Chemistry Atoms First2e
Chemistry Atoms First2e
2nd Edition
ISBN: 9781947172647
Author: OpenStax
Publisher: OpenStax College
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Chapter 12, Problem 46E

The evaporation of one mole of water at 298 K has a standard free energy change of 8.58 kJ).

H 2 O ( l ) = H 2 O ( g ) Δ G ° = 8.58 kJ

(a) Is the evaporation of water under standard thermodynamic conditions spontaneous?

(b) Determine the equilibrium constant,K p, for this physical process.

(c) By calculating Δ G , determine if the evaporation of water at 298 K is spontaneous when the partial pressure of water, P H 2 O , is 0.011 atm.

(d) If the evaporation of water were always nonspontaneous at room temperature, wet Laundry would never dry when placed outside. In order for laundry to dry, what must be the value of P H 2 O in the air?

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The evaporation of one mole of water at 298 K has a standard free energy change of 8.58 kJ.H2O(l) ⇌ H2O(g)                  ΔG°298 = 8.58 kJ(a) Is the evaporation of water under standard thermodynamic conditions spontaneous?(b) Determine the equilibrium constant, KP, for this physical process.(c) By calculating ΔG, determine if the evaporation of water at 298 K is spontaneous when the partial pressure of water, PH2 O, is 0.011 atm.(d) If the evaporation of water were always nonspontaneous at room temperature, wet laundry would never dry when placed outside. In order for laundry to dry, what must be the value of PH2 O in the air?
What is the equilibrium pressure of O 2(g), in bar, over a sample of NiO(s) at 298 K, given that Δ rG˚ = 208.2 kJ for the reaction: NiO(s) ↔ Ni(s) + ½O 2(g)?

Chapter 12 Solutions

Chemistry Atoms First2e

Ch. 12 - Consider the system shown in Figure 12.9. What is...Ch. 12 - Arrange the following sets of systems in order of...Ch. 12 - At room temperature, the entropy of the halogens...Ch. 12 - Consider two processes: sublimation of I2(s) and...Ch. 12 - Indicate which substance in the given pairs has...Ch. 12 - Predict the sign of the entropy change for the...Ch. 12 - Predict the sign of the entropy change for the...Ch. 12 - Write the balanced chemical equation for the...Ch. 12 - Write the balanced chemical equation for the...Ch. 12 - What is the difference between S and S for a...Ch. 12 - Calculate S for the following changes. (a)...Ch. 12 - Determine the entropy change for the combustion of...Ch. 12 - Determine the entropy change for the combustion of...Ch. 12 - Thermite reactions have been used for welding...Ch. 12 - Using the relevant S values listed in Appendix G,...Ch. 12 - From the following information, determine S for...Ch. 12 - By calculating Suniv, at each temperature,...Ch. 12 - Use the standard entropy data in Appendix G to...Ch. 12 - Use the standard entropy data in Appendix G to...Ch. 12 - What is the difference between G and G for a...Ch. 12 - A reaction has H=100kJ/mol and S=250J/mol.K . Is...Ch. 12 - Explain what happens as a reaction starts with G0...Ch. 12 - Use the standard free energy of formation data in...Ch. 12 - Use the standard free energy data in Appendix G to...Ch. 12 - Given: P4(s)+5O2(g)P4O10(s) G=2697.0kJ/mol...Ch. 12 - Is the formation of ozone (O3(g)) from oxygen...Ch. 12 - Consider the decomposition of red mercury(II)...Ch. 12 - Among other things, an ideal fuel for the control...Ch. 12 - Calculate G for each of the following reactions...Ch. 12 - Calculate G for each of the following reactions...Ch. 12 - Calculate the equilibrium constant at 25 C for...Ch. 12 - Determine G for the following reactions. (a)...Ch. 12 - Given that the Gf for Pb2+(aq) and Cl-(aq) is...Ch. 12 - Determine the standard free energy change, Gf, for...Ch. 12 - Determine the standard enthalpy change, entropy...Ch. 12 - The evaporation of one mole of water at 298 K has...Ch. 12 - In glycolysis, the reaction of glucose (Glu) to...Ch. 12 - One of the important reactions in the biochemical...Ch. 12 - Without doing a numerical calculation, determine...Ch. 12 - When ammonium chloride is added to water and...Ch. 12 - An important source of copper is from the copper...Ch. 12 - What happens to G (becomes more negative or more...
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