Chapter 14, Problem 9CPE

To determine

Tofind: the value of $R_x\circ {\Re }_{O.90}:\left(-2,5\right)\to \left(\right)$ .

Answer to Problem 9CPE

The value is $R_x\circ {\Re }_{O.90}:\left(-2,5\right)\to \left(-5,2\right)$ .

Explanation of Solution

Given information:

the $O$ is the origin.

Calculation: to find the value, after rotation of ${90}^{\circ }$ , switch the coordinates with sign change,

$R_x\circ {\Re }_{O.90}:\left(-2,5\right)\to \left(-5,2\right)$