Chapter 1.3, Problem 4P

(a)

To determine

To find: the inequality that compare the two numbers.

Answer to Problem 4P

  $\sqrt{129}<11.52$ .

Explanation of Solution

Given:

  $\sqrt{129}\text{ and }11.52$ .

Concept used:

Less than inequality is denoted by $"<":x<y$ if $x$ is less than $y$ .

Calculation:

According to the given:

  $\sqrt{129}\text{ and }11.52$ .

By simplify the root term as:

  $\sqrt{129}=11.358$ .

Which is less than the $11.52$ .

So, the less than inequality is denoted by $"<":x<y$ if $x$ is less than $y$ :

Hence, $\sqrt{129}<11.52$ .

(b)

To determine

To find: the reason of having another inequality or not that can compare to numbers.

Answer to Problem 4P

  $\sqrt{129}<11.52$ .

Explanation of Solution

Given:

  $\sqrt{129}\text{ and }11.52$ .

Concept used:

he less than inequality is denoted by $"<":x<y$ if $x$ is less than $y$ .

Calculation:

According to the given:

  $\sqrt{129}\text{ and }11.52$ .

By simplify the root term as:

  $\sqrt{129}=11.358$ .

Which is less than the $11.52$ .

No there is no other inequality which can represent the inequality So, the less than inequality is denoted by $"<":x<y$ if $x$ is less than $y$ :

Hence, $\sqrt{129}<11.52$ .