Traffic and Highway Engineering
5th Edition
ISBN: 9781305156241
Author: Garber, Nicholas J.
Publisher: Cengage Learning
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Chapter 15, Problem 16P
To determine
The radius of the curve and the angle set out from
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In the figure shown AB = 103.20m with A at station 10 + 158.93. The angle VAC is 15°21’ and
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23.97 meters away from
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Traffic and Highway Engineering
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- Determine the length of chord from PC to the PT of a compound curve. if the curve laid out given the following data: PC – PCC = 400 m R1 = 700 m PCC – PT = 200 m R2 = 200 Stationing of the point of intersection of the tangents is 10 + 350arrow_forward3 Four tangents having an angle of intersections shown is to be connected by three simple curves having different radius with the last curve w/C is s times sharper than the first curve. Find the radius of each curve. AB = 300m, BC = 200m. k T₁ + T₂ P.C. 7₂ R₂ R₁ R₂ R B 50° 700 P.Tarrow_forwardThe compound curve that was laid out has a long chord distance of 562.31 from its beginning to end. The tangents of the first and second curves form an angle of 22° and 17°, respectively, with this long chord. Find the following if the common tangent is parallel to the long chord: a. Length of the common tangent of the compound curve using arc basis. b. Station of PC if the station P.I. is at 12+765.275. c. Stationing at the endpoint of the compound curve.arrow_forward
- QUESTION 2 The tangent thru the PC has a direction due to North; and the tangent through the PT has a bearing of N 50° E. It has a radius of 200 m. Stationing of PC is 12+060. a. Compute the tangent distance of the curve. Answer: T= b. Compute the long chord of the curve. Answer: Lc = m m c. A line is drawn from the center of the curve (at the central angle) and intersects the curve at point B. This line, when extended, makes an angle of 62° with the tangent thru PC. What is the stationing of point B? Answer: Sta. B = Note: Unit has been provided after the blank space. No need to indicate units on your answer.arrow_forwardThe tangent thru the PC has a direction due to North; and the tangent through the PT has a bearing of N 50° E. It has a radius of 200 m. Stationing of PC is 12+060. % a. Compute the tangent distance of the curve. Answer: T= [tangent] m b. Compute the long chord of the curve. Answer: Lc = [Lchord] m c. A line is drawn from the center of the curve (at the central angle) and intersects the curve at point B. This line, when extended, makes an angle of 62° with the tangent thru PC. What is the stationing of point B? Answer: Sta. B = [StaB]arrow_forwardA curve having tangents of UV and VW intersects at point V. UV and VW has an azimuth (from south) of 165° and 215° respectively. U is at 10+340.26. The degree of the curve is 4°. Determine: Middle ordinate of the curve A line passes through the center of the curve to the curve itself at point X, then to UV, making an angle of 60°. What is the station of point X. Draw and plot the curve. Compute all of the necessary elements of the curve. Include the proper units/dimensions and round-off the answers to three decimal places.arrow_forward
- Two tangents AB and BC intersect at an angle of 24.b°. A point P is located 21.13m from point Band has a perpendicular distance of 2.69m from line AB. Calculate the radius of the simple curveconnecting the two tangents and passing point P.arrow_forwardThe central angles of a compound curve are 30° and 40° respectively. In addition, the radii of the curves are 400 m and 240 m respectively. PC is at 0+999. a. What is the length of the common tangent? b. What is the station of PCC? c. What is the station of PT? Draw and plot the curve. Compute all of the necessary elements of the curve. Include the proper units/dimensions and round-off the answers to 3 decimal places.arrow_forwardIn a compound curve, the line connecting the P.l. at point V and the PC is an angle bisector. VA is 270 meters and BV =90 m. The stationing of A is 6+421 and that of B is 6+721. Point A is along the tangent passing through PC while point B is along the tangent passing through PT. The PC is also along AB. a. Compute the radius of the first curve b. Compute the radius of the second curve c. Determine the length of the line connecting PC and PT.arrow_forward
- On a rail road line, two tangents that intersect at station 10 + 243 so as to form an angle of 36°28′ are to be connected by a compound curve consisting of two simple curves. The simple curve beginning at the P.C. which is at station 10 + 163 is to be 4° curve whose degree is based on a 20m chord and is to have a central angle of 17°. Using chord basis:a. What should be the radius of the other simple curve that ends at the P.T.?b. Compute the stationing of P.C.C.arrow_forwardA compound curve has two simple curves. The radius of first simple is 30 meters and its angle of intersection is 18 degrees. The radius of second simple is 10 meters and its angle of intersection is 38 degrees. What is the length of the common tangent of the compound curve? What is the stationing of PT of the compound curve? The stationing of PI of the first simple curve is 1+000.arrow_forwardThe angle of intersection of a 5 is drawn intersecting at an angle of 60 simple curve is 50 °. From the center of the curve, a line °the tangent thru P.T. and passing thru a point X on the curve. The stationing of P.T. is 100+ 080. Determine the following: a. The length of the curve from X to P.T., b. Stationing of point Xarrow_forward
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