Chapter 14.7, Problem 22WE

To determine

To find : the rule for $S^{-1}$ .

Answer to Problem 22WE

The $S^{-1}\left(x,y\right)=\left(x+3,y+1\right)$ .

Explanation of Solution

Given information: $S:\left(x,y\right)\to \left(x-3,y-1\right)$ .

Calculation :

  $\begin{array}{l}{S}^{-1}\left(S\left(t,z\right)\right)\\ \Rightarrow \left(t,z\right)\\ \Rightarrow S^{-1}\left(t-3,z-1\right)=\left(t,z\right)\\ \Rightarrow S^{-1}\left(x,y\right)=\left(x+3,y+1\right)\end{array}$