Concept explainers
a)
To find
a)
Answer to Problem 21E
The probability that car neither will need repair is 0.5184
Explanation of Solution
Given:
P(Once repair) = 17% = 0.17
P(Twice repair) = 7% = 0.07
P(Thrice or more) = 4% = 0.04
P(No repairs) = 0.72
P(Some repairs) = 0.28
Formula:
Multiplication rule:
Hence, probability that car neither will need repair is 51.84%
b)
To find probability that both will need repair.
b)
Answer to Problem 21E
The probability that both will need repair is 0.0784
Explanation of Solution
Given:
P(Once repair) = 17% = 0.17
P(Twice repair) = 7% = 0.07
P(Thrice or more) = 4% = 0.04
P(No repairs) = 0.72
P(Some repairs) = 0.28
Formula:
Multiplication rule:
Hence, probability that both will need repair is 7.84%
c)
To find probability that at least one repair.
c)
Answer to Problem 21E
The probability that at least one repair is 0.4816
Explanation of Solution
Given:
P(Once repair) = 17% = 0.17
P(Twice repair) = 7% = 0.07
P(Thrice or more) = 4% = 0.04
P(No repairs) = 0.72
P(Some repairs) = 0.28
P(Neither need repairs) = 0.5184
Formula:
Complement rule:
Hence, probability that at least one repair is 48.16%
Chapter 14 Solutions
Stats: Modeling the World Nasta Edition Grades 9-12
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