Chemistry: An Atoms-Focused Approach
14th Edition
ISBN: 9780393912340
Author: Thomas R. Gilbert, Rein V. Kirss, Natalie Foster
Publisher: W. W. Norton & Company
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Chemistry: An Atoms-Focused Approach
Ch. 14 - Prob. 14.1VPCh. 14 - Prob. 14.2VPCh. 14 - Prob. 14.3VPCh. 14 - Prob. 14.4VPCh. 14 - Prob. 14.5VPCh. 14 - Prob. 14.6VPCh. 14 - Prob. 14.7VPCh. 14 - Prob. 14.8VPCh. 14 - Prob. 14.9VPCh. 14 - Prob. 14.10VP
Ch. 14 - Prob. 14.11QACh. 14 - Prob. 14.12QACh. 14 - Prob. 14.13QACh. 14 - Prob. 14.14QACh. 14 - Prob. 14.15QACh. 14 - Prob. 14.16QACh. 14 - Prob. 14.17QACh. 14 - Prob. 14.18QACh. 14 - Prob. 14.19QACh. 14 - Prob. 14.20QACh. 14 - Prob. 14.21QACh. 14 - Prob. 14.22QACh. 14 - Prob. 14.23QACh. 14 - Prob. 14.24QACh. 14 - Prob. 14.25QACh. 14 - Prob. 14.26QACh. 14 - Prob. 14.27QACh. 14 - Prob. 14.28QACh. 14 - Prob. 14.29QACh. 14 - Prob. 14.30QACh. 14 - Prob. 14.31QACh. 14 - Prob. 14.32QACh. 14 - Prob. 14.33QACh. 14 - Prob. 14.34QACh. 14 - Prob. 14.35QACh. 14 - Prob. 14.36QACh. 14 - Prob. 14.37QACh. 14 - Prob. 14.38QACh. 14 - Prob. 14.39QACh. 14 - Prob. 14.40QACh. 14 - Prob. 14.41QACh. 14 - Prob. 14.42QACh. 14 - Prob. 14.43QACh. 14 - Prob. 14.44QACh. 14 - Prob. 14.45QACh. 14 - Prob. 14.46QACh. 14 - Prob. 14.47QACh. 14 - Prob. 14.48QACh. 14 - Prob. 14.49QACh. 14 - Prob. 14.50QACh. 14 - Prob. 14.51QACh. 14 - Prob. 14.52QACh. 14 - Prob. 14.53QACh. 14 - Prob. 14.54QACh. 14 - Prob. 14.55QACh. 14 - Prob. 14.56QACh. 14 - Prob. 14.57QACh. 14 - Prob. 14.58QACh. 14 - Prob. 14.59QACh. 14 - Prob. 14.60QACh. 14 - Prob. 14.61QACh. 14 - Prob. 14.62QACh. 14 - Prob. 14.63QACh. 14 - Prob. 14.64QACh. 14 - Prob. 14.65QACh. 14 - Prob. 14.66QACh. 14 - Prob. 14.67QACh. 14 - Prob. 14.68QACh. 14 - Prob. 14.69QACh. 14 - Prob. 14.70QACh. 14 - Prob. 14.71QACh. 14 - Prob. 14.72QACh. 14 - Prob. 14.73QACh. 14 - Prob. 14.74QACh. 14 - Prob. 14.75QACh. 14 - Prob. 14.76QACh. 14 - Prob. 14.77QACh. 14 - Prob. 14.78QACh. 14 - Prob. 14.79QACh. 14 - Prob. 14.80QACh. 14 - Prob. 14.81QACh. 14 - Prob. 14.82QACh. 14 - Prob. 14.83QACh. 14 - Prob. 14.84QACh. 14 - Prob. 14.85QACh. 14 - Prob. 14.86QACh. 14 - Prob. 14.87QACh. 14 - Prob. 14.88QACh. 14 - Prob. 14.89QACh. 14 - Prob. 14.90QACh. 14 - Prob. 14.91QACh. 14 - Prob. 14.92QACh. 14 - Prob. 14.93QACh. 14 - Prob. 14.94QACh. 14 - Prob. 14.95QACh. 14 - Prob. 14.96QACh. 14 - Prob. 14.97QACh. 14 - Prob. 14.98QACh. 14 - Prob. 14.99QACh. 14 - Prob. 14.100QACh. 14 - Prob. 14.101QACh. 14 - Prob. 14.102QACh. 14 - Prob. 14.103QACh. 14 - Prob. 14.104QACh. 14 - Prob. 14.105QACh. 14 - Prob. 14.106QACh. 14 - Prob. 14.107QACh. 14 - Prob. 14.108QACh. 14 - Prob. 14.109QACh. 14 - Prob. 14.110QACh. 14 - Prob. 14.111QACh. 14 - Prob. 14.112QACh. 14 - Prob. 14.113QACh. 14 - Prob. 14.114QACh. 14 - Prob. 14.115QACh. 14 - Prob. 14.116QACh. 14 - Prob. 14.117QACh. 14 - Prob. 14.118QACh. 14 - Prob. 14.119QACh. 14 - Prob. 14.120QACh. 14 - Prob. 14.121QACh. 14 - Prob. 14.122QACh. 14 - Prob. 14.123QACh. 14 - Prob. 14.124QACh. 14 - Prob. 14.125QACh. 14 - Prob. 14.126QA
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- For the reaction N2(g)+3H2(g)2NH3(g) show that Kc = Kp(RT)2 Do not use the formula Kp = Kc(RT)5n given in the text. Start from the fact that Pi = [i]RT, where Pi is the partial pressure of substance i and [i] is its molar concentration. Substitute into Kc.arrow_forward12.103 Methanol, CH3OH, can be produced by the reaction of CO with H2, with the liberation of heat. All species in the reaction are gaseous. What effect will each of the following have on the equilibrium concentration of CO? (a) Pressure is increased, (b) volume of the reaction container is decreased, (c) heat is added, (d) the concentration of CO is increased, (e) some methanol is removed from the container, and (f) H2 is added.arrow_forwardShow that the complete chemical equation, the total ionic equation, and the net ionic equation for the reaction represented by the equation KI(aq)+I2(aq)KI3(aq) give the same expression for the reaction quotient. KI3 is composed of the ions K+ and I3-.arrow_forward
- A solution is prepared by dissolving 0.050 mol of diiodocyclohexane, C5H10I2, in the solvent CCl4.The total solution volume is 1.00 L When the reaction C6H10I2 C6H10 + I2 has come to equilibrium at 35 C, the concentration of I2 is 0.035 mol/L. (a) What are the concentrations of C6H10I2 and C6H10 at equilibrium? (b) Calculate Kc, the equilibrium constant.arrow_forwardWrite an equation for an equilibrium system that would lead to the following expressions (ac) for K. (a) K=(Pco)2 (PH2)5(PC2H6)(PH2O)2 (b) K=(PNH3)4 (PO2)5(PNO)4 (PH2O)6 (c) K=[ ClO3 ]2 [ Mn2+ ]2(Pcl2)[ MNO4 ]2 [ H+ ]4 ; liquid water is a productarrow_forwardKc = 5.6 1012 at 500 K for the dissociation of iodine molecules to iodine atoms. I2(g) 2 I(g) A mixture has [I2] = 0.020 mol/Land [I] = 2.0 108 mol/L. Is the reaction at equilibrium (at 500 K)? If not, which way must the reaction proceed to reach equilibrium?arrow_forward
- The decomposition of PCl5(g) to form PCl3(g) and Cl2(g) has Kc = 33.3 at a high temperature. If the initial concentration of PCl5 is 0.1000 M, what are the equilibrium concentrations of the reactants and products?arrow_forwardWrite a chemical equation for an equilibrium system that would lead to the following expressions (ad) for K. (a) K=(PH2S)2 (PO2)3(PSO2)2 (PH2O)2 (b) K=(PF2)1/2 (PI2)1/2PIF (c) K=[ Cl ]2(Pcl2)[ Br ]2 (d) K=(PNO)2 (PH2O)4 [ Cu2+ ]3[ NO3 ]2 [ H+ ]8arrow_forwardBecause calcium carbonate is a sink for CO32- in a lake, the student in Exercise 12.39 decides to go a step further and examine the equilibrium between carbonate ion and CaCOj. The reaction is Ca2+(aq) + COj2_(aq) ** CaCO,(s) The equilibrium constant for this reaction is 2.1 X 10*. If the initial calcium ion concentration is 0.02 AI and the carbonate concentration is 0.03 AI, what are the equilibrium concentrations of the ions? A student is simulating the carbonic acid—hydrogen carbonate equilibrium in a lake: H2COj(aq) H+(aq) + HCO}‘(aq) K = 4.4 X 10"7 She starts with 0.1000 AI carbonic acid. What are the concentrations of all species at equilibrium?arrow_forward
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