Concept explainers
(a)
Interpretation: The number of rings and number of pi bonds in A is to be determined. And one possible structure is to be drawn.
Concept introduction: Degree of unsaturation is used to determine the total number of rings and pi bonds present in compound by just looking at the molecular formula. It does not specify the total number of rings and total number of pi bonds individually.
Answer to Problem 12.35P
The number of pi bonds and number of rings in A is one. The possible structure is given in Figure 1.
Explanation of Solution
For compound A:
Before hydrogenation, the molecular formula is
The maximum number of
The maximum number of
The number of
Substitute the values of maximum number of
The degree of unsaturation is calculated by the formula,
Hence, the degree of unsaturation before hydrogenation is two.
After hydrogenation, the molecular formula is
The maximum number of
The maximum number of
The number
Substitute the values of maximum number of
The degree of unsaturation is calculated by the formula,
Hence, the degree of unsaturation after hydrogenation is one.
The number of pi bonds in A is calculated by the formula,
Substitute the values of degree of unsaturation before hydrogenation and degree of unsaturation after hydrogenation in the above formula.
Hence, the number of pi bonds is one.
Number of rings is calculated by the formula,
Substitute the values of degree of unsaturation and number of pi bonds in the above formula.
Hence, the number of rings is one.
The possible structure for A is,
Figure 1
The number of pi bonds and number of rings in A is one. The possible structure is given in Figure 1.
(b)
Interpretation: The number of rings and number of pi bonds in B is to be determined. And one possible structure is to be drawn.
Concept introduction: Degree of unsaturation is used to determine the total number of rings and pi bonds present in compound by just looking at the molecular formula. It does not specify the total number of rings and total number of pi bonds individually.
Answer to Problem 12.35P
The number of pi bonds and number of rings in B is one and two respectively. The possible structure is given in Figure 2.
Explanation of Solution
For compound B:
Before hydrogenation, the molecular formula is
The maximum number of
The maximum number of
The number of
Substitute the values of maximum number of
The degree of unsaturation is calculated by the formula,
Hence, the degree of unsaturation before hydrogenation is three.
After hydrogenation, the molecular formula is
The maximum number of
The maximum number of
The number
Substitute the values of maximum number of
The degree of unsaturation is calculated by the formula,
Hence, the degree of unsaturation after hydrogenation is two.
The number of pi bonds in A is calculated by the formula,
Substitute the values of degree of unsaturation before hydrogenation and degree of unsaturation after hydrogenation in the above formula.
Hence, the number of pi bonds is one.
Number of rings is calculated by the formula,
Substitute the values of degree of unsaturation and number of pi bonds in the above formula.
Hence, the number of rings is two.
The possible structure for B is,
Figure 2
The number of pi bonds and number of rings in B is one and two respectively. The possible structure is given in Figure 2.
(c)
Interpretation: The number of rings and number of pi bonds in B is to be determined. And one possible structure is to be drawn.
Concept introduction: Degree of unsaturation is used to determine the total number of rings and pi bonds present in compound by just looking at the molecular formula. It does not specify the total number of rings and total number of pi bonds individually.
Answer to Problem 12.35P
The number of pi bonds and number of rings in C is four and one respectively. The possible structure is given in Figure 3.
Explanation of Solution
For compound C:
Before hydrogenation, the molecular formula is
The maximum number of
The maximum number of
The number of
Substitute the values of maximum number of
The degree of unsaturation is calculated by the formula,
Hence, the degree of unsaturation before hydrogenation is five.
After hydrogenation, the molecular formula is
The maximum number of
The maximum number of
The number
Substitute the values of maximum number of
The degree of unsaturation is calculated by the formula,
Hence, the degree of unsaturation after hydrogenation is one.
The number of pi bonds in A is calculated by the formula,
Substitute the values of degree of unsaturation before hydrogenation and degree of unsaturation after hydrogenation in the above formula.
Hence, the number of pi bonds is four.
Number of rings is calculated by the formula,
Substitute the values of degree of unsaturation and number of pi bonds in the above formula.
Hence, the number of rings is one.
The possible structure for C is,
Figure 3
The number of pi bonds and number of rings in C is four and one respectively. The possible structure is given in Figure 3.
Want to see more full solutions like this?
Chapter 12 Solutions
Organic Chemistry
- (12) Which one of the following statements about fluo- rometry is FALSE? a) Fluorescence is better detected at 90 from the exci- tation direction. b) Fluorescence is typically shifted to longer wave- length from the excitation wavelength. c) For most fluorescent compounds, radiation is pro- duced by a transitionarrow_forwardDon't used Ai solutionarrow_forwardDon't used Ai solutionarrow_forward
- Don't used Ai solutionarrow_forwardIndicate the correct option.a) Graphite conducts electricity, being an isotropic materialb) Graphite is not a conductor of electricityc) Both are falsearrow_forward(f) SO: Best Lewis Structure 3 e group geometry:_ shape/molecular geometry:, (g) CF2CF2 Best Lewis Structure polarity: e group arrangement:_ shape/molecular geometry: (h) (NH4)2SO4 Best Lewis Structure polarity: e group arrangement: shape/molecular geometry: polarity: Sketch (with angles): Sketch (with angles): Sketch (with angles):arrow_forward
- 1. Problem Set 3b Chem 141 For each of the following compounds draw the BEST Lewis Structure then sketch the molecule (showing bond angles). Identify (i) electron group geometry (ii) shape around EACH central atom (iii) whether the molecule is polar or non-polar (iv) (a) SeF4 Best Lewis Structure e group arrangement:_ shape/molecular geometry: polarity: (b) AsOBr3 Best Lewis Structure e group arrangement:_ shape/molecular geometry: polarity: Sketch (with angles): Sketch (with angles):arrow_forward(c) SOCI Best Lewis Structure 2 e group arrangement: shape/molecular geometry:_ (d) PCls Best Lewis Structure polarity: e group geometry:_ shape/molecular geometry:_ (e) Ba(BrO2): Best Lewis Structure polarity: e group arrangement: shape/molecular geometry: polarity: Sketch (with angles): Sketch (with angles): Sketch (with angles):arrow_forwardDon't used Ai solutionarrow_forward