Chapter 12.7, Problem 47STP

To determine

To find: The correct option of the median of the following class sizes.

Answer to Problem 47STP

The correct option is B.

Explanation of Solution

Given:

The given class size is:

  $29,31,28,25,27,33,33,26$ .

Calculation:

Arrange the given class size in ascending order as:

  $25,26,27,28,29,31,33,33$ .

As the number of elements are even so median is calculated as:

  $\begin{array}{c}\text{Median}=\frac{1}{2}\left(\frac{n}{2}\text{th term}+\left(\frac{n}{2}+1\right)\text{th term}\right)\\ =\frac{1}{2}\left(\left(\frac{8}{2}\text{th term}+\left(\frac{8}{2}+1\right)\text{th term}\right)\right)\\ =\frac{1}{2}\left(28+29\right)\\ =28.5\end{array}$

Therefore the correct option is B.