Chapter 14.3, Problem 14PSB

To determine

To find the coordinates of the centroid.

Answer to Problem 14PSB

  $\left(5,4\right)$

Explanation of Solution

Given:

The triangle is PQR with $P=(0,0),Q=(5,12)$ and $R=(10,0)$

Calculation:

The centroid of the trianglePQR can be found as follows-

  $\begin{array}{l}C(x,y)=\left(\frac{x_1+x_2+x_3}{3},\frac{y_1+y_2+y_3}{3}\right)\\ C(x,y)=\left(\frac{0+5+10}{3},\frac{0+12+0}{3}\right)\\ C(x,y)=\left(5,4\right)\end{array}$