Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Textbook Question
Chapter 12, Problem 69E
The activation energy for the reaction
is 125 kJ/mol, and ∆E for the reaction is −216 kJ/mol. What is the activation energy for the reverse reaction [NO(g) + CO2(g) →+ NO2(g) + CO(g)]?
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Consider these three reactions as the elementary steps in the mechanism for a chemical reaction.(i) Cl2 (g) + Pt (s) à 2Cl (g) + Pt (s) Ea = 1550 kJ ∆H = – 950 kJ(ii) Cl (g)+ CO (g) + Pt (s) à ClCO (g) + Pt (s) Ea = 2240 kJ ∆H = 575 kJ(iii) Cl (g) + ClCO (g) à Cl2CO (g) Ea = 2350 kJ ∆H = – 825 kJ
e. Which reaction intermediate would be considered a catalyst (if any) and why?f. If you were to add 2700kJ of activation energy to the reaction, would you be able to make thereaction reverse itself (i.e. have the products become reactants)? Justify your answer.g. If you were to added a positive catalyst to step (iii) what would the end result be? Justify yourprediction.h. Your friend is looking at your graph and states that she believes that step (ii) is the ratedetermining step. Do you agree with her? Justify your reasoning.
Consider these three reactions as the elementary steps in the mechanism for a chemical reaction.(i) Cl2 (g) + Pt (s) à 2Cl (g) + Pt (s) Ea = 1550 kJ ∆H = – 950 kJ(ii) Cl (g)+ CO (g) + Pt (s) à ClCO (g) + Pt (s) Ea = 2240 kJ ∆H = 575 kJ(iii) Cl (g) + ClCO (g) à Cl2CO (g) Ea = 2350 kJ ∆H = – 825 kJ
a. Draw the potential energy diagram for the reaction. Label the data points for clarity.The potential energy of the reactants is 600 kJ.
b. What is the overall chemical equation?
c. What is the overall change in enthalpy for the above chemical reaction?
d. What is the overall amount of activation energy for the above chemical reaction?
e. Which reaction intermediate would be considered a catalyst (if any) and why?
f. If you were to add 2700kJ of activation energy to the reaction, would you be able to make the reaction reverse itself (i.e. have the products become reactants)? Justify your answer.
g. If you were to added a positive catalyst to step (iii) what would the end result be? Justify…
Consider these three reactions as the elementary steps in the mechanism for a chemical reaction.(i) Cl2 (g) + Pt (s) à 2Cl (g) + Pt (s) Ea = 1550 kJ ∆H = – 950 kJ(ii) Cl (g)+ CO (g) + Pt (s) à ClCO (g) + Pt (s) Ea = 2240 kJ ∆H = 575 kJ(iii) Cl (g) + ClCO (g) à Cl2CO (g) Ea = 2350 kJ ∆H = – 825 kJ
e. Which reaction intermediate would be considered a catalyst (if any) and why?f. If you were to add 2700kJ of activation energy to the reaction, would you be able to make thereaction reverse itself (i.e. have the products become reactants)? Justify your answer.g. If you were to added a positive catalyst to step (iii) what would the end result be? Justify yourprediction. h. Your friend is looking at your graph and states that she believes that step (ii) is the ratedetermining step. Do you agree with her? Justify your reasoning.
Chapter 12 Solutions
Chemistry
Ch. 12 - Define reaction rate. Distinguish between the...Ch. 12 - Distinguish between the differential rate law and...Ch. 12 - One experimental procedure that can be used to...Ch. 12 - The initial rate for a reaction is equal to the...Ch. 12 - Consider the zero-, first-, and second-order...Ch. 12 - Derive expressions for the half-life of zero-,...Ch. 12 - Prob. 7RQCh. 12 - What two requirements must be met to call a...Ch. 12 - Prob. 9RQCh. 12 - Give the Arrhenius equation. Take the natural log...
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