Chemistry: An Atoms First Approach
2nd Edition
ISBN: 9781305079243
Author: Steven S. Zumdahl, Susan A. Zumdahl
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Textbook Question
Chapter 12, Problem 27E
At a particular temperature, a 3.0-L flask contains 2.4 moles of Cl2, l.0 mole of NOCI, and 4.5 × 10−3 mole of NO. Calculate K at this temperature for the following reaction:
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionChapter 12 Solutions
Chemistry: An Atoms First Approach
Ch. 12 - Characterize a system at chemical equilibrium with...Ch. 12 - What is the law of mass action? Is it true that...Ch. 12 - Prob. 3RQCh. 12 - Prob. 4RQCh. 12 - Prob. 5RQCh. 12 - Distinguish between the terms equilibrium constant...Ch. 12 - Summarize the steps for solving equilibrium...Ch. 12 - Prob. 8RQCh. 12 - What is Le Chteliers principle? Consider the...Ch. 12 - Prob. 10RQ
Ch. 12 - Consider an equilibrium mixture of four chemicals...Ch. 12 - The boxes shown below represent a set of initial...Ch. 12 - For the reactionH2(g)+I2(g)2HI(g), consider two...Ch. 12 - Prob. 4ALQCh. 12 - Consider the reaction A(g)+2B(g)C(g)+D(g) in a...Ch. 12 - Consider the reactionA(g)+B(g)C(g)+D(g). A friend...Ch. 12 - Prob. 7ALQCh. 12 - Prob. 8ALQCh. 12 - Prob. 9ALQCh. 12 - Prob. 10QCh. 12 - Consider the following reaction:...Ch. 12 - Prob. 12QCh. 12 - Suppose a reaction has the equilibrium constant K...Ch. 12 - Prob. 14QCh. 12 - Consider the following reaction at some...Ch. 12 - Prob. 16QCh. 12 - Prob. 17QCh. 12 - Prob. 18QCh. 12 - For a typical equilibrium problem, the value of K...Ch. 12 - Prob. 20QCh. 12 - Write the equilibrium expression (K) for each of...Ch. 12 - Write the equilibrium expression (Kp) for each...Ch. 12 - Prob. 23ECh. 12 - For the reaction H2(g)+Br2(g)2HBr(g) Kp = 3.5 104...Ch. 12 - Prob. 25ECh. 12 - At high temperatures, elemental nitrogen and...Ch. 12 - At a particular temperature, a 3.0-L flask...Ch. 12 - At a particular temperature a 2.00-L flask at...Ch. 12 - Prob. 29ECh. 12 - Prob. 30ECh. 12 - Prob. 31ECh. 12 - Prob. 32ECh. 12 - Prob. 33ECh. 12 - Write expressions for Kp for the following...Ch. 12 - Prob. 35ECh. 12 - Prob. 36ECh. 12 - Prob. 37ECh. 12 - In a study of the reaction...Ch. 12 - The equilibrium constant is 0.0900 at 25C for the...Ch. 12 - The equilibrium constant is 0.0900 at 25C for the...Ch. 12 - At 900c, Kp = 1.04 for the reaction...Ch. 12 - Ethyl acetate is synthesized in a nonreacting...Ch. 12 - For the reaction 2H2O(g)2H2(g)+O2(g) K = 2.4 103...Ch. 12 - The reaction 2NO(g)+Br2(g)2NOBr(g) has Kp = 109 at...Ch. 12 - A 1.00-L flask was filled with 2.00 moles of...Ch. 12 - Prob. 46ECh. 12 - Prob. 47ECh. 12 - Prob. 48ECh. 12 - Prob. 49ECh. 12 - Nitrogen gas (N2) reacts with hydrogen gas (H2) to...Ch. 12 - Prob. 51ECh. 12 - Prob. 52ECh. 12 - Prob. 53ECh. 12 - At 25c, K = 0.090 for the reaction...Ch. 12 - Prob. 55ECh. 12 - Prob. 56ECh. 12 - Prob. 57ECh. 12 - At o particular temperature, K = 4 .0 107 for the...Ch. 12 - Prob. 59ECh. 12 - Lexan is a plastic used to make compact discs,...Ch. 12 - At 25C, Kp. = 2.9 103 for the reaction...Ch. 12 - A sample of solid ammonium chloride was placed in...Ch. 12 - Prob. 63ECh. 12 - Predict the shift in the equilibrium position that...Ch. 12 - An important reaction in the commercial production...Ch. 12 - What will happen to the number of moles of SO3 in...Ch. 12 - Prob. 67ECh. 12 - Hydrogen for use in ammonia production is produced...Ch. 12 - Old-fashioned smelling salts consist of ammonium...Ch. 12 - Ammonia is produced by the Haber process, in which...Ch. 12 - Prob. 71AECh. 12 - Given the following equilibrium constants at...Ch. 12 - Consider the decomposition of the compound C5H6O3...Ch. 12 - Prob. 74AECh. 12 - The gas arsine, AsH3, decomposes as follows:...Ch. 12 - At a certain temperature, K = 9.1 10-4 for the...Ch. 12 - At a certain temperature, K = 1.1 l03 for the...Ch. 12 - Prob. 78AECh. 12 - At 25C, gaseous SO2Cl2 decomposes to SO2(g) and...Ch. 12 - For the following reaction at a certain...Ch. 12 - Prob. 81AECh. 12 - Consider the reaction Fe3+(aq)+SCN(aq)FeSCN2+(aq)...Ch. 12 - Chromium(VI) forms two different oxyanions, the...Ch. 12 - Prob. 84AECh. 12 - Prob. 85AECh. 12 - For the reaction below, Kp = 1.16 at 800C....Ch. 12 - Many sugars undergo a process called mutarotation,...Ch. 12 - Peptide decomposition is one of the key processes...Ch. 12 - The creation of shells by mollusk species is a...Ch. 12 - Methanol, a common laboratory solvent, poses a...Ch. 12 - Prob. 91CWPCh. 12 - Prob. 92CWPCh. 12 - Prob. 93CWPCh. 12 - Prob. 94CWPCh. 12 - Prob. 95CWPCh. 12 - Prob. 96CWPCh. 12 - Consider the following exothermic reaction at...Ch. 12 - For the following endothermic reaction at...Ch. 12 - Prob. 99CPCh. 12 - A 4.72-g sample of methanol (CH3OH) was placed in...Ch. 12 - At 35C, K = 1.6 105 for the reaction...Ch. 12 - Nitric oxide and bromine at initial partial...Ch. 12 - At 25C. Kp = 5.3 105 for the reaction...Ch. 12 - Prob. 104CPCh. 12 - The partial pressures of an equilibrium mixture of...Ch. 12 - At 125C, KP = 0.25 for the reaction...Ch. 12 - A mixture of N2, H2, and NH3 is at equilibrium...Ch. 12 - Prob. 108CPCh. 12 - Prob. 109CPCh. 12 - Prob. 110CPCh. 12 - Prob. 111CPCh. 12 - A sample of N2O4(g) is placed in an empty cylinder...Ch. 12 - A sample of gaseous nitrosyl bromide (NOBr) was...Ch. 12 - Prob. 114CPCh. 12 - For the reaction NH3(g)+H2S(g)NH4HS(s) K = 400. at...Ch. 12 - Prob. 116IPCh. 12 - In a solution with carbon tetrachloride as the...Ch. 12 - Prob. 118IPCh. 12 - A gaseous material XY(g) dissociates to some...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Consider the system 4NH3(g)+3O2(g)2N2(g)+6H2O(l)H=1530.4kJ (a) How will the concentration of ammonia at equilibrium be affected by (1) removing O2(g)? (2) adding N2(g)? (3) adding water? (4) expanding the container? (5) increasing the temperature? (b) Which of the above factors will increase the value of K? Which will decrease it?arrow_forwardConsider 0.200 mol phosphorus pentachloride sealed in a 2.0-L container at 620 K. The equilibrium constant, Kc, is 0.60 for PCl5(g) PCl3(g) + Cl2(g) Calculate the concentrations of all species after equilibrium has been reached.arrow_forwardWrite equilibrium constant expressions for the following reactions. For gases, use either pressures or concentrations. (a) 2 H2O2(g) 2 H2O(g) + O2(g) (b) CO(g) + O2g CO2(g) (c) C(s) + CO2(g) 2 CO(g) (d) NiO(s) + CO(g) Ni(s) + CO2(g)arrow_forward
- Write an equation for an equilibrium system that would lead to the following expressions (ac) for K. (a) K=(Pco)2 (PH2)5(PC2H6)(PH2O)2 (b) K=(PNH3)4 (PO2)5(PNO)4 (PH2O)6 (c) K=[ ClO3 ]2 [ Mn2+ ]2(Pcl2)[ MNO4 ]2 [ H+ ]4 ; liquid water is a productarrow_forwardLexan is a plastic used to make compact discs, eyeglass lenses, and bullet-proof glass. One of the compounds used to make Lexan is phosgene (COCl2), an extremely poisonous gas. Phosgene decomposes by the reaction COCl2(g)CO(g)+Cl2(g) for which Kp 6.8 109 at 100C. If pure phosgene at an initial pressure of 1.0 atm decomposes, calculate the equilibrium pressures of all species.arrow_forwardMethanol, a common laboratory solvent, poses a threat of blindness or death if consumed in sufficient amounts. Once in the body, the substance is oxidized to produce formaldehyde (embalming fluid) and eventually formic acid. Both of these substances are also toxic in varying levels. The equilibrium between methanol and formaldehyde can be described as follows: CH3OH(aq)H2CO(aq)+H2(aq) Assuming the value of K for this reaction is 3.7 1010, what are the equilibrium concentrations of each species if you start with a 1.24 M solution of methanol? What will happen to the concentration of methanol as the formaldehyde is further converted to formic acid?arrow_forward
- For the reactionH2(g)+I2(g)2HI(g), consider two possibilities: (a) you mix 0.5 mole of each reactant. allow the system to come to equilibrium, and then add another mole of H2 and allow the system to reach equilibrium again. or (b) you mix 1.5 moles of H2 and 0.5 mole of I2 and allow the system to reach equilibrium. Will the final equilibrium mixture be different for the two procedures? Explain.arrow_forwardAt room temperature, the equilibrium constant Kc for the reaction 2 NO(g) ⇌ N2(g) + O2(g) is 1.4 × 1030. Is this reaction product-favored or reactant-favored? Explain your answer. In the atmosphere at room temperature the concentration of N2 is 0.33 mol/L, and the concentration of O2 is about 25% of that value. Calculate the equilibrium concentration of NO in the atmosphere produced by the reaction of N2 and O2. How does this affect your answer to Question 11?arrow_forwardThe decomposition of PCl5(g) to form PCl3(g) and Cl2(g) has Kc = 33.3 at a high temperature. If the initial concentration of PCl5 is 0.1000 M, what are the equilibrium concentrations of the reactants and products?arrow_forward
- Suppose a reaction has the equilibrium constant K = 1.3 108. What does the magnitude of this constant tell you about the relative concentrations of products and reactants that will be present once equilibrium is reached? Is this reaction likely to be a good source of the products?arrow_forwardBecause calcium carbonate is a sink for CO32- in a lake, the student in Exercise 12.39 decides to go a step further and examine the equilibrium between carbonate ion and CaCOj. The reaction is Ca2+(aq) + COj2_(aq) ** CaCO,(s) The equilibrium constant for this reaction is 2.1 X 10*. If the initial calcium ion concentration is 0.02 AI and the carbonate concentration is 0.03 AI, what are the equilibrium concentrations of the ions? A student is simulating the carbonic acid—hydrogen carbonate equilibrium in a lake: H2COj(aq) H+(aq) + HCO}‘(aq) K = 4.4 X 10"7 She starts with 0.1000 AI carbonic acid. What are the concentrations of all species at equilibrium?arrow_forwardKc = 5.6 1012 at 500 K for the dissociation of iodine molecules to iodine atoms. I2(g) 2 I(g) A mixture has [I2] = 0.020 mol/Land [I] = 2.0 108 mol/L. Is the reaction at equilibrium (at 500 K)? If not, which way must the reaction proceed to reach equilibrium?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
- Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningIntroductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Introductory Chemistry: A Foundation
Chemistry
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Chemical Equilibria and Reaction Quotients; Author: Professor Dave Explains;https://www.youtube.com/watch?v=1GiZzCzmO5Q;License: Standard YouTube License, CC-BY