
To explain: why the given center and radius values are incorrect.

Answer to Problem 62AYU
The given center and radius values are incorrect.
The correct center is (−3,2) .
Explanation of Solution
Given:
(x+3)2+(y−2)2=16
Center = (3,−2)
Radius = 4
First compare the equation (x+3)2+(y−2)2=16 to the standard form of the equation of a circle with radius r and center (h,k) ;
(x−h)2+(y−k)2=r2
The comparison yields information about the circle.
h=−3,k=2 and r=4 .
Therefore, the center is (3,−2) and radius is 4 units.
Hence, the center (3,−2) of equation (x+3)2+(y−2)2=16 is incorrect. The correct center is (−3,2) .
Conclusion:
Hence,the given center and radius values are incorrect.
The correct center is (−3,2) .
Chapter 1 Solutions
Precalculus
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