CHEMISTRY >CUSTOM<
CHEMISTRY >CUSTOM<
8th Edition
ISBN: 9781309097182
Author: SILBERBERG
Publisher: MCG/CREATE
Question
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Chapter 13, Problem 13.91P

(a)

Interpretation Introduction

Interpretation:

The moles of particles of CuSO4 in 1mL of the solution is to be calculated.

Concept introduction:

Molarity is defined as the number of moles of solute that are dissolved in one litre of solution. It is represented by M and its unit is mol/L.

The formula to calculate the molarity of the solution is as follows:

Molarity=amount(mol)ofsolutevolume (L)ofsolution (1)

(a)

Expert Solution
Check Mark

Answer to Problem 13.91P

The moles of CuSO4 in 1mL of the solution is 4×105mol.

Explanation of Solution

Rearrange equation (1) to calculate the amount of solute as follows:

Amountofsolute=(Molarity)(Volume ofsolution) (2)

The dissociation of CuSO4 occurs as follows:

CuSO4Cu++SO42

One mole of CuSO4 to give one Cu+ and one SO42 ion.

The formula to calculate the moles of particles of any compound is as follows:

Molesof particles=(Molarity)(Volume ofsolution)(molesof dissociated particlesmolesofcompound) (3)

Substitute 0.02M for the molarity, 1mL for the volume of solution, 2 mol for the moles of dissociated particles and 1mol for the moles of the compound in equation (3) to calculate the moles of particles of CuSO4.

Molesof particles of CuSO4=(0.02mol1L)(1mL)(1L103mL)(2mol1 mol)=4×105mol

Conclusion

The moles of CuSO4 in 1mL of the solution is 4×105mol.

(b)

Interpretation Introduction

Interpretation:

The moles of particles of Ba(OH)2 in 1mL of the solution is to be calculated.

Concept introduction:

Molarity is defined as the number of moles of solute that are dissolved in one litre of solution. It is represented by M and its unit is mol/L.

The formula to calculate the molarity of the solution is as follows:

Molarity=amount(mol)ofsolutevolume (L)ofsolution (1)

(b)

Expert Solution
Check Mark

Answer to Problem 13.91P

The moles of particles of Ba(OH)2 in 1mL of the solution is 1×105mol.

Explanation of Solution

The dissociation of Ba(OH)2 occurs as follows:

Ba(OH)2Ba2++2OH

One mole of Ba(OH)2 dissociates to give one Ba2+ and two OH ions.

Substitute 0.004M for the molarity, 1mL for the volume of solution, 3mol for the moles of dissociated particles and 1mol for the moles of the compound in equation (3) to calculate the moles of particles of Ba(OH)2.

Molesof particles of Ba(OH)2=(0.004mol1L)(1mL)(1L103mL)(3mol1 mol)=1.2×105mol=1×105mol

Conclusion

The moles of particles of Ba(OH)2 in 1mL of the solution is 1×105mol.

(c)

Interpretation Introduction

Interpretation:

The moles of particles of C5H5N in 1mL of the solution is to be calculated.

Concept introduction:

Molarity is defined as the number of moles of solute that are dissolved in one litre of solution. It is represented by M and its unit is mol/L.

The formula to calculate the molarity of the solution is as follows:

Molarity=amount(mol)ofsolutevolume (L)ofsolution (1)

(c)

Expert Solution
Check Mark

Answer to Problem 13.91P

The moles of particles of C5H5N in 1mL of the solution is 8×105mol.

Explanation of Solution

Pyridine is an aromatic compound so it does not dissociate into ions.

Substitute 0.08M for the molarity, 1mL for the volume of solution, 1mol for the moles of dissociated particles and 1mol for the moles of the compound in equation (3) to calculate the moles of particles of C5H5N.

Molesof particles of C5H5N=(0.08mol1L)(1mL)(1L103mL)(1mol1 mol)=8×105mol

Conclusion

The moles of particles of C5H5N in 1mL of the solution is 8×105mol.

(d)

Interpretation Introduction

Interpretation:

The moles of particles of (NH4)2CO3 in 1mL of the solution is to be calculated.

Concept introduction:

Molarity is defined as the number of moles of solute that are dissolved in one litre of solution. It is represented by M and its unit is mol/L.

The formula to calculate the molarity of the solution is as follows:

Molarity=amount(mol)ofsolutevolume (L)ofsolution (1)

(d)

Expert Solution
Check Mark

Answer to Problem 13.91P

The moles of particles of (NH4)2CO3 in 1mL of the solution is 2×104mol.

Explanation of Solution

The dissociation of (NH4)2CO3 occurs as follows:

(NH4)2CO32NH4++CO32

One mole of (NH4)2CO3 dissociates to give one CO32 and two NH4+ ions.

Substitute 0.05M for the molarity, 1mL for the volume of solution, 3mol for the moles of dissociated particles and 1mol for the moles of the compound in equation (3) to calculate the moles of particles of (NH4)2CO3.

Molesof particles of (NH4)2CO3=(0.05mol1L)(1mL)(1L103mL)(3mol1 mol)=1.5×104mol=2×104mol

Conclusion

The moles of particles of (NH4)2CO3 in 1mL of the solution is 2×104mol.

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Chapter 13 Solutions

CHEMISTRY >CUSTOM<

Ch. 13.5 - Prob. 13.6AFPCh. 13.5 - Prob. 13.6BFPCh. 13.6 - Calculate the vapor pressure lowering of a...Ch. 13.6 - Prob. 13.7BFPCh. 13.6 - Prob. 13.8AFPCh. 13.6 - Prob. 13.8BFPCh. 13.6 - Prob. 13.9AFPCh. 13.6 - Prob. 13.9BFPCh. 13.6 - A solution is made by dissolving 31.2 g of...Ch. 13.6 - Prob. 13.10BFPCh. 13.7 - Prob. B13.1PCh. 13.7 - Prob. B13.2PCh. 13 - Prob. 13.1PCh. 13 - Prob. 13.2PCh. 13 - Prob. 13.3PCh. 13 - Which would you expect to be more effective as a...Ch. 13 - Prob. 13.5PCh. 13 - Prob. 13.6PCh. 13 - Prob. 13.7PCh. 13 - Prob. 13.8PCh. 13 - Prob. 13.9PCh. 13 - Prob. 13.10PCh. 13 - Prob. 13.11PCh. 13 - What is the strongest type of intermolecular force...Ch. 13 - Prob. 13.13PCh. 13 - Prob. 13.14PCh. 13 - Prob. 13.15PCh. 13 - Prob. 13.16PCh. 13 - Prob. 13.17PCh. 13 - Prob. 13.18PCh. 13 - Prob. 13.19PCh. 13 - Prob. 13.20PCh. 13 - Prob. 13.21PCh. 13 - Prob. 13.22PCh. 13 - Prob. 13.23PCh. 13 - What is the relationship between solvation and...Ch. 13 - Prob. 13.25PCh. 13 - Prob. 13.26PCh. 13 - Prob. 13.27PCh. 13 - Prob. 13.28PCh. 13 - Prob. 13.29PCh. 13 - Prob. 13.30PCh. 13 - Prob. 13.31PCh. 13 - Prob. 13.32PCh. 13 - Prob. 13.33PCh. 13 - Prob. 13.34PCh. 13 - Prob. 13.35PCh. 13 - Use the following data to calculate the combined...Ch. 13 - Use the following data to calculate the combined...Ch. 13 - State whether the entropy of the system increases...Ch. 13 - Prob. 13.39PCh. 13 - Prob. 13.40PCh. 13 - Prob. 13.41PCh. 13 - Prob. 13.42PCh. 13 - Prob. 13.43PCh. 13 - Prob. 13.44PCh. 13 - For a saturated aqueous solution of each of the...Ch. 13 - Prob. 13.46PCh. 13 - Prob. 13.47PCh. 13 - Prob. 13.48PCh. 13 - Prob. 13.49PCh. 13 - Prob. 13.50PCh. 13 - Prob. 13.51PCh. 13 - Prob. 13.52PCh. 13 - Prob. 13.53PCh. 13 - Prob. 13.54PCh. 13 - Prob. 13.55PCh. 13 - Calculate the molarity of each aqueous...Ch. 13 - Calculate the molarity of each aqueous...Ch. 13 - Prob. 13.58PCh. 13 - Calculate the molarity of each aqueous...Ch. 13 - How would you prepare the following aqueous...Ch. 13 - Prob. 13.61PCh. 13 - Prob. 13.62PCh. 13 - Prob. 13.63PCh. 13 - Prob. 13.64PCh. 13 - Prob. 13.65PCh. 13 - Prob. 13.66PCh. 13 - Prob. 13.67PCh. 13 - Prob. 13.68PCh. 13 - Prob. 13.69PCh. 13 - Prob. 13.70PCh. 13 - Prob. 13.71PCh. 13 - Prob. 13.72PCh. 13 - Prob. 13.73PCh. 13 - Prob. 13.74PCh. 13 - Prob. 13.75PCh. 13 - Prob. 13.76PCh. 13 - Prob. 13.77PCh. 13 - Prob. 13.78PCh. 13 - Prob. 13.79PCh. 13 - Prob. 13.80PCh. 13 - Prob. 13.81PCh. 13 - What are the most important differences between...Ch. 13 - Prob. 13.83PCh. 13 - Prob. 13.84PCh. 13 - Prob. 13.85PCh. 13 - Prob. 13.86PCh. 13 - Prob. 13.87PCh. 13 - Prob. 13.88PCh. 13 - Classify each substance as a strong electrolyte,...Ch. 13 - Prob. 13.90PCh. 13 - Prob. 13.91PCh. 13 - Which solution has the lower freezing point? 11.0...Ch. 13 - Prob. 13.93PCh. 13 - Prob. 13.94PCh. 13 - Prob. 13.95PCh. 13 - Prob. 13.96PCh. 13 - Prob. 13.97PCh. 13 - Prob. 13.98PCh. 13 - Prob. 13.99PCh. 13 - The boiling point of ethanol (C2H5OH) is 78.5°C....Ch. 13 - Prob. 13.101PCh. 13 - Prob. 13.102PCh. 13 - Prob. 13.103PCh. 13 - Prob. 13.104PCh. 13 - Prob. 13.105PCh. 13 - Prob. 13.106PCh. 13 - Prob. 13.107PCh. 13 - Prob. 13.108PCh. 13 - Prob. 13.109PCh. 13 - Prob. 13.110PCh. 13 - Prob. 13.111PCh. 13 - In a study designed to prepare new...Ch. 13 - The U.S. Food and Drug Administration lists...Ch. 13 - Prob. 13.114PCh. 13 - Prob. 13.115PCh. 13 - Prob. 13.116PCh. 13 - In a movie theater, you can see the beam of...Ch. 13 - Prob. 13.118PCh. 13 - Prob. 13.119PCh. 13 - Prob. 13.120PCh. 13 - Prob. 13.121PCh. 13 - Gold occurs in seawater at an average...Ch. 13 - Prob. 13.123PCh. 13 - Prob. 13.124PCh. 13 - Prob. 13.125PCh. 13 - Prob. 13.126PCh. 13 - Pyridine (right) is an essential portion of many...Ch. 13 - Prob. 13.128PCh. 13 - Prob. 13.129PCh. 13 - Prob. 13.130PCh. 13 - Prob. 13.131PCh. 13 - Prob. 13.132PCh. 13 - Prob. 13.133PCh. 13 - Prob. 13.134PCh. 13 - Prob. 13.135PCh. 13 - Prob. 13.136PCh. 13 - Prob. 13.137PCh. 13 - Prob. 13.138PCh. 13 - Prob. 13.139PCh. 13 - Prob. 13.140PCh. 13 - Prob. 13.141PCh. 13 - Prob. 13.142PCh. 13 - Prob. 13.143PCh. 13 - The release of volatile organic compounds into the...Ch. 13 - Although other solvents are available,...Ch. 13 - Prob. 13.146PCh. 13 - Prob. 13.147PCh. 13 - Prob. 13.148PCh. 13 - Prob. 13.149PCh. 13 - Prob. 13.150PCh. 13 - Prob. 13.151PCh. 13 - Suppose coal-fired power plants used water in...Ch. 13 - Urea is a white crystalline solid used as a...Ch. 13 - Prob. 13.154PCh. 13 - Prob. 13.155PCh. 13 - Prob. 13.156PCh. 13 - Prob. 13.157PCh. 13 - Prob. 13.158PCh. 13 - Prob. 13.159PCh. 13 - Prob. 13.160PCh. 13 - Prob. 13.161PCh. 13 - Prob. 13.162PCh. 13 - Figure 12.11 shows the phase changes of pure...Ch. 13 - KNO3, KClO3, KCl, and NaCl are recrystallized as...Ch. 13 - Prob. 13.165PCh. 13 - Prob. 13.166PCh. 13 - Prob. 13.167P
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