Chapter 12, Problem 41SGR

To determine

The experimental probability of the rolling 3 or 10 twice in the seven rolls.

Answer to Problem 41SGR

The probability is 0..60.

Explanation of Solution

Given:

In dice game, a player tries to roll a total of 3 or 10 with the two dice.

Kevin conducted binomial experiment for 7 rolls of the dice.

The table is shown below:

  

The probability is defined as the ratio of the number of outcomes in the favor of the event to the total number of the outcomes in the sample space.

From the Kevin’s experiment, Kevin get twice 3 or 10 in 3 simulation out of 5.

So, the experimental probability of rolling 3 or 10 twice in the seven rolls:

  $\begin{array}{l}P=\frac{3}{5}\\ =0.6\end{array}$

Therefore, the probability is 0..60.