Chapter 15, Problem 15.18P

(a)

Interpretation Introduction

Interpretation:

To develop Rule of thumb: Solubility of a solid in a liquid solvent increases with increasing T.

Concept Introduction:

The given rule of thumb is based on case II binary SLE behavior.

Let the solid be pure species 1 and the Liquid solvent be species 2.

Then $x_1={\psi }_1$and${\psi }_1=\exp \frac{\Delta H_1^{sl}}{R{T}_{m1}}\left(\frac{T-T_{m1}}{T}\right)$

(b)

Interpretation Introduction

Interpretation:

To develop Rule of thumb: Solubility of a solid in a liquid solvent is independent of the identity of the solvent species

Concept Introduction:

The given rule of thumb is based on case II binary SLE behavior.

Let the solid be pure species 1 and the Liquid solvent be species 2.

Then $x_1={\psi }_1$and${\psi }_1=\exp \frac{\Delta H_1^{sl}}{R{T}_{m1}}\left(\frac{T-T_{m1}}{T}\right)$

(c)

Interpretation Introduction

Interpretation:

To develop Rule of thumb: Of 2 solids with roughly the same heat of fusion, that solid with the lower melting point is the more soluble in a given liquid solvent at a given T

Concept Introduction:

The given rule of thumb is based on case II binary SLE behavior.

Let the solid be pure species 1 and the Liquid solvent be species 2.

Then $x_1={\psi }_1$and${\psi }_1=\exp \frac{\Delta H_1^{sl}}{R{T}_{m1}}\left(\frac{T-T_{m1}}{T}\right)$

(d)

Interpretation Introduction

Interpretation:

To develop Rule of thumb: Of 2 solids with similar melting points, that solid with the smaller heat of fusion is the more soluble in a given liquid solvent at a given T

Concept Introduction:

The given rule of thumb is based on case II binary SLE behavior.

Let the solid be pure species 1 and the Liquid solvent be species 2.

Then $x_1={\psi }_1$and${\psi }_1=\exp \frac{\Delta H_1^{sl}}{R{T}_{m1}}\left(\frac{T-T_{m1}}{T}\right)$