World of Chemistry, 3rd edition
World of Chemistry, 3rd edition
3rd Edition
ISBN: 9781133109655
Author: Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher: Brooks / Cole / Cengage Learning
Question
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Chapter 14, Problem 2STP
Interpretation Introduction

Interpretation: The reason for difference in strength of intermolecular forces between ammonia and methane needs to be explained.

Concept introduction: When polar molecules with dipole moments are put together, they orient themselves in such a way that molecules with dipole moments can attract each other so that the positive and negative portions of the molecules come close to each other.

The forces that exist among non-polar molecules are called London dispersion forces. Atoms can develop a temporary dipole moment due the distortion of symmetrical charge distribution as the electrons move around the nucleus. This instantaneous dipole generated in turn induces a similar dipole in a neighboring atom.

Expert Solution & Answer
Check Mark

Answer to Problem 2STP

Option “A” is correct.

Explanation of Solution

Ammonia due to electronegativity difference between N and H developes a dipole moment where N acquires partial negative charge and H acquires partial positive charge. Due to the pyramidal structure the net dipole directed towards the lone pair.

  World of Chemistry, 3rd edition, Chapter 14, Problem 2STP , additional homework tip  1

On the other hand due tetrahedral structure of methane ( CH4 ) the dipole generated in CH are in opposite direction and hence the cancel each other. Hence CH4 is non-polar molecule and only force that operates in it is London dispersion forces.

  World of Chemistry, 3rd edition, Chapter 14, Problem 2STP , additional homework tip  2

Conclusion

Option “A” is correct.

Chapter 14 Solutions

World of Chemistry, 3rd edition

Ch. 14.2 - Prob. 3RQCh. 14.2 - Prob. 4RQCh. 14.2 - Prob. 5RQCh. 14.2 - Prob. 6RQCh. 14.2 - Prob. 7RQCh. 14.3 - Prob. 1RQCh. 14.3 - Prob. 2RQCh. 14.3 - Prob. 3RQCh. 14.3 - Prob. 4RQCh. 14.3 - Prob. 5RQCh. 14 - Prob. 1ACh. 14 - Prob. 2ACh. 14 - Prob. 3ACh. 14 - Prob. 4ACh. 14 - Prob. 5ACh. 14 - Prob. 6ACh. 14 - Prob. 7ACh. 14 - Prob. 8ACh. 14 - Prob. 9ACh. 14 - Prob. 10ACh. 14 - Prob. 11ACh. 14 - Prob. 12ACh. 14 - Prob. 13ACh. 14 - Prob. 14ACh. 14 - Prob. 15ACh. 14 - Prob. 16ACh. 14 - Prob. 17ACh. 14 - Prob. 18ACh. 14 - Prob. 19ACh. 14 - Prob. 20ACh. 14 - Prob. 21ACh. 14 - Prob. 22ACh. 14 - Prob. 23ACh. 14 - Prob. 24ACh. 14 - Prob. 25ACh. 14 - Prob. 26ACh. 14 - Prob. 27ACh. 14 - Prob. 28ACh. 14 - Prob. 29ACh. 14 - Prob. 30ACh. 14 - Prob. 31ACh. 14 - Prob. 32ACh. 14 - Prob. 33ACh. 14 - Prob. 34ACh. 14 - Prob. 35ACh. 14 - Prob. 36ACh. 14 - Prob. 37ACh. 14 - Prob. 38ACh. 14 - Prob. 39ACh. 14 - Prob. 40ACh. 14 - Prob. 41ACh. 14 - Prob. 42ACh. 14 - Prob. 43ACh. 14 - Prob. 44ACh. 14 - Prob. 45ACh. 14 - Prob. 46ACh. 14 - Prob. 47ACh. 14 - Prob. 48ACh. 14 - Prob. 49ACh. 14 - Prob. 50ACh. 14 - Prob. 51ACh. 14 - Prob. 52ACh. 14 - Prob. 53ACh. 14 - Prob. 54ACh. 14 - Prob. 55ACh. 14 - Prob. 56ACh. 14 - Prob. 57ACh. 14 - Prob. 58ACh. 14 - Prob. 59ACh. 14 - Prob. 60ACh. 14 - Prob. 61ACh. 14 - Prob. 62ACh. 14 - Prob. 63ACh. 14 - Prob. 64ACh. 14 - Prob. 1STPCh. 14 - Prob. 2STPCh. 14 - Prob. 3STPCh. 14 - Prob. 4STPCh. 14 - Prob. 5STPCh. 14 - Prob. 6STPCh. 14 - Prob. 7STPCh. 14 - Prob. 8STPCh. 14 - Prob. 9STPCh. 14 - Prob. 10STPCh. 14 - Prob. 11STPCh. 14 - Prob. 12STP
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