To determine why the low-molecular-weight alcohols are more soluble in water than the low-molecular-weight ethers are not. Concept Introduction: Generally, the solubility depends on the attractions between the molecules solute and solvent. This causes the difference between the solubility of alcohols and ethers.

Question

(a) The following synthesis of the molecule shown in the circle has a major problem. What is this problem? (2 pts) 1) HBr (no peroxides) 2) H- NaNH2 Br 3) NaNH, 4) CH3Br 5) H2, Pd (b) Starting with the molecule shown below and any other materials with two carbons or less, write out an alternate synthesis of the circled molecule. More than one step is needed. Indicate the reagent(s) and the major product in all the steps in your synthesis. (5 pts) 2024 Fall Term (1) Organic Chemistry 1 (Lec) CHEM 22204 02[6386] (Hunter College) (c) Using the same starting material as in part (b) and any other materials win two carpons or less, write out syntheses of the circled molecules shown below. More than one step is needed in each case. Indicate the reagent(s) and the major product in all the steps in your synthesis. You may use reactions and products from your synthesis in part (b). (5 pts)

Answer 1

Question

Chapter 14, Problem 14.18P

Interpretation Introduction

Interpretation:

To determine why the low-molecular-weight alcohols are more soluble in water than the low-molecular-weight ethers are not.

Concept Introduction:

Generally, the solubility depends on the attractions between the molecules solute and solvent. This causes the difference between the solubility of alcohols and ethers.

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