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Organic Chemistry
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- Nitriles, R–=C≡N, undergo a hydrolysis reaction when heated with aqueous acid. What is the structure of the compound produced by hydrolysis of propanenitrile, CH3CH2C≡N, if it has IR absorptions from 2500–3100 cm-1 and at 1710 cm-1, and has M+=74?arrow_forwardKetones undergo a reduction when treated with sodium borohydride, NaBH4. What is the structure of the compound produced by reaction of 2-butanone with NaBH4 if it has an IR absorption at 3400 cm-1 and M+=74 in the mass spectrum?arrow_forwardThe treatment of (CH3)2C=CHCH2Br with H2O forms B (molecular formula C5H10O) as one of the products. Determine the structure of B from its 1H NMR and IR spectra.arrow_forward
- A compound has the molecular formula C6H12O2. Its IR spectrum shows a strong absorption band near 1740 cm-1. Its 1H NMR spectrum consists of two singlets at δ 1.2 and δ 3.6. Which is the most likely structure of the compound?arrow_forwardWhich of the following compounds is consistent with the ¹H NMR spectrum shown below? 7 1H dd (A) 1H 1H dd dd 6 (B) ppm 5 (C) ★ 3H S (D)arrow_forwardThe azo compound shown below has a λmax value of 410 nm. When treated with hydrogen in the presence of palladium on carbon, the λmax changes significantly. Suggest a reason for this observation and predict whether the λmax value increases or decreases.arrow_forward
- An unknown compound C3H2NCl shows moderately strong IR absorptions around 1650 cm-1 and 2200 cm-1. Its NMR spectrum consists of two doublets (J = 14 Hz) at δ 5.9 and δ 7.1. Propose a structure consistent with this data?arrow_forwardIdentify the structures of isomers A and B, whose molecular formula is C10 H12 O2, from IR spectroscopic data and their H-NMR spectra.arrow_forward5arrow_forward
- The NMR spectrum of bromocyclohexane indicates a low field signal (1H) at δ 4.16. To room temperature, this signal is a singlet, but at -75 ° C it separates into two peaks of unequal area (but totaling one proton): δ 3.97 and δ 4.64, in ratio 4.6: 1.0. How do you explain the doubling in two peaks? According to the generalization of the previous problem, what conformation of the molecule predominates (at -75 ° C)? What percentage of the molecules does it correspond to? Solve all parts otherwise down vote and hand written solutionarrow_forwardCompound B of molecular formula C9H19N shows a noteworthy infrared absorption at 3300 cm-1. Its 1H-NMR spectrum shows three singlets – δ 1.0 (6H), 1.1 (12H), 1.4 (1H) ppm. Its 13C-NMR spectrum has four signals – δ 25, 28, 41, 64 ppm. Suggest a structure for this compound.arrow_forwardWhen 2-bromo-3,3-dimethylbutane is treated with K+ −OC(CH3)3, a single product T having molecular formula C6H12 is formed. When 3,3dimethylbutan-2-ol is treated with H2SO4, the major product U has the same molecular formula. Given the following 1H NMR data, what are the structures of T and U? Explain in detail the splitting patterns observed for the three split signals in T. 1H NMR of T: 1.01 (singlet, 9 H), 4.82 (doublet of doublets, 1 H, J = 10, 1.7 Hz), 4.93 (doublet of doublets, 1 H, J = 18, 1.7 Hz), and 5.83 (doublet of doublets, 1 H, J = 18, 10 Hz) ppm 1H NMR of U: 1.60 (singlet) ppmarrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning