Explanation Given: The mass ( m ) A and B is m . Draw the free body diagram of block A as shown in Figure (1). Write the formula for equation of motion for block A in the vertical direction. ∑ F y = m a y = m ( 0 ) = 0 Here, summation of total force acting on vertical direction is ∑ F y mass is m and acceleration in the vertical direction is a y . Refer Figure (1) resolve the forces in the vertical direction. ∑ F y = N cos θ − m g (I). Write the formula for equation of motion for block A in the horizontal direction. ∑ F x = m a x Here, summation of total force acting on horizontal direction is ∑ F x mass is m and acceleration in the horizontal direction is a x . Refer Figure (1) resolve the forces in the horizontal direction. ∑ F x = N sin θ (II). Draw the free body diagram for block B as shown in Figure (2). Write the formula for equation of motion for block B in the horizontal direction. ∑ F x = m a x Here, summation of total force acting on horizontal direction is ∑ F x mass is m and acceleration in the horizontal direction is a x . Refer Figure (2) resolve the forces in the horizontal direction. ∑ F x = P − N sin θ (III). Conclusion: Substitute m a for ∑ F x in Equation (III). ∑ F x = P − N sin θ m a = P − N sin θ (IV)

Engineering Mechanics: Statics & Dynamics (14th Edition)

14th Edition

ISBN: 9780133915426

Author: Russell C. Hibbeler

Publisher: PEARSON

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Chapter 13.4, Problem 46P

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The horizontal force P required to apply on block B so that A will not relative to B .

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Chapter 13.4, Problem 45P

Chapter 13.4, Problem 47P

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Engineering Mechanics: Statics & Dynamics (14th Edition)

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The horizontal force P required to apply on block B so that A will not relative to B .

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The horizontal force P required to apply on block B so that A will not relative to B .

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Chapter 13 Solutions