as a coefficient depend on C1 and 2 but not on C2 or 2. Why is such a result to be expected?arrow_forwardConsider the damped oscillator illustrated in Figure 12.16a. The mass of the object is 375 g, the spring constant is 100 N/m, and b = 0.100 N s/m. (a) Over what time interval does the amplitude drop to half its initial value? (b) What If? Over what time interval does the mechanical energy drop to half its initial value? (c) Show that, in general, the fractional rate at which the amplitude decreases in a damped harmonic oscillator is one-half the fractional rate at which the mechanical energy decreases.arrow_forwardA block of mass m = 2.00 kg is attached to a spring of force constant k = 500 N/m as shown in Figure P7.15. The block is pulled to a position xi = 5.00 cm to the right of equilibrium and released from rest. Find the speed the block has as it passes through equilibrium if (a) the horizontal surface is frictionless and (b) the coefficient of friction between block and surface is k = 0.350. Figure P7.15arrow_forward
- A lightweight spring with spring constant k = 225 N/m is attached to a block of mass m1 = 4.50 kg on a frictionless, horizontal table. The blockspring system is initially in the equilibrium configuration. A second block of mass m2 = 3.00 kg is then pushed against the first block, compressing the spring by x = 15.0 cm as in Figure P16.77A. When the force on the second block is removed, the spring pushes both blocks to the right. The block m2 loses contact with the springblock 1 system when the blocks reach the equilibrium configuration of the spring (Fig. P16.77B). a. What is the subsequent speed of block 2? b. Compare the speed of block 1 when it again passes through the equilibrium position with the speed of block 2 found in part (a). 77. (a) The energy of the system initially is entirely potential energy. E0=U0=12kymax2=12(225N/m)(0.150m)2=2.53J At the equilibrium position, the total energy is the total kinetic energy of both blocks: 12(m1+m2)v2=12(4.50kg+3.00kg)v2=(3.75kg)v2=2.53J Therefore, the speed of each block is v=2.53J3.75kg=0.822m/s (b) Once the second block loses contact, the first block is moving at the speed found in part (a) at the equilibrium position. The energy 01 this spring-block 1 system is conserved, so when it returns to the equilibrium position, it will be traveling at the same speed in the opposite direction, or v=0.822m/s. FIGURE P16.77arrow_forwardCheck Your Understanding Identify an object that undergoes uniform circular motion. Describe how you could trace the SHM of this object.arrow_forwardA blockspring system oscillates with an amplitude of 3.50 cm. The spring constant is 250 N/m and the mass of the block is 0.500 kg. Determine (a) the mechanical energy of the system, (b) the maximum speed of the block, and (c) the maximum acceleration.arrow_forward
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