Traffic and Highway Engineering
5th Edition
ISBN: 9781305156241
Author: Garber, Nicholas J.
Publisher: Cengage Learning
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Chapter 15, Problem 18P
To determine
The station of PT.
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Two parallel roads 30m apart are to be connected by a reversed curve with equal radii at PC and PT. The length of the common tangent is 160m. The stationing of PC is 14+285a. Find the radius of the reversed curveb. Find the length of the curve from PC to PTc. Find the stationing of PT
An arterial road is to be connected to a frontage road by a reverse curve with parallel tangents. The distance between the centerline of the two tangent section is 18 m. The PC of the curve is located at station (38+125.31) and the central angle of each of the component curves is 25°.
Determine the radius of each of the two curves in the reverse curve if they have the same radius and central angle.
Determine the station of PT.
Determine the maximum speed to be allowed on this curve if the superelevation rate is 8%.
Two tangents to be connected by a simple curve have an intersection angle of 55° 30'. The curve is to pass through a
point "P" which lies on a line through the P.I. that makes an angle of 20° with the forward tangent. If "P" is 30 m.
from the P.I., what should the radius of the required curve?
Answer:
R= 160. 94 m.
Chapter 15 Solutions
Traffic and Highway Engineering
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- Two tangents adjacent to each other having bearings N 65 E and S 81 E meet at station 11+150. If the radius of the simple curve connecting these two tangents is 251 m, determine the following A. Tangent Distance B. Length of curve C. Station of PTarrow_forwardTwo tangents intersect at V at station 12+705.84. The angle of intersection is 32°. The stationing of PC is 12+630. Without changing the location of PC and the sharpness of the curve, it is desired to shorten the length of curve by 50 meters. Determine the stationing of the new point of intersection (PI) and new point of tangency (PT).arrow_forwardA simple curve has a radius of 120m and an angle of intersection of 36 degrees. A new curve was designed such that the new forward tangent is moved out at a perpendicular distance of 12m. Without changing the directions of the tangents and the position of the PC remains the same, determine the following: Radius of the new curve in meters. Length of the new curve in meters Stationing of the new PT if the PC is as STA 10+020arrow_forward
- A compound curve passes through a common tangent BC having a length of 400m. The first curve passing through the PC has a degree of curve of 4 ̊ and a central angle of 40 ̊. If the central angle of the second curve is 30 ̊, compute the degree of curve of the second curve.arrow_forwardThe tangent through PC and PT intersects at Station 100+280, the length of chord from PC to PT is 80m, if the angle of intersection of tangents is 40°. a)Determine the Degree of Curve. b)Determine the Stationing of PT.arrow_forwardPROBLEM 7: Two tangents converge at an angle of 40. The direction of the second tangent is due east. The distance of the P.C. from the second tangent is 150m. The bearing of the common tangent is S 40° E. Compute the following: a. Central angle of the first curve b. If a reversed curve is to connect these two tangents, determine the common radius of the curve. c. The stationing of the P.T. if P.C. is at sta. 11+820arrow_forward
- A compound curve has a central angle of 40deg. and radius 280m. The second curve has a degree of curve of 5deg. and central angle of 28deg. (a) Compute the length of the common tangent.arrow_forwardA. Reversed curve with diverging tangents is to pass through three lines to form a center line of a proposed road. the first line AB has a bearing of N 88° E. and a distance of 125 m., BC has a bearing of N 60° E and a distance of 350 m., while on that of CD has a bearing of S 40° E and a distance of 305 m. If the first tangent has a distance of only % of the common tangent measured from the point of intersection of the first curve determine the radius of the curves and station of PT if PC is 12+ 350 Pls answer ASAP ( Nearest 3 decimal places)arrow_forwardA reverse curve with diverging tangent is to be designed for a proposed highway as illustrated below. The reverse curve is composed of one compound curve, from point A to C, and one simple curve, from point C to D. Point A is located at the Point of Curvature having Station 12+808.35, point B is located at the Point of Compound Curve, point C is located at the Point of Tangency. The back tangent of the reverse curve is having an located at the Point of Reverse Curve, and point D azimuth of 388.5 degrees and the forward tangent is having an azimuth of 748.8 degrees. The common tangent for the reverse curve has an azimuth of 313.1 degrees from south. It has been found out that the long chord of curve A to C is thrice the value of the chord in curve C to D. The common tangent of the curve A to C is having an azimuth of 254.1 degrees from south and the chord of curve C to D is 161.3m long.arrow_forward
- Two tangents converge at an angle of 30°, the direction of the second tangent is due east. The vertical distance of the PC from the second tangent is 116.50. The bearing of the common tangent is S 40° E. a) Compute the central angle of the first curve. b) If a reversed curve is to connect these two tangents, determine the common radius of the curve. c) Compute the stationing of the PT if PC is located at 10+620.arrow_forward1. Two roads with azimuths of due east are to be connected using a reversed curve. The PC is at the lower tangent and the PT is at the upper tangent. The distance between two centers is 2256.85 m and the perpendicular distance of the two roads is 25 m apart. The stationing of the point of intersection of the first curve is 12+022.022. The reversed curve has a common radius, R.a) Compute the long chord of the curve.b) Compute the stationing of the point where the curve starts to reverse in direction.c) Compute the stationing of the point where the reversed curve end.arrow_forwardTwo parallel tangents have directions of due east and are 200 m. apart, are connected by a reverse curve having equal radius of 800 m. The P.C. of the curve is on the upper tangent while the P.T. is at the lower tangent. If the horizontal distance parallel to the tangent from the P.C. to the P.T. of the reverse curve is 800 m.a. Compute the distance of the intermediate tangent between the curves.b. Compute the distance between the centers of the reversed curve.c. Compute the stationing of P.T. if sta. of the P.C. is 10 + 020.40.arrow_forward
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