Chapter 12.7, Problem 52MR

To determine

To find: The number of permutations or combinations.

Answer to Problem 52MR

The solution is $30$ .

Explanation of Solution

Given:

The given term is,

  $P{}_2$

Calculation:

For any positive integers,

  $P{}_r=\frac{n!}{\left(n-r\right)!}$

The value is calculated as,

  $\begin{array}{c}P{}_2=\frac{6!}{\left(6-2\right)!}\\ =\frac{6\times 5\times 4!}{4!}\\ =30\end{array}$

Therefore, the solution is $30$ .