To find: The radius of the drainpipe when the water in it is 18 cm deep and the width of the surface of water is 48 cm.

Answer to Problem 32CR
The radius of the drainpipe is 25 cm.
Explanation of Solution
Given Information:
Depth of the water = 18 cm
Width of the surface of water = 48 cm
Formula used:
By Pythagoras theorem,
Hypotenuse2=Base2+Altitude2
Calculation:
Let x be the radius of the pipe.
Draw radius OP and then draw a line ⊥ the surface of the water and extend it to meet the
We know that, a perpendicular from the centre of a circle to the chord bisect it.
So, PR=482=24 cm
Now, OR⊥PR
Here, ΔORP forms a right triangle with ∠ORP=90o
By Pythagoras theorem,
Hypotenuse2=Base2+Altitude2
∴OP2=PR2+OR2∴x2=242+(x−18)2∴x2=576+x2−36x+324∴36x=900∴x=25 cm
Hence, radius of the pipe is 25 cm.
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