Chapter 12.3, Problem 6CYU

To determine

To find : The Correct option.

Answer to Problem 6CYU

B

Explanation of Solution

Given information :

The given data is,

  $\begin{array}{ccccc}\text{Class}& \text{Freshman}& \text{Sophomore}& \text{Junior}& \text{Senior}\\ \text{Attended}& \text{48}& \text{90}& \text{224}& \text{254}\\ \text{Not attended}& \text{182}& \text{141}& \text{36}& \text{8}\end{array}$

Formula Used:

Probability = $\frac{\text{No}\text{. of favourable outcomes}}{\text{Total possible outcomes}}$

Calculation :

Total number of students has attended game is $616=48+90+224+254$

People who took the class for junior senior $=224+254=239$

So, probability = $\frac{224+254}{616}=\frac{478}{616}$

  $=\frac{239}{308}$

Hence, option (B) is correct.