Geometry For Enjoyment And Challenge
Geometry For Enjoyment And Challenge
91st Edition
ISBN: 9780866099653
Author: Richard Rhoad, George Milauskas, Robert Whipple
Publisher: McDougal Littell
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Chapter 14.4, Problem 2PSA

a.

To determine

To construct the segment whose length is the sum of AB and CD.

a.

Expert Solution
Check Mark

Explanation of Solution

Given:

The two segments AB and CD with AB>CD .

Calculation:

The following is the construction-

  Geometry For Enjoyment And Challenge, Chapter 14.4, Problem 2PSA , additional homework tip  1

b.

To determine

To construct the segment whose length is the difference of AB and CD.

b.

Expert Solution
Check Mark

Explanation of Solution

Given:

The two segments AB and CD with AB>CD .

Calculation:

The following is the construction-

  Geometry For Enjoyment And Challenge, Chapter 14.4, Problem 2PSA , additional homework tip  2

c.

To determine

To locate the midpoint of AB.

c.

Expert Solution
Check Mark

Explanation of Solution

Given:

The two segments AB and CD with AB>CD .

Calculation:

The following is the construction of mid-point-

  Geometry For Enjoyment And Challenge, Chapter 14.4, Problem 2PSA , additional homework tip  3

d.

To determine

To construct the equilateral triangle whose sides are congruent to CD.

d.

Expert Solution
Check Mark

Explanation of Solution

Given:

The two segments AB and CD with AB>CD .

Calculation:

The following is the construction of equilateral triangle-

  Geometry For Enjoyment And Challenge, Chapter 14.4, Problem 2PSA , additional homework tip  4

e.

To determine

To construct the isosceles triangle making base congruent to CD and leg congruent to AB.

e.

Expert Solution
Check Mark

Explanation of Solution

Given:

The two segments AB and CD with AB>CD .

Calculation:

The following is the construction of isosceles triangle-

  Geometry For Enjoyment And Challenge, Chapter 14.4, Problem 2PSA , additional homework tip  5

f.

To determine

To construct the square congruent to AB.

f.

Expert Solution
Check Mark

Explanation of Solution

Given:

The two segments AB and CD with AB>CD .

Calculation:

The following is the construction of square each side is 5 unit-

  Geometry For Enjoyment And Challenge, Chapter 14.4, Problem 2PSA , additional homework tip  6

g.

To determine

To construct the circle whose diameter is congruent to CD.

g.

Expert Solution
Check Mark

Explanation of Solution

Given:

The two segments AB and CD with AB>CD .

Calculation:

The following is the construction of circle of radius =6 unit.

  Geometry For Enjoyment And Challenge, Chapter 14.4, Problem 2PSA , additional homework tip  7

Chapter 14 Solutions

Geometry For Enjoyment And Challenge

Ch. 14.1 - Prob. 11PSBCh. 14.1 - Prob. 12PSBCh. 14.1 - Prob. 13PSBCh. 14.1 - Prob. 14PSBCh. 14.1 - Prob. 15PSBCh. 14.1 - Prob. 16PSBCh. 14.1 - Prob. 17PSBCh. 14.1 - Prob. 18PSBCh. 14.1 - Prob. 19PSBCh. 14.1 - Prob. 20PSBCh. 14.1 - Prob. 21PSBCh. 14.1 - Prob. 22PSBCh. 14.1 - Prob. 23PSBCh. 14.1 - Prob. 24PSCCh. 14.1 - Prob. 25PSCCh. 14.1 - Prob. 26PSCCh. 14.1 - Prob. 27PSCCh. 14.1 - Prob. 28PSCCh. 14.1 - Prob. 29PSCCh. 14.1 - Prob. 30PSCCh. 14.2 - Prob. 1PSACh. 14.2 - Prob. 2PSACh. 14.2 - Prob. 3PSACh. 14.2 - Prob. 4PSACh. 14.2 - Prob. 5PSBCh. 14.2 - Prob. 6PSBCh. 14.2 - Prob. 7PSBCh. 14.2 - Prob. 8PSBCh. 14.2 - Prob. 9PSBCh. 14.2 - Prob. 10PSBCh. 14.2 - Prob. 11PSCCh. 14.2 - Prob. 12PSCCh. 14.2 - Prob. 13PSCCh. 14.2 - Prob. 14PSCCh. 14.2 - Prob. 15PSCCh. 14.2 - Prob. 16PSCCh. 14.2 - Prob. 17PSCCh. 14.3 - Prob. 1PSACh. 14.3 - Prob. 2PSACh. 14.3 - Prob. 3PSACh. 14.3 - Prob. 4PSACh. 14.3 - Prob. 5PSACh. 14.3 - Prob. 6PSACh. 14.3 - Prob. 7PSACh. 14.3 - Prob. 8PSBCh. 14.3 - Prob. 9PSBCh. 14.3 - Prob. 10PSBCh. 14.3 - Prob. 11PSBCh. 14.3 - Prob. 12PSBCh. 14.3 - Prob. 13PSBCh. 14.3 - Prob. 14PSBCh. 14.3 - Prob. 15PSCCh. 14.3 - Prob. 16PSCCh. 14.3 - Prob. 17PSCCh. 14.3 - Prob. 18PSCCh. 14.3 - Prob. 19PSCCh. 14.3 - Prob. 20PSCCh. 14.3 - Prob. 21PSDCh. 14.4 - Prob. 1PSACh. 14.4 - Prob. 2PSACh. 14.4 - Prob. 3PSACh. 14.4 - Prob. 4PSACh. 14.4 - Prob. 5PSACh. 14.4 - Prob. 6PSBCh. 14.4 - Prob. 7PSBCh. 14.4 - Prob. 8PSBCh. 14.4 - Prob. 9PSBCh. 14.4 - Prob. 10PSBCh. 14.4 - Prob. 11PSBCh. 14.4 - Prob. 12PSBCh. 14.4 - Prob. 13PSBCh. 14.4 - Prob. 14PSCCh. 14.4 - Prob. 15PSCCh. 14.4 - Prob. 16PSCCh. 14.4 - Prob. 17PSCCh. 14.4 - Prob. 18PSCCh. 14.4 - Prob. 19PSDCh. 14.5 - Prob. 1PSACh. 14.5 - Prob. 2PSACh. 14.5 - Prob. 3PSACh. 14.5 - Prob. 4PSACh. 14.5 - Prob. 5PSACh. 14.5 - Prob. 6PSACh. 14.5 - Prob. 7PSACh. 14.5 - Prob. 8PSACh. 14.5 - Prob. 9PSACh. 14.5 - Prob. 10PSACh. 14.5 - Prob. 11PSACh. 14.5 - Prob. 12PSBCh. 14.5 - Prob. 13PSBCh. 14.5 - Prob. 14PSBCh. 14.5 - Prob. 15PSBCh. 14.5 - Prob. 16PSBCh. 14.5 - Prob. 17PSBCh. 14.5 - Prob. 18PSBCh. 14.5 - Prob. 19PSBCh. 14.5 - Prob. 20PSCCh. 14.5 - Prob. 21PSCCh. 14.5 - Prob. 22PSCCh. 14.5 - Prob. 23PSCCh. 14.5 - Prob. 24PSCCh. 14.5 - Prob. 25PSCCh. 14.5 - Prob. 26PSDCh. 14.6 - Prob. 1PSACh. 14.6 - Prob. 2PSACh. 14.6 - Prob. 3PSACh. 14.6 - Prob. 4PSACh. 14.6 - Prob. 5PSACh. 14.6 - Prob. 6PSACh. 14.6 - Prob. 7PSACh. 14.6 - Prob. 8PSBCh. 14.6 - Prob. 9PSBCh. 14.6 - Prob. 10PSBCh. 14.6 - Prob. 11PSBCh. 14.6 - Prob. 12PSBCh. 14.6 - Prob. 13PSBCh. 14.6 - Prob. 14PSBCh. 14.6 - Prob. 15PSBCh. 14.6 - Prob. 16PSBCh. 14.6 - Prob. 17PSCCh. 14.6 - Prob. 18PSCCh. 14.6 - Prob. 19PSCCh. 14.6 - Prob. 20PSCCh. 14.6 - Prob. 21PSCCh. 14.6 - Prob. 22PSDCh. 14.6 - Prob. 23PSDCh. 14.6 - Prob. 24PSECh. 14 - Prob. 1RPCh. 14 - Prob. 2RPCh. 14 - Prob. 3RPCh. 14 - Prob. 4RPCh. 14 - Prob. 5RPCh. 14 - Prob. 6RPCh. 14 - Prob. 7RPCh. 14 - Prob. 8RPCh. 14 - Prob. 9RPCh. 14 - Prob. 10RPCh. 14 - Prob. 11RPCh. 14 - Prob. 12RPCh. 14 - Prob. 13RPCh. 14 - Prob. 14RPCh. 14 - Prob. 15RPCh. 14 - Prob. 16RPCh. 14 - Prob. 17RPCh. 14 - Prob. 18RPCh. 14 - Prob. 19RPCh. 14 - Prob. 20RPCh. 14 - Prob. 21RPCh. 14 - Prob. 22RPCh. 14 - Prob. 23RPCh. 14 - Prob. 24RPCh. 14 - Prob. 25RPCh. 14 - Prob. 26RPCh. 14 - Prob. 27RPCh. 14 - Prob. 28RPCh. 14 - Prob. 29RPCh. 14 - Prob. 30RPCh. 14 - Prob. 31RPCh. 14 - Prob. 32RP

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