Chapter 12.2, Problem 49S

To determine

To find: Mean, median, and mode to the nearest tenth fir the set of data.

Answer to Problem 49S

Mean of the data is approximately 4.3, median of the data is 4 and mode of the data is 1.

Explanation of Solution

Given information:

The given set of data is 1, 5, 3, 7, 6, 2, 9, 2, 5, 1, 9, 1.

Calculation:

Arrange the data from least to greatest:

1, 1, 1, 2, 2, 3, 5, 5, 6, 7, 9, 9.

Since, mean is defined as the sum of the data divided by total number of data in a data set. Therefore,

  $\begin{array}{l}\text{mean}=\frac{1+1+1+2+2+3+5+5+6+7+9+9}{12}\\ \text{mean}=\frac{51}{12}\\ \text{mean}\approx \text{4}\text{.3}\end{array}$

Also, median of the data is middle number of the ordered data or the mean of the middle two numbers. Therefore,

  $\begin{array}{l}\text{Median}=\frac{3+5}{2}\\ \text{Median}=\frac{8}{2}\\ \text{Median}=4\end{array}$

And, mode of the data defined as the data that occurs most often. Therefore,

  $\text{Mode}=1$

Hence,

Mean of the data is approximately 4.3, median of the data is 4 and mode of the data is 1.