Biology: The Dynamic Science (MindTap Course List)
4th Edition
ISBN: 9781305389892
Author: Peter J. Russell, Paul E. Hertz, Beverly McMillan
Publisher: Cengage Learning
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Textbook Question
Chapter 13.2, Problem 1SB
You have a true-breeding strain of miniature-winged fruit flies, where this wing trait is recessive to the normal long wings. How would you show whether the miniature wing trait is sex-linked or autosomal?
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Consider a cross between a Brown furred dog and a Yellow furred dog. All the puppies born from these parents are yellow furred. Crossing the F1 yellow furred sons and F1 yellow furred daughters produces a 3:1 ratio of yellow furred dogs (3) to brown-furred dogs (1) in the F2 generation.
True or False: this tells you that brown fur color in this dog species is inherited in an autosomal recessive manner.
is it true or false?
You have a Drosophila line that is homozygous for autosomal recessive alleles a, b, and c, linked in that order. Youcross females of this line with males homozygous for thecorresponding wild-type alleles. You then cross the F1 heterozygous males with their heterozygous sisters. You obtain the following F2 phenotypes (where letters denoterecessive phenotypes and pluses denote wild-type phenotypes): 1364 + + +, 365 a b c, 87 a b +, 84 + + c,47 a + +, 44 + b c, 5 a + c, and 4 + b +.a. What is the recombinant frequency between a andb? Between b and c? (Remember, there is no crossingover in Drosophila males.)b. What is the coefficient of coincidence?
In Alaskan Malamute dogs, an autosomal recessive allele
causes a condition in which the cartilage in the front legs
fails to develop properly. This results in a type of
dwarfism. Dogs with the dominant wild-type allele are of
normal height.
In the same breed of dogs, there is an autosomal
dominant allele that codes for a curled tail and a
recessive allele that codes for an uncurled tail.
Show the possible genotypes for the offspring of a
dog heterozygous for height and tail curl crossed
with a dog recessive for both traits. Your answer must
include the use of a Punnett square and a legend
indicating the allele symbols used.
Chapter 13 Solutions
Biology: The Dynamic Science (MindTap Course List)
Ch. 13.1 - You want to determine whether genes a and b are...Ch. 13.2 - You have a true-breeding strain of...Ch. 13.3 - What mechanisms are responsible for: (a)...Ch. 13.4 - A man has Simpson syndrome, an addiction to a...Ch. 13.4 - Prob. 2SBCh. 13.5 - Prob. 1SBCh. 13 - In humans, redgreen color blindness is an X-linked...Ch. 13 - The following pedigree shows the pattern of...Ch. 13 - Individuals affected by a condition known as...Ch. 13 - A number of genes carried on the same chromosome...
Ch. 13 - Prob. 5TYKCh. 13 - Discuss Concepts Can a linkage map be made for a...Ch. 13 - In Drosophila, two genes, one for body color and...Ch. 13 - Another gene in Drosophila determines wing length....Ch. 13 - Prob. 9TYKCh. 13 - You conduct a cross in Drosophila that produces...Ch. 13 - Discuss Concepts Crossing-over does not occur...Ch. 13 - Prob. 12TYKCh. 13 - Prob. 13TYKCh. 13 - Prob. 14TYKCh. 13 - Prob. 1ITDCh. 13 - Prob. 2ITDCh. 13 - Prob. 3ITDCh. 13 - Prob. 4ITD
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- In goats, a beard is produced by an autosomal allele that is dominant in males and recessive in females. We’ll use the symbol b for the beard allele and + for the beardless allele. Another independently assorting autosomal allele that produces a black coat (W) is dominant over the allele for white coat (w). Part A and D have been completed for you and is shown in the image. Give the phenotypes and their expected proportions for the crosses B and C:b) +bWw male x +bww femalec) ++Ww male x bbWw femalearrow_forwardWild type fruit flies have grey bodies and straight wings. Yellow bodies and curly wings are both recessive phenotypes. The body color gene is X-linked; the wild type allele is designated XY+. The wing shape gene is autosomal; the wild type allele is designated C+. You cross a pure breeding yellow-bodied, curly-winged female with a grey-bodied, straight-winged male to produce an F1 generation. Use this information to answer questions X-Y below. 20) You cross two F1 flies to produce an F2 generation. What proportion of the F2 female flies are expected to have curly wings and yellow bodies? a) 1/16 b) 1/4 c) 1/8 d) 3/8 e) 3/16arrow_forwardVestigial wing is a recessive autosomal mutation in the fruit fly Drosophila melanogaster. Wild-type flies have red eyes, but another mutation, an X-linked recessive mutation causes white eyes. You cross a parental generation of males with vestigial wings with females that have white eyes. 1) What phenotypic ratio would you expect in the F1 generation from such a cross? What phenotypes do you observe in these flies? (e.g. males with red eyes and wild-type wings). 2) What phenotypic ratio would you expect in the F2 generation? What phenotypes do you observe in these flies?arrow_forward
- In Drosophila, the white gene located on the X chromosome affects eye color; an autosomal gene, wingless, is on an autosomal chromosome. Use the following allele symbols: Xw+ _ , Xw+Y = wild type red eyes; X-linked dominant allele Xw Xw , XwY = white eyes; X-linked recessive allele Y = Y sex chromosome vg+ = wild type wings; autosomal dominant vg = wingless; autosomal recessive Predict ratios/proportions of genotypes and phenotypes of offspring from the following cross, of a white-eyed male with wild type wings and a wild type red eyed female with wild type wings: indicate sex of offspring along with phenotypes. XwY vg+ vg x Xw+Xw vg+vgarrow_forwardIn Drosophila, an X-linked recessive mutation, Xm causes miniature wings. List the F2 phenotypic ratios if: a miniature-winged female is crossed with a normal male and a miniature-winged male is crossed with a normal female. What would the phenotypic ratio from (a) be if the miniature-winged gene were autosomal? Assume in all cases that the P1 individuals are true-breeding.arrow_forwardA recessive allele causes Drosophila to have white eyes instead of wild-type eyes. This eye colourgene is known to be X-linked. In a cross between homozygous wild-type females and white-eyedmales, all F1 progeny have wild-type eyes. What ratio of wild-type to white-eyed progeny can be expected in each sex if F1 females arecrossed to males of the same genotype as their father?a. Males – 1 : 0; females – 1 : 0b. Males – 1 : 1; females – 1 : 0c. Males – 0 : 1; females – 1 : 1d. Males – 1 : 1; females – 1 : 1arrow_forward
- Let’s say we are crossing flies with a “big head” mutant trait with flies that have normal sized heads. If the mutant allele in this cross is a dominant, autosomal allele, when phenotype(s) should be present in the F1 of your cross, and what fraction of the F1 should each phenotype represent?arrow_forwardPlease explain You are interested in the inheritance of two autosomal genes in a type of beetle. These genes determine carapace color (violet or green, governed by the alleles c+ and c) and presence or absence of a horn (with horn, without horn, determined by the alleles h+ and h). You cross two pure lines of beetles and let the F1 generation (c+/c · h+/h) intercross. The F2 progeny deviate from the expected Mendelian ratio, so you cross a dihybrid F1 female with a tester male. Of the 500 progeny, 132 are (c+ · h+), _____ are (c · h), 118 are (c · h+), and 110 are (c+ · h).arrow_forwardIN DROSOPHILA, AN X-LINKED RECESSIVE MUTATION, Xm CAUSES MINIATURE WINGS. LIST THE F₂ PHENOTYPIC RATIOS IF: A MINIATURE-WINGED FEMALE IS CROSSED WITH A NORMAL MALE AND A MINIATURE-WINGED MALE IS ● ● CROSSED WITH A NORMAL FEMALE. WHAT WOULD THE PHENOTYPIC RATIO FROM (A) BE IF THE MINIATURE- WINGED GENE WERE AUTOSOMAL? ASSUME IN ALL CASES THAT THE P1 INDIVIDUALS ARE TRUE-BREEDING.arrow_forward
- Some conditions like progeria do not run in families despite being autosomal dominant. How is this possible?arrow_forwardIn Drosophila, ebony body colour is produced by a recessive gene a and wild-type (gray) body colour by its dominant allele a+. Vestigial wings are governed by a recessive gene vg, and normal wing size (wild type) by its dominant allele vg+. If wild-type dihybrid flies are crossed and produce 256 progeny, how many of these progeny flies are expected in each phenotypic class?arrow_forwardColor blindness in humans is controlled by an X-linked completely recessive allele (Xc), while breast cancer is controlled by an autosomal completely dominant allele, B. A color blind male, who is a heterozygote carrier for breast cancer has three children/n with a normal eyed female (whose mother was color blind), who is homozygote recessive for the breast cancer allele. What is the probability that out of three children, 2 will be color blind males, and not show breast cancer, and one will be a color blind female, who shows breast cancer?arrow_forward
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