Biological Science (7th Edition)
7th Edition
ISBN: 9780134678320
Author: Scott Freeman, Kim Quillin, Lizabeth Allison, Michael Black, Greg Podgorski, Emily Taylor, Jeff Carmichael
Publisher: PEARSON
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Chapter 14, Problem 4TYK
Example Problem Two black female mice are crossed with a brown male. In several litters, female I produced 9 black offspring and 7 brown; female II produced 57 black offspring. What deductions can you make about the inheritance of black and brown coat color in mice? What are the genotypes of the parents in this case?
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Students have asked these similar questions
Miniature wings (Xm) in Drosophila result from an X-linked allele that is recessive to
the allele for long wings (X*). Give the genotypes of the parents in the following
cross:
Male parent Female parent Male offspring Female offspring
231 long,
250 miniature
Long
Long
560 long
O male: Xm/Y and female X* /X*
male: X* / Y and female Xm /x
O male: X* /Y and female X* /X*
male: Xm/Y and female Xm /x+
EXAMPLE PROBLEM Two black female mice are crossed with a brown male. In several litters, female I produced 9 black offspring and 7 brown; female II produced 57 black offspring. What deductions can you make about the inheritance of black and brown coat color in mice? What are the genotypes of the parents? Dominance and recessive describe which of two possible phenotypes are exhibited when two different alleles occur in the same individual.
In Drosophila fruit flies, the genes for warped wings (dwp), rumpled bristles (rmp), and pallid wings (pld) are linked. A trihybrid female for all three allleles is crossed with homozygous recessive male for all three alleles and the offspring obtained showed the following phenotypes:
3 pld rmp dwp
428 pld rmp +
427 + + dwp
48 + rmp +
47 pld + dwp
23 pld + +
2 + + +
22 + rmp dwp
What is the order and map distance between these three alleles?
Chapter 14 Solutions
Biological Science (7th Edition)
Ch. 14 - 1. The genes for the trails that Mendel worked...Ch. 14 - Example Problem Two black female mice are crossed...Ch. 14 - Prob. 5TYKCh. 14 - Prob. 6TYPSSCh. 14 - Prob. 7TYPSSCh. 14 - 11. In garden peas, yellow seeds (Y) are dominant...Ch. 14 - Prob. 9TYPSSCh. 14 - The smooth feathers on the back of the neck in...Ch. 14 - SOCIETY As a genetic counselor, you advise couples...Ch. 14 - 15. Suppose you are heterozygous for two genes...
Ch. 14 - Suppose a woman with blood type O married a man...Ch. 14 - Prob. 14TYPSSCh. 14 - Society Two mothers give birth to sons at the same...Ch. 14 - Prob. 16TYPSSCh. 14 - QUANTITATIVE Recall that hemophilia is an X-linked...Ch. 14 - Prob. 18PIATCh. 14 - Given the pedigree, what is the most likely mode...Ch. 14 - Prob. 20PIATCh. 14 - QUANTITATIVE If the son with ALD in the third...Ch. 14 - Prob. 22PIATCh. 14 - Prob. 23PIAT
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- In mice, the allele C for colored fur is dominant over the allele c for white fur, and the allele V for normal behavior is dominant over the allele v for waltzing behavior, a form of discoordination. Give the genotypes of the parents in each of the following crosses: (a) Colored, normal mice mated with white, normal mice produced 29 colored, normal and 10 colored, waltzing progeny. (b) Colored, normal mice mated with colored, normal mice produced 38 colored, normal, 15 colored, waltzing, 11 white, normal, and 4 white, waltzing progeny. (c) Colored, normal mice mated with white, waltzing mice produced 8 colored, normal, 7 colored, waltzing, 9 white, normal, and 6 white, waltzing progeny.arrow_forwardPart 2 Spotty and Cutie have puppies and 50% of the puppies are unaffected for both traits (not blind and not BHFD). What is Spotty's genotype? bbDD bbdd BBDd BbDd BbDD BBddarrow_forwardThe recessive allele s causes Drosophila to have small wings, and the s+ allele causes normal wings. This gene is known to be X linked. If a small-winged male is crossed with a homozygous wild-type female, what ratio of normal to small-winged flies can be expected in each sex in the F1? If F1 flies are intercrossed, what F2 progeny ratios are expected? What progeny ratios are predicted if F1 females are backcrossed with their father?arrow_forward
- You are doing a cross with Drosophila using the following two traits. Curly wings is dominant over straight wings, and round eyes is dominant over elliptical eyes. You cross a female fly that is known to be heterozygous for both genes with a male that is heterozygous for the wing gene but has elliptical eyes. This cross produces 74 flies with curly wings and round eyes, 61 with curly wings and elliptical eyes, 24 with straight wings and round eyes, and 21 with straight wing and elliptical eyes. Calculate the expected phenotype ratios for this cross, then use the chi-square test to see if the observed data are consistent with the expected numbers.arrow_forwardtype P = n! (p)* (q)"* х! (n - х)! Practice Problem: You cross a true-breeding pea plant with red flowers to a true-breeding pea plant with white flowers. All of your offspring have red flowers. Which gene is dominant? Why? What is the genotype of your offspring? You then cross the offspring to each other. What ratio do you expect? Why? You count 1000 plants and look at their flowers. Your results are as follows: 740 red 260 white Does this follow a simple Mendelian inheritance pattern? Why or why not? DADT 2 MEA SUDI ND D LUT IONSarrow_forwardGiven that loci A and B in Drosophila are sex-linked and 20 map units apart, what phenotypic frequencies would you expect in male and female offspring resulting from the following crosses? (Assume that A and B are dominant to a and b, respectively.) a) AaBb (dominant alleles on same chromosome) female x ab/Y male b.) AaBb (dominant alleles on homologs) female x ab/Y male c) aabb female x AB/Y male (no crossing over in male Drosophilaarrow_forward
- With regard to scurs in cattle ( a sex influenced trait) a cow with no scurs whose mother had scurs had offspring with a bull with scurs whose father had no scurs. What are their probabilities of having the following combinations?a. their first offspring will not have scursb. their first offspring will be a male with no scursc. their first three offspring will be females with no scurs step by step explain in details please!!!!arrow_forwardIn the Manx tailless phenotype of cats, the tailless phenotype is caused by the mutation ML and is inherited as an autosomal dominant trait. Homozygotes for ML are lethal, and do not survive to birth. A breeder mates a Manx tailless male with a Manx tailless female. The female is now pregnant with a litter of 3 kittens. What is the probability that all the kittens born will be tailless? 0.012 0.125 0.04 0.20 0.30arrow_forwardIn Drosophila, the recessive allele for forked bristles is X-linked, and the recessive allele for purple eyes is autosomal. The wild- type alleles are for straight bristles and red eyes, respectively. A female heterozygous for both pairs is mated with a male with forked bristles and purple eyes. What percentage of the males will have forked bristles and purple eyes? 25% O 50% O 75% 100%arrow_forward
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