Chapter 12.2, Problem 4CYU

To determine

The width of the window box whose volume, length, and height are $2295i{n}^3,8.5in,9in$ respectively.

Answer to Problem 4CYU

The value of the width of the window box is $30in$ .

Explanation of Solution

Given:

  $\begin{array}{l}V=2295i{n}^3\\ l=8.5in\\ h=9in\end{array}$

Concept Used:

The volume of the window box is given by the following expression:

  $V=l\times w\times h$

Where,

Length of window box: $l$

Width of window box: $w$

Height of window box: $h$

Calculation:

The volume of the window box is calcualted by using the follwoing formula:

  $V=l\times w\times h$

Put the given values:

  $\begin{array}{l}V=l\times w\times h\\ 2295=8.5\times w\times 9\\ w=\frac{2295}{8.5\times 9}\\ w=30in\end{array}$

Conclusion:

Hence, the width of the window box is $30in$ .