Physics for Scientists and Engineers, Technology Update (No access codes included)
9th Edition
ISBN: 9781305116399
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 13, Problem 13.66AP
To determine
The time period of each of three stars is
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Plaskett's binary system consists of two stars that revolve in a circular orbit about a center of mass midway between them. This statement
implies that the masses of the two stars are equal (see figure below). Assume the orbital speed of each star is V| = 200 km/s and the
orbital period of each is 11.5 days. Find the mass M of each star. (For comparison, the mass of our Sun is 1.99 x 1030 kg.)
| solar masses
M
XCM
M
Plaskett's binary system consists of two stars that revolve in a circular orbit about a center of mass midway
between them. This statement implies that the masses of the two stars are equal (see figure below). Assume
the orbital speed of each star is v| = 225 km/s and the orbital period of each is 11.6 days. Find the mass M
of each star. (For comparison, the mass of our Sun is 1.99 x 1030 kg.)
M
XCM
M
Part 1 of 3 - Conceptualize
From the given data, it is difficult to estimate a reasonable answer to this problem without working through
the details and actually solving it. A reasonable guess might be that each star has a mass equal to or slightly
larger than our Sun because fourteen days is short compared to the periods of all the Sun's planets.
Part 2 of 3 - Categorize
The only force acting on each star is the central gravitational force of attraction which results in a centripetal
acceleration. When we solve Newton's second law, we can find the unknown mass in terms of the variables…
Two stars M, and M, of equal mass make up a binary star system. They move in a circular orbit that has its center at the midpoint of the line that separates them. If
M, - M, - 1.45 sm (solar mass), and the orbital period of each star is 1.70 days, find their orbital speed. (The mass of the sun is 1.99 x 10 kg.)
km/s
M,
Chapter 13 Solutions
Physics for Scientists and Engineers, Technology Update (No access codes included)
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